Java Spring安全性和angularjs POST请求

Java Spring安全性和angularjs POST请求,java,angularjs,spring,spring-mvc,spring-security,Java,Angularjs,Spring,Spring Mvc,Spring Security,使用spring security自定义登录表单时,我从UI传递的参数在HttpServletRequest中无法访问 class StatelessLoginFilter extends AbstractAuthenticationProcessingFilter { private final TokenAuthenticationService tokenAuthenticationService; private final CustomJDBCDaoImpl user

使用spring security自定义登录表单时,我从UI传递的参数在HttpServletRequest中无法访问

class StatelessLoginFilter extends AbstractAuthenticationProcessingFilter {

    private final TokenAuthenticationService tokenAuthenticationService;
    private final CustomJDBCDaoImpl userDetailsService;

    protected StatelessLoginFilter(String urlMapping, TokenAuthenticationService tokenAuthenticationService,
            CustomJDBCDaoImpl userDetailsService, AuthenticationManager authManager) {
        super(new AntPathRequestMatcher(urlMapping));
        this.userDetailsService = userDetailsService;
        this.tokenAuthenticationService = tokenAuthenticationService;
        setAuthenticationManager(authManager);
    }

    @Override
    public Authentication attemptAuthentication(HttpServletRequest request, HttpServletResponse response)
            throws AuthenticationException, IOException, ServletException {

                final UsernamePasswordAuthenticationToken loginToken = new UsernamePasswordAuthenticationToken(
                request.getAttribute("email").toString(), request.getAttribute("password").toString());
        return getAuthenticationManager().authenticate(loginToken);
    }

    @Override
    protected void successfulAuthentication(HttpServletRequest request, HttpServletResponse response,
            FilterChain chain, Authentication authentication) throws IOException, ServletException {

        final UserDetails authenticatedUser = userDetailsService.loadUserByUsername(authentication.getName());
        final UserAuthentication userAuthentication = new UserAuthentication(authenticatedUser);

        tokenAuthenticationService.addAuthentication(response, userAuthentication);
        SecurityContextHolder.getContext().setAuthentication(userAuthentication);
    }
}
在AttemptAuthentication method中,请求未使用我使用以下代码从POST请求传递的属性:

 var request = $http.post('/verifyUser', 
       {email: 'user', password: 'user',_csrf: $cookies['XSRF-TOKEN']})
我尝试使用调试器控制台跟踪它,发现负载中填充了我转发的元素

{“电子邮件”:“用户”、“密码”:“用户”、“csrf”:“f1d88246-28a0-4e64-a988-def4cafa5004”}

我的安全配置是:

http
                .exceptionHandling().and()
                .anonymous().and()
                .servletApi().and()
                .headers().cacheControl().and()
                .authorizeRequests()

                //allow anonymous resource requests
                .antMatchers("/").permitAll()               
                //allow anonymous POSTs to login
                .antMatchers(HttpMethod.POST, "/verifyUser").permitAll()
                .and()
                  .formLogin().loginPage("/signin")
                .permitAll()
                .and()

                .addFilterBefore(new StatelessLoginFilter("/verifyUser", new TokenAuthenticationService("456abc"), new CustomJDBCDaoImpl() , authenticationManager()), UsernamePasswordAuthenticationFilter.class)


                .addFilterBefore(new StatelessAuthenticationFilter(new TokenAuthenticationService("456abc")), UsernamePasswordAuthenticationFilter.class).httpBasic()
                         .and().csrf().disable().addFilterBefore(new CSRFFilter(), CsrfFilter.class);
编辑#1

我还尝试使用getParameter(“email”)而不是getAttribute(“email”),但此时整个参数映射也是空的

编辑#2:添加请求内容

Remote Address:127.0.0.1:80
Request URL:http://localhost/api/verifyUser/
Request Method:POST
Status Code:502 Bad Gateway
Response Headers
view source
Connection:keep-alive
Content-Length:583
Content-Type:text/html
Date:Sun, 11 Oct 2015 17:23:24 GMT
Server:nginx/1.6.2 (Ubuntu)
Request Headers
view source
Accept:application/json, text/plain, */*
Accept-Encoding:gzip, deflate
Accept-Language:en-US,en;q=0.8
Connection:keep-alive
Content-Length:81
Content-Type:application/x-www-form-urlencoded
Cookie:XSRF-TOKEN=f1d88246-28a0-4e64-a988-def4cafa5004
Host:localhost
Origin:http://localhost
Referer:http://localhost/ui/
User-Agent:Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/45.0.2454.85 Safari/537.36
X-XSRF-TOKEN:f1d88246-28a0-4e64-a988-def4cafa5004
Form Data
view source
view URL encoded
{"email":"user","password":"user"}:

所需的
电子邮件
密码
数据是参数,而不是属性。ServletRequest中的属性是仅服务器端的数据,您可以在应用程序中使用它们在类之间传递数据或将数据传递给JSP

注意:您必须使用内容类型
application/x-www-form-urlencoded
,并确保请求正文的编码格式正确,以便在服务器端使用
getParameter
,例如
email=user&password=user

默认情况下,Angular将对象编码为JSON

角度变换提供以下默认变换:

请求转换($httpProvider.defaults.transformRequest和 $http.defaults.transformRequest):

如果请求配置对象的数据属性包含 对象,将其序列化为JSON格式

也看到


Hmm,请求的内容类型是什么?如果它不是像
application/x-www-form-urlencoded
这样的“表单”类型,那么您需要读取请求主体并对其进行解析。请参阅或我已在POST之前显式设置表单类型。当我检查request.getHeader(“内容类型”)时,它返回给我application/x-www-form-urlencoded。或者我仍然需要解析请求inputstream吗?您不必这样做。我没有使用过
AbstractAuthenticationProcessingFilter
,但我知道
getParameter
在过滤器和端点的这种情况下工作。您能否在服务器看到请求正文时发布其内容?可能angular做了一些奇怪的事情,服务器没有以正确的格式获取数据。啊,我想我看到了问题所在。尽管您的请求内容类型是
application/x-www-form-urlencoded
,但您的请求正文实际上是JSON格式的(最后一行)。格式应为
email=user&password=user
,类似于查询字符串。我将编辑我的答案。