Java 有没有办法防止Apache CloseableHttpClient抛出HttpResponseException?
我正在使用ApacheHttpComponents(4.5.11)测试web API 对于否定测试(例如,发送错误的请求),我还想检查响应主体,但Java 有没有办法防止Apache CloseableHttpClient抛出HttpResponseException?,java,apache-httpclient-4.x,apache-httpcomponents,web-api-testing,Java,Apache Httpclient 4.x,Apache Httpcomponents,Web Api Testing,我正在使用ApacheHttpComponents(4.5.11)测试web API 对于否定测试(例如,发送错误的请求),我还想检查响应主体,但CloseableHttpClient使用响应的状态代码抛出HttpResponseException,而不是返回实际响应。 有没有办法防止这种情况发生,或者我应该切换到另一个库(例如重新发行) 我是这样做的: try (CloseableHttpClient httpClient = HttpClients.createDefault();
CloseableHttpClient
使用响应的状态代码抛出HttpResponseException
,而不是返回实际响应。
有没有办法防止这种情况发生,或者我应该切换到另一个库(例如重新发行)
我是这样做的:
try (CloseableHttpClient httpClient = HttpClients.createDefault();
CloseableHttpResponse response = httpClient.execute(request)) {
ResponseHandler<String> handler = new BasicResponseHandler();
String body = handler.handleResponse(response);
//Deserialize and perform response assertions..
} catch(HttpResponseException e){
//Exception is caught here..
}
try(CloseableHttpClient-httpClient=HttpClients.createDefault();
CloseableHttpResponse response=httpClient.execute(请求)){
ResponseHandler=new BasicResponseHandler();
字符串体=handler.handleResponse(响应);
//反序列化并执行响应断言。。
}捕获(HttpResponseException e){
//这里有个例外。。
}
pom.xml依赖项:
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.11</version>
</dependency>
org.apache.httpcomponents
httpclient
4.5.11
我不太明白这个问题。没有什么可以阻止您直接从响应对象获取状态代码和读取响应内容
try (CloseableHttpClient httpClient = HttpClients.createDefault();
CloseableHttpResponse response = httpClient.execute(request)) {
int statusCode = response.getStatusLine().getStatusCode();
final HttpEntity entity = response.getEntity();
if (entity != null) {
try (InputStream inputStream = entity.getContent()) {
// Do something useful with the response
}
}
}
handler.HandlerResponse(响应);此语句是引发异常的语句。我把它取下来,自己处理回复。谢谢你的帮助@ok2c