通过java进行xslt转换时出现异常

正如您所看到的，我现在在下面的java类中使用xstream rite 在下面的java类中，我从对象生成xml

InvoiceReferenceNotificationMessage invoiceReferenceNotificationMessage = new InvoiceReferenceNotificationMessage();
        invoiceReferenceNotificationMessage.setInvoiceReference("SM/829709/0315");
        invoiceReferenceNotificationMessage.setABSReference("IRMAR157311");
        invoiceReferenceNotificationMessage.setCurrency("GBP");
        invoiceReferenceNotificationMessage.setInvoiceAmount(2546);
        invoiceReferenceNotificationMessage.setPaidAmount(1245);
        invoiceReferenceNotificationMessage.setBalanceAmount(0);
        invoiceReferenceNotificationMessage.setValueDate(new Date());
        invoiceReferenceNotificationMessage.setRemarks("abc");


        InvoiceReferenceNotificationMessage invoiceReferenceNotificationMessage1 = new InvoiceReferenceNotificationMessage();
        invoiceReferenceNotificationMessage1.setInvoiceReference("SM/15");
        invoiceReferenceNotificationMessage1.setABSReference("I157311");
        invoiceReferenceNotificationMessage1.setCurrency("EUR");
        invoiceReferenceNotificationMessage1.setInvoiceAmount(255546);
        invoiceReferenceNotificationMessage1.setPaidAmount(125545);
        invoiceReferenceNotificationMessage1.setBalanceAmount(0);
        invoiceReferenceNotificationMessage1.setValueDate(new Date());
        invoiceReferenceNotificationMessage1.setRemarks("abERRc");


        Mail m = new Mail();
        String xslFilePath1 = "C:\\xsl\\rok.xsl";

        m.setInvoiceReferenceNotificationMessage(invoiceReferenceNotificationMessage);
        XStream xstream = new XStream();
        xstream.alias("arokermail",Mail.class);
        String abc = xstream.toXML(m);


        m.setInvoiceReferenceNotificationMessage(invoiceReferenceNotificationMessage1);
        xstream.alias("arokermail",Mail.class);
        String def = xstream.toXML(m);

        String t =abc+def;

因此，上面的代码生成以下xml

        <arokermail>
  <invoiceReferenceNotificationMessage>
    <InvoiceReference>SM/829709/0315</InvoiceReference>
    <ABSReference>IRMAR157311</ABSReference>
    <Currency>GBP</Currency>
    <InvoiceAmount>2546.0</InvoiceAmount>
    <PaidAmount>1245.0</PaidAmount>
    <BalanceAmount>0.0</BalanceAmount>
    <ValueDate>2015-05-22 15:44:14.741 IST</ValueDate>
    <Remarks>abc</Remarks>
  </invoiceReferenceNotificationMessage>
</arokermail><arokermail>
  <invoiceReferenceNotificationMessage>
    <InvoiceReference>SM/15</InvoiceReference>
    <ABSReference>I157311</ABSReference>
    <Currency>EUR</Currency>
    <InvoiceAmount>255546.0</InvoiceAmount>
    <PaidAmount>125545.0</PaidAmount>
    <BalanceAmount>0.0</BalanceAmount>
    <ValueDate>2015-05-22 15:44:14.741 IST</ValueDate>
    <Remarks>abERRc</Remarks>
  </invoiceReferenceNotificationMessage>
</arokermail>

现在请建议如何在生成的xml上应用此xsl生成的xml存储在名为t的字符串变量中

String t =abc+def;

下面是我通过调用函数和传递参数所做的尝试

String t =abc+def; //generated xml
    String xslFilePath1 = "C:\\xsl\\rok.xsl";";
    String outputhtml =null;

    try
        {
            st.transform(t, xslFilePath1, outputhtml);
            }
    catch (TransformerConfigurationException e)
                {
                    System.err.println("TransformerConfigurationException");
                    System.err.println(e);
                }
                catch (TransformerException e)
                {
                    System.err.println("TransformerException");
                    System.err.println(e);
                }

正在调用的函数如下所示

public void transform(String dataXML, String inputXSL, String outputHTML)
                throws TransformerConfigurationException, TransformerException

        {
         TransformerFactory factory = TransformerFactory.newInstance();
            StreamSource xslStream = new StreamSource(inputXSL);
            Transformer transformer = factory.newTransformer(xslStream);
           StreamSource in = new StreamSource(dataXML);
            StreamResult out = new StreamResult(outputHTML);
            transformer.transform(in, out);
            System.out.println("The generated HTML file is:" + outputHTML);

        }






the error that i am getting is ..




