Java 如果当前行包含太多文本，是否在Stringlist中创建新行？

所以我现在有我的stringlist，用户可以在其中编辑输入的内容，只要它是一个字符串。因此，对于较短的文本，这很好，但是当文本开始变得越来越长时，我使用stringlist的工具提示将占用屏幕太多的空间，使事情看起来很难看。所以我想为每一个特定数量的字符创建一个新的字符串列表，这样它就不会变得混乱。以下是我目前正在进行的测试：

'Salamander specializes in disguising in the green woods, mainly in oak forests salamanders will hide and lure to wait for your loot, they will then jump out and do a sneak attack. Be prepared!'

我通过以下方式获得该信息：

lore.add(kitConfig.getString("kits." + kitName + ".description"));

---

lore

ArrayList

中的每个

字符串都显示在新行上。您可以编写一个方法，将
字符串
拆分为段，并返回一个
数组列表
，其中包含可以设置为新知识的部分。下面是一个示例，展示了它的外观：

public static ArrayList<String> splitLore(String text, int characters) {
    ArrayList<String> lore = new ArrayList<String>(); // Create the ArrayList that will contain the lore lines
    if (text.length() <= characters) { // If the line of text is short enough (doesn't need to be split)...
        lore.add(text); // Add the entire line to the list and return it
    } else { // If the line is longer and needs to be split into at least two lines...
        int beginIndex = 0; // A "begin index" where each substring or segment will begin
        while (beginIndex <= text.length() - 1) { // If the index is not larger than the last character index in the line of text...
            lore.add(text.substring(beginIndex, Math.min(beginIndex + characters, text.length()))); // Add the segment
            beginIndex += characters;
            // This will also add any trailing segments at the end of the line that are shorter than the character limit
        }
    }
    return lore;
}

这种方法不是很“聪明”，会将单词切掉，产生看起来不太漂亮或难以阅读的文本行

为了让这些知识更容易阅读，你可以把一行文字分成“单词”，然后试着把它们分组，这样就不会有任何一行文字超过“软”字的限制。下面的示例方法不会分割单词，尽管它也不会强制分割占用超过整行的超长单词

public static ArrayList<String> splitLoreNicely(String text, int characters) {
    ArrayList<String> lore = new ArrayList<>();
    String[] words = text.split(" "); // Get the "words" in the line of text by splitting the space characters
    int wordsUsed = 0; // A counter for how many words have been placed in lines so far
    while (wordsUsed < words.length) { // Repeat this process until all words have been placed into separate lines
        String line = ""; // The line that will be added to the lore list
        for (int i = wordsUsed; i < words.length; i++) { // For each remaining word in the array
            if (line.length() + words[i].length() >= characters) { // If adding the next word exceeds or matches the character limit...
                line += words[i]; // Add the last word in the line without a space character
                wordsUsed++;
                break; // Break out of this inner loop, since we have reached/exceeded the character limit for this line
            } else { // If adding this word does not exceed or match the character limit... 
                line += words[i] + " "; // Add the word with a space character, continue for loop
                wordsUsed++;
            }
        }
        lore.add(line); // Add the line of text to the list
    }
    return lore;
}

publicstaticarraylistsplitlorenicely（字符串文本，int字符）{
ArrayList lore=新的ArrayList（）；
String[]words=text.split（“”；//通过拆分空格字符获取文本行中的“words”
int wordsUsed=0；//一个计数器，用于计算到目前为止已在行中放置了多少个单词
while（wordsUsed=个字符）{//如果添加下一个单词超过或匹配字符限制。。。
line+=单词[i]；//将最后一个单词添加到行中，不带空格字符
wordsUsed++；
break；//中断此内部循环，因为我们已达到/超过此行的字符限制
}否则{//如果添加此单词未超过或匹配字符限制。。。
line+=words[i]+“”；//添加带空格字符的单词，继续循环
wordsUsed++；
}
}
lore.add（line）；//将文本行添加到列表中
}
回归知识；
}
谢谢，我会试试的。
public static ArrayList<String> splitLoreNicely(String text, int characters) {
    ArrayList<String> lore = new ArrayList<>();
    String[] words = text.split(" "); // Get the "words" in the line of text by splitting the space characters
    int wordsUsed = 0; // A counter for how many words have been placed in lines so far
    while (wordsUsed < words.length) { // Repeat this process until all words have been placed into separate lines
        String line = ""; // The line that will be added to the lore list
        for (int i = wordsUsed; i < words.length; i++) { // For each remaining word in the array
            if (line.length() + words[i].length() >= characters) { // If adding the next word exceeds or matches the character limit...
                line += words[i]; // Add the last word in the line without a space character
                wordsUsed++;
                break; // Break out of this inner loop, since we have reached/exceeded the character limit for this line
            } else { // If adding this word does not exceed or match the character limit... 
                line += words[i] + " "; // Add the word with a space character, continue for loop
                wordsUsed++;
            }
        }
        lore.add(line); // Add the line of text to the list
    }
    return lore;
}