Java 列“ID”H2 Hibernate不允许为NULL

我正在使用JavaEE和Wildfly 12。我有以下SQL表方案：

CREATE TABLE AUTHOR ("ID" INTEGER primary key, "FIRSTNAME" VARCHAR(50) not null, "SECONDNAME" VARCHAR(50) not null);
CREATE TABLE BOOK ("ID" INTEGER primary key, "TITLE" VARCHAR(50) not null, "AUTHOR" INTEGER, FOREIGN KEY ("AUTHOR") REFERENCES AUTHOR("ID"));

我要执行以下插入：

INSERT INTO AUTHOR("SECONDNAME","FIRSTNAME") values ('a', 'b');
INSERT INTO BOOK("TITLE","AUTHOR") values ('bookTitle', 1);

My persistence.xml：

<property name="hibernate.hbm2ddl.auto" value="create-drop" />
<property name="hibernate.show_sql" value="true" />
<property name="hibernate.dialect" value="org.hibernate.dialect.H2Dialect"/>
<property name="javax.persistence.schema-generation.create-source" value="script"/>
<property name="javax.persistence.schema-generation.drop-source" value="script"/>
<property name="javax.persistence.schema-generation.create-script-source" value="META-INF/create.sql"/>
<property name="javax.persistence.schema-generation.drop-script-source" value="META-INF/drop.sql"/>
<property name="javax.persistence.sql-load-script-source" value="META-INF/load.sql"/>

我尝试过所有的生成策略，自动、身份、顺序。正如我所说的，如果我在SQL中显式设置ID，SQL会工作，但在使用entityManager.persist时我会遇到同样的问题

@POST
@Path("/create")
public void createAuthor(Author author) {
    entityManager.persist(author);
}

所有这些都给了我：

Caused by: org.h2.jdbc.JdbcSQLException: NULL not allowed for column "ID"; SQL statement: ...

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有什么帮助吗？

您只声明了列ID是整数和主键。您从未将列设置为自动递增，因此错误消息是正确的。将DDL更改为：

CREATE TABLE AUTHOR (
    "ID" INTEGER primary key auto_increment,
    "FIRSTNAME" VARCHAR(50) not null,
    "SECONDNAME" VARCHAR(50) not null
);

CREATE TABLE BOOK (
    "ID" INTEGER primary key auto_increment,
    "TITLE" VARCHAR(50) not null,
    "AUTHOR" INTEGER, FOREIGN KEY ("AUTHOR") REFERENCES AUTHOR("ID")
);

---

您只声明了列ID是整数和主键。您从未将列设置为自动递增，因此错误消息是正确的。将DDL更改为：

CREATE TABLE AUTHOR (
    "ID" INTEGER primary key auto_increment,
    "FIRSTNAME" VARCHAR(50) not null,
    "SECONDNAME" VARCHAR(50) not null
);

CREATE TABLE BOOK (
    "ID" INTEGER primary key auto_increment,
    "TITLE" VARCHAR(50) not null,
    "AUTHOR" INTEGER, FOREIGN KEY ("AUTHOR") REFERENCES AUTHOR("ID")
);