Java 错误，方法无法应用于给定类型

该代码应询问事故数量，确定五个地区中事故数量最少的地区，并打印事故数量和地区。我对java相当陌生，我遇到了这个错误。它说第四堂课家庭作业中的getNumAcidents方法不能应用于给定的类型；必需：双重查找：无参数原因：实际列表和正式列表长度不同。如何解决此问题

import java.util.*;
public class fourthHomework
{
public static void main(String args[]) {
double smallest = 0;
double north = getNumAccidents();
double south = getNumAccidents();
double east = getNumAccidents();
double west = getNumAccidents();
double central = getNumAccidents();

getNumAccidents(smallest);
findLowest(north, south, east, west, central, smallest);


}
public static double getNumAccidents(double smallest) {
System.out.println("Please enter all accidents as positive numbers.");
Scanner input = new Scanner(System.in);
System.out.print("Please enter the amount of accidents: ");
smallest = input.nextDouble();
}

public static void findLowest(double north, double south, double east, double west, double central, double smallest) {
System.out.println("The lowest amount of accidents this year was " +smallest);
if (north == smallest)
{
    System.out.println("The region that had the least amount of accidents was the north.");
}

if (south == smallest)
{
    System.out.println("The region that had the least amount of accidents was the south.");
}

if (east == smallest)
{
    System.out.println("The region that had the least amount of accidents was the east.");
}

if (west == smallest)
{
    System.out.println("The region that had the least amount of accidents was the west.");
}

if (central == smallest)
{
    System.out.println("The region that had the least amount of accidents was the central region.");
}

}

---

}

您的问题是因为在方法GetNumAcidents（最小双精度）中需要双精度作为参数。在声明double-north、south、east、west和central时，不为方法添加任何参数。您需要添加双倍，否则它将运行。另外，因为您说过该方法将返回一个double，所以您需要在该方法的末尾说

return smallest

---

让主要方法的开头显示：

public static void main(String args[]) {
    double smallest = 0.0;
    double north = getNumAccidents(smallest);
    double south = getNumAccidents(smallest);
    double east = getNumAccidents(smallest);
    double west = getNumAccidents(smallest);
    double central = getNumAccidents(smallest);
...

在

getNumAcidents

方法中，由于它被声明为double，因此需要返回一个double值：

...
smallest = input.nextDouble();
return smallest;
}

---

这不会完全修复程序，但它会帮助您在执行过程中解决问题。

方法

getnumacidents

需要一个参数。执行

double south=getNumAccidentd（）

时，应该向它传递一个值，其他方向也是如此。另外，您似乎忘记了让该方法返回一个值。这里有很多问题，谢谢！当我运行它时，不管我输入了什么，它都会说最小的事故量是0。您对此有什么建议吗？@carrollsoccer5您可以查看main方法，其中显示getnumacidents（最小值）；把它分配给最小的变量而不是等于零？@carrollsoccer5分配给最小的变量是这样的：

minimate=getnumacidents（minimate）而不是
getnumacidents（最小）。。。然后，当您运行程序时，无论您输入什么，您都不会将0视为最小的事故数（除非它是一个输入数）。您仍然需要修复
getNumAcidents
方法以请求5个区域输入（而不是6个），并将正确的最低值分配给最小值（变量名）。如何使其不请求6个？抱歉问了这么多问题，你帮了大忙。