    TransformerException
    javax.xml.transform.TransformerException: Result object passed to ''{0}'' is invalid.

我已经更新了xsl，所以我的rok.xsl如下所示

String xslFilePath1 = "C:\\xsl\\rok.xsl";

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

    <xsl:template match="/">
        <html>
            <body>
                Hello,
                <br>
                </br>
                <br>
                </br>
                Please be advised of the following payment details
                    <font color="black" face="Arial" size="2" >
                    <br>
                        <br>

                            <table border="1" cellpadding="3" cellspacing="0">
                                <tr bgcolor="lightblue">
                                     <td nowrap="nowrap">Invoice Reference</td>
                                     <td nowrap="nowrap">ABSReference</td>
                                     <td nowrap="nowrap">Currency</td>
                                     <td nowrap="nowrap">Invoice Amount</td>
                                     <td nowrap="nowrap">Paid Amount</td>
                                     <td nowrap="nowrap">Balance Amount</td>
                                     <td nowrap="nowrap">Value Date</td>
                                     <td nowrap="nowrap">Remarks</td>

                                </tr>
                                <xsl:for-each select="arokermail/invoiceReferenceNotificationMessage">
                                    <tr>
                                        <td nowrap="nowrap"><xsl:value-of select="InvoiceReference" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="ABSReference" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="Currency" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="InvoiceAmount" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="PaidAmount" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="BalanceAmount" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="ValueDate" /></td>
                                        <td nowrap="nowrap"><xsl:value-of select="Remarks" /></td>
                                        </tr>
                                </xsl:for-each>
                                <TR>

                                </TR>
                            </table>
                        </br>
                    </br>
                    <p>

-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
</br>
</br>                                   
</p>
                </font>
            </body>
        </html>
    </xsl:template>
</xsl:stylesheet>

你好








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由

String t =abc+def; //generated xml

---

它的格式不好。特别是，您通过连接两个现有XML文档创建了一个文档，因此它没有一个根节点。我不太清楚您想要实现什么（可能是转换每个XML文档，然后连接），但是您将两个文档连接起来肯定是无效的。

问题在于

StreamResult

的构造函数中，您正在传递

null

。这就是它所期望的

public StreamResult(String systemId) 
Construct a StreamResult from a URL.
Parameters:
    systemId - Must be a String that conforms to the URI syntax.

您应该使用另一个构造函数。如果您的xml和xsl是正确的（并且t包含您的xml），那么这应该是可行的。请注意，

StringBufferInputStream

已被弃用，但它是一个快速而肮脏的解决方案）：

---

你能不能先说明一下请帮我更正一下xml，因为它缺少的东西每一半生成的xml看起来格式都很好，但如果将两个文档加在一起，就会得到一些非xml的东西，因为它没有一个顶级节点。谢谢，那么，请告诉我如何组合并生成完整的xml。在这种情况下，您需要查看XSL并设计XSL期望的文档。我的第一个问题是，XSL希望文档的根节点是什么。这将给你一个关于如何使用itI的线索我已经更新了my arok.xsl，请你查看更新的帖子谢谢Vancethanks，请您在上面的代码中进行更改，以便我能提前了解更多感谢您能突出显示引发该异常的特定行吗？TransformerException javax.xml.transform.TransformerException:传递给{0}的结果对象无效。这是我能看到的唯一异常，您能告诉我如何通过xalan进行xsl转换吗？还有其他方法吗way@BrianAgnew是否可以使用任何其他可能的方法进行xsl转换请建议您需要突出显示引发异常的代码中的特定行。也就是说，它在哪条线上爆炸？

TransformerFactory factory = TransformerFactory.newInstance();
     //File object with path to your xsl file
StreamSource xslStream = new StreamSource(new File("C:\\xsl\\rok.xsl"));
Transformer transformer = factory.newTransformer(xslStream);
    //Read xml from string
StreamSource in = new StreamSource(new StringBufferInputStream(t));
    //Prints to stdout
StreamResult out = new StreamResult(System.out);