Java 为什么我能'；在这个Spring应用程序中，是否将服务类（使用@Autowired）注入到主类（包含Main（）方法的类）中？
我在春天是个新手，我有以下问题 我正在实现一个Spring控制台应用程序（这不是一个web应用程序），它对数据库执行一些查询，我有以下配置： 1） 包含bean定义的beans.xml文件：Java 为什么我能'；在这个Spring应用程序中，是否将服务类（使用@Autowired）注入到主类（包含Main（）方法的类）中？,java,spring,frameworks,autowired,spring-annotations,Java,Spring,Frameworks,Autowired,Spring Annotations,我在春天是个新手，我有以下问题 我正在实现一个Spring控制台应用程序（这不是一个web应用程序），它对数据库执行一些查询，我有以下配置： 1） 包含bean定义的beans.xml文件： <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd">
<context:component-scan base-package="it.mycompany.myapp.profilatura.service" />
<!-- bean definitions here -->
<bean id="helloWorld" class="HelloWorld">
<property name="message" value="Hello World!"/>
</bean>
</beans>
utenteLoggatoService.getInfoUtenteLoggato();
@Service
@Transactional(rollbackFor={Exception.class})
public class UtenteLoggatoService {
public String getInfoUtenteLoggato() {
return "TEST";
}
}
@Component
public class MainApp {
@Autowired
private UtenteLoggatoService utenteLoggatoService;
public static void main(String[] args) {
ApplicationContext context = new ClassPathXmlApplicationContext("Beans.xml");
MainApp app = context.getBean(MainApp.class);
app.start();
//HelloWorld obj = (HelloWorld) context.getBean("helloWorld");
//obj.getMessage();
}
private void start() {
System.out.println("APPLICATION STARTED");
System.out.println(utenteLoggatoService.getInfoUtenteLoggato());
}
}
Exception in thread "main" org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException: Line 8 in XML document from class path resource [Beans.xml] is invalid; nested exception is org.xml.sax.SAXParseException; lineNumber: 8; columnNumber: 74; The prefix "context" for element "context:component-scan" is not bound.
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:399)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:336)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions(XmlBeanDefinitionReader.java:304)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:181)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:217)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:188)
at org.springframework.beans.factory.support.AbstractBeanDefinitionReader.loadBeanDefinitions(AbstractBeanDefinitionReader.java:252)
at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:127)
at org.springframework.context.support.AbstractXmlApplicationContext.loadBeanDefinitions(AbstractXmlApplicationContext.java:93)
at org.springframework.context.support.AbstractRefreshableApplicationContext.refreshBeanFactory(AbstractRefreshableApplicationContext.java:129)
at org.springframework.context.support.AbstractApplicationContext.obtainFreshBeanFactory(AbstractApplicationContext.java:537)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:452)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:139)
at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:83)
at MainApp.main(MainApp.java:14)
Caused by: org.xml.sax.SAXParseException; lineNumber: 8; columnNumber: 74; The prefix "context" for element "context:component-scan" is not bound.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:203)
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(ErrorHandlerWrapper.java:177)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:400)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:327)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:284)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:290)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:2787)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:606)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:118)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:510)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:848)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:777)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:141)
at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:243)
at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:339)
at org.springframework.beans.factory.xml.DefaultDocumentLoader.loadDocument(DefaultDocumentLoader.java:76)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadDocument(XmlBeanDefinitionReader.java:429)
at org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions(XmlBeanDefinitionReader.java:391)
... 14 more
Tnx我独自看着文档： 所以我有一个beans.xml文件：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd">
<context:component-scan base-package="it.mycompany.myproject.profilatura.app" />
<context:component-scan base-package="it.hp.miur.profilatura.service" />
<!-- bean definitions here -->
<bean id="helloWorld" class="it.mycompany.myproject.profilatura.app.HelloWorld">
<property name="message" value="Hello World!"/>
</bean>
</beans>
这样做，MainApp类是一个Spring组件，我将其实例化为一个Springbean，这样我就可以自动连接上下文中的另一个bean（作为Utenelogatoservice Utenelogatoservice） 您收到的异常与您提出的问题无关。为什么这会解决任何问题？文档的哪一部分引导您找到这个解决方案？因为用这种方式，MainApp类是一个Spring组件，我将它实例化为一个bean，以便在上下文中自动连接另一个bean。这很好，请将这些细节添加到您的a中
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.1.xsd">
<context:component-scan base-package="it.mycompany.myproject.profilatura.app" />
<context:component-scan base-package="it.hp.miur.profilatura.service" />
<!-- bean definitions here -->
<bean id="helloWorld" class="it.mycompany.myproject.profilatura.app.HelloWorld">
<property name="message" value="Hello World!"/>
</bean>
</beans>
@Component
public class MainApp {
@Autowired
private UtenteLoggatoService utenteLoggatoService;
public static void main(String[] args) {
ApplicationContext context = new ClassPathXmlApplicationContext("Beans.xml");
MainApp app = context.getBean(MainApp.class);
app.start();
//HelloWorld obj = (HelloWorld) context.getBean("helloWorld");
//obj.getMessage();
}
private void start() {
System.out.println("APPLICATION STARTED");
System.out.println(utenteLoggatoService.getInfoUtenteLoggato());
}
}