在java中尝试查找数组中字符串的索引
我试图找到数组中最长字符串的索引,它由字符串longString表示。我一直收到一个“找不到符号”错误,不知道如何修复它在java中尝试查找数组中字符串的索引,java,arrays,string,indexof,Java,Arrays,String,Indexof,我试图找到数组中最长字符串的索引,它由字符串longString表示。我一直收到一个“找不到符号”错误,不知道如何修复它 public class Final21 { public static String getLongString(String[] array) { int x=0; int maxLength = 0; String longString = null; for (String
public class Final21 {
public static String getLongString(String[] array) {
int x=0;
int maxLength = 0;
String longString = null;
for (String s : array) {
if (s.length() > maxLength) {
maxLength = s.length();
longString = s;
}
}
return longString;
}
public static String getShortString(String[] array) {
int minLength = 0;
String shortString = null;
for (String t : array) {
if (t.length() > minLength) {
minLength = t.length();
shortString = t;
}
}
return shortString;
}
public static void main(String[] args) {
String[] names = {"bob", "maxwell", "charley", "tomtomjack"};
String longString = getLongString(names);
System.out.println("The Longest String is: " + longString + " With The Index Of" + names.indexOf(longString));
String shortString = getShortString(names);
System.out.println("The Longest String is: " + shortString + " With The Index Of" );
}
}
问题在于
names.indexOf(longString)
。因为names
属于String[]
类型,它是一个数组。此类型String[]
没有名为indexOf
的方法定义。你也可以试试
所以,为了纠正代码剪贴,您可以像这样重写它
System.out.println("The Longest String is: " + longString + " With The Index Of" + java.util.Arrays.asList(names).indexOf(longString));
阅读的JavaDoc,学习如何使用javaapi在java中处理数组
此外,可以通过修改代码的语义来实现同样的效果。我是为你做的。也请阅读这篇文章。数组中没有
indexOf
函数,而不是您当前的方法-我将从getLongString
和getShortString
方法返回索引
;首先假设它是第一个元素。如果任何元素更长(或更短),则更新返回值。像
public static int getLongString(String[] array) {
int max = 0;
for (int i = 1; i < array.length; i++) {
if (array[i].length() > array[max].length()) {
max = i;
}
}
return max;
}
public static int getShortString(String[] array) {
int min = 0;
for (int i = 1; i < array.length; i++) {
if (array[i].length() < array[min].length()) {
min = i;
}
}
return min;
}
哪个输出
The Longest String is: tomtomjack With The Index Of 3
The Longest String is: bob With The Index Of 0
indexOf()的语法为:
公共int索引of(char-ch)
它返回指定字符第一次出现时该字符串内的索引,如果该字符没有出现,则返回-1
以获得所需的输出
您可以尝试使用以下命令更改代码:
public static String getLongString(String[] array) {
int x=0, maxLength = 0, index = 0;
String longString = null;
for (String s : array) {
if (s.length() > maxLength)
{
maxLength = s.length();
index++;
longString = s;
}
}
return "The Longest String is: "+ longString + " With The Index Of :" + index;
}
public static void main(String[] args) {
String[] names = {"bob", "maxwell", "charley", "tomtomjack"};
String longString = getLongString(names);
System.out.println(longString);
}
您得到的
找不到符号
错误的行号是多少?请尝试具体说明您得到错误的点。您可以这样做,只需在这里发布编译器输出。如果你这样做,你的问题和答案也会更有成效……)@罗密欧塞拉哦,是的,对不起。。。是在names.indexOf。我是新来的,我尝试了@Romeo Sierra的解决方案,似乎效果不错。虽然您的解决方案也可以工作,但它需要更多的代码行。
public static String getLongString(String[] array) {
int x=0, maxLength = 0, index = 0;
String longString = null;
for (String s : array) {
if (s.length() > maxLength)
{
maxLength = s.length();
index++;
longString = s;
}
}
return "The Longest String is: "+ longString + " With The Index Of :" + index;
}
public static void main(String[] args) {
String[] names = {"bob", "maxwell", "charley", "tomtomjack"};
String longString = getLongString(names);
System.out.println(longString);
}