Java 使用Spring Data Core的PagedResourcesAssembler生成HATEOAS链接
在Spring数据JPA中,它解释了如何使用PagedResourcesAssembler生成链接。该文档引用了一个toResources方法,但据我所知,该方法并不存在。我已经成功地为资源集合生成了链接,但是我不知道如何为子资源生成链接 这是我的控制器:Java 使用Spring Data Core的PagedResourcesAssembler生成HATEOAS链接,java,spring,spring-data,spring-data-jpa,spring-hateoas,Java,Spring,Spring Data,Spring Data Jpa,Spring Hateoas,在Spring数据JPA中,它解释了如何使用PagedResourcesAssembler生成链接。该文档引用了一个toResources方法,但据我所知,该方法并不存在。我已经成功地为资源集合生成了链接,但是我不知道如何为子资源生成链接 这是我的控制器: public HttpEntity<PagedResources<Party>> search(@RequestBody PartySearchRequest request,
public HttpEntity<PagedResources<Party>> search(@RequestBody PartySearchRequest request,
Pageable pageable, PagedResourcesAssembler<Party> assembler ) {
Map<String,String> searchFilters = RequestValidator.validateContractSearchFilters(request);
Page<Party> parties = repository.findByFirstNameOrLastName(searchFilters.get("firstName"), searchFilters.get("lastName"), pageable);
return new ResponseEntity(assembler.toResource(parties), HttpStatus.OK);
}
private final MyResourceAssembler myResourceAssembler;
public MyController(MyResourceAssembler myResourceAssembler) {
this.myResourceAssembler = myResourceAssembler;
}
public HttpEntity<PagedResources<Party>> search(@RequestBody PartySearchRequest request,
Pageable pageable, PagedResourcesAssembler<Party> assembler ) {
Map<String,String> searchFilters = RequestValidator.validateContractSearchFilters(request);
Page<Party> parties = repository.findByFirstNameOrLastName(searchFilters.get("firstName"), searchFilters.get("lastName"), pageable);
Link selfLink = linkTo(methodOn(this.getClass().view(pageable, null)).withSelfRel();
return new ResponseEntity(assembler.toResource(parties, myResourceAssembler, selfLink), HttpStatus.OK);
}
如您所见,我获得了整个party搜索的链接,但没有获得单个party对象的链接。我想我的问题类似于这个问题:但我不太确定,所以我发布了我自己的问题
任何帮助都将不胜感激!谢谢大家! 您需要对扩展的类的引用 这应该是可行的,将myResourceAssembler更改为您的类: 在控制器中:
public HttpEntity<PagedResources<Party>> search(@RequestBody PartySearchRequest request,
Pageable pageable, PagedResourcesAssembler<Party> assembler ) {
Map<String,String> searchFilters = RequestValidator.validateContractSearchFilters(request);
Page<Party> parties = repository.findByFirstNameOrLastName(searchFilters.get("firstName"), searchFilters.get("lastName"), pageable);
return new ResponseEntity(assembler.toResource(parties), HttpStatus.OK);
}
private final MyResourceAssembler myResourceAssembler;
public MyController(MyResourceAssembler myResourceAssembler) {
this.myResourceAssembler = myResourceAssembler;
}
public HttpEntity<PagedResources<Party>> search(@RequestBody PartySearchRequest request,
Pageable pageable, PagedResourcesAssembler<Party> assembler ) {
Map<String,String> searchFilters = RequestValidator.validateContractSearchFilters(request);
Page<Party> parties = repository.findByFirstNameOrLastName(searchFilters.get("firstName"), searchFilters.get("lastName"), pageable);
Link selfLink = linkTo(methodOn(this.getClass().view(pageable, null)).withSelfRel();
return new ResponseEntity(assembler.toResource(parties, myResourceAssembler, selfLink), HttpStatus.OK);
}
工具书类
非常感谢。我创建了PartyResourcesAssembler extends ResourceAssembler支持,但在注入它时遇到问题。我用的是弹簧靴。有什么快速的建议吗?谢谢,它是用@Component注释的吗?愚蠢的错误:现在它自动连线了。因此,如果我理解正确,ResourceAssemblerSupport负责每个单独的资源链接,PagedResourcesAssembler负责整个资源?正确,您返回的资源是资源的集合。集合本身就是一个资源,它包含嵌入嵌套集合的_。每个嵌套集合项都是一个单独的资源,具有自己的链接集。PagedResourcesAssembler处理诸如prev/next links.Yup之类的事情。我把一切都搞定了。唯一的问题是,现在我必须为每个实体创建一个资源,然后为每个资源创建一个汇编程序。很多额外的课程。。。关于如何不必为每个实体创建汇编程序和资源,有什么建议吗?谢谢你的帮助。