Java 如何将POJO转换为JSON，反之亦然？_Java_Json_Pojo

Java 如何将POJO转换为JSON，反之亦然？

java json

Java 如何将POJO转换为JSON，反之亦然？,java,json,pojo,Java,Json,Pojo,我想知道是否有Java API可用于将POJO对象转换为JSON对象，反之亦然 [已编辑] 假设您有这样一个简单的Java类： public class Person { private String name; private Integer age; public String getName() { return this.name; } public void setName( String name ) { this.name = name; }

我想知道是否有Java API可用于将POJO对象转换为JSON对象，反之亦然

[已编辑] 假设您有这样一个简单的Java类：

public class Person {

    private String name;
    private Integer age;

    public String getName() { return this.name; }
    public void setName( String name ) { this.name = name; }

    public Integer getAge() { return this.age; }
    public void setAge( Integer age ) { this.age = age; }

}

因此，将其转换为JSon对象非常简单。像这样：

import org.json.JSONObject;

public class JsonTest {

    public static void main( String[] args ) {
        Person person = new Person();
        person.setName( "Person Name" );
        person.setAge( 333 );

        JSONObject jsonObj = new JSONObject( person );
        System.out.println( jsonObj );
    }

}

希望能有帮助

[已编辑] 这里还有另一个例子，在本例中使用Jackson：

马文：

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.6.1</version>
</dependency>


com.fasterxml.jackson.core
我们还可以在pom文件中使用下面给定的依赖项和插件-我使用maven。通过使用这些，您可以根据JSON模式生成POJO，然后使用下面给出的代码通过指定为gson.toJson（object src）参数的src对象填充请求JSON对象，反之亦然。请看下面的代码：
Gson gson = new GsonBuilder().create();
String payloadStr = gson.toJson(data.getMerchant().getStakeholder_list());

Gson gson2 = new Gson();
Error expectederr = gson2.fromJson(payloadStr, Error.class);

以及Maven设置：
<dependency>
    <groupId>com.google.code.gson</groupId>
    <artifactId>gson</artifactId>
    <version>1.7.1</version>
</dependency>

<plugin>
    <groupId>com.googlecode.jsonschema2pojo</groupId>
    <artifactId>jsonschema2pojo-maven-plugin</artifactId>
    <version>0.3.7</version>
    <configuration>
        <sourceDirectory>${basedir}/src/main/resources/schema</sourceDirectory>
        <targetPackage>com.example.types</targetPackage>
    </configuration>
    <executions>
        <execution>
            <phase>generate-sources</phase>
            <goals>
                <goal>generate</goal>
            </goals>
        </execution>
    </executions>
</plugin>


com.google.code.gson
格森
1.7.1
com.googlecode.jsonschema2pojo
jsonschema2pojo maven插件
0.3.7
${basedir}/src/main/resources/schema
com.example.types
生成源
生成
如果您了解《杰克逊2》，在上有一个关于如何将Java对象转换为JSON以及如何将Java对象转换为JSON的精彩教程。以下代码片段取自该教程
将Java对象转换为JSON，writeValue（…）
：
ObjectMapper mapper = new ObjectMapper();
Staff obj = new Staff();

//Object to JSON in file
mapper.writeValue(new File("c:\\file.json"), obj);

//Object to JSON in String
String jsonInString = mapper.writeValueAsString(obj);

ObjectMapper mapper = new ObjectMapper();
String jsonInString = "{'name' : 'mkyong'}";

//JSON from file to Object
Staff obj = mapper.readValue(new File("c:\\file.json"), Staff.class);

//JSON from URL to Object
Staff obj = mapper.readValue(new URL("http://mkyong.com/api/staff.json"), Staff.class);

//JSON from String to Object
Staff obj = mapper.readValue(jsonInString, Staff.class);

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.6.3</version>
</dependency>

将JSON转换为Java对象，readValue（…）
：
ObjectMapper mapper = new ObjectMapper();
Staff obj = new Staff();

//Object to JSON in file
mapper.writeValue(new File("c:\\file.json"), obj);

//Object to JSON in String
String jsonInString = mapper.writeValueAsString(obj);

ObjectMapper mapper = new ObjectMapper();
String jsonInString = "{'name' : 'mkyong'}";

//JSON from file to Object
Staff obj = mapper.readValue(new File("c:\\file.json"), Staff.class);

//JSON from URL to Object
Staff obj = mapper.readValue(new URL("http://mkyong.com/api/staff.json"), Staff.class);

//JSON from String to Object
Staff obj = mapper.readValue(jsonInString, Staff.class);

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.6.3</version>
</dependency>

Jackson 2依赖项：
ObjectMapper mapper = new ObjectMapper();
Staff obj = new Staff();

//Object to JSON in file
mapper.writeValue(new File("c:\\file.json"), obj);

//Object to JSON in String
String jsonInString = mapper.writeValueAsString(obj);

ObjectMapper mapper = new ObjectMapper();
String jsonInString = "{'name' : 'mkyong'}";

//JSON from file to Object
Staff obj = mapper.readValue(new File("c:\\file.json"), Staff.class);

//JSON from URL to Object
Staff obj = mapper.readValue(new URL("http://mkyong.com/api/staff.json"), Staff.class);

//JSON from String to Object
Staff obj = mapper.readValue(jsonInString, Staff.class);

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.6.3</version>
</dependency>


com.fasterxml.jackson.core
杰克逊数据绑定
2.6.3

有关完整教程，请转到上面给出的链接。
使用GSON将POJO转换为JSONObject
要将JSONObject转换为POJO，只需在POJO中调用setter方法，并直接从JSONObject分配值。
您可以使用jackson api进行转换
<dependency>
  <groupId>com.fasterxml.jackson.core</groupId>
  <artifactId>jackson-databind</artifactId>
  <version>2.9.4</version>
</dependency>

稍后，我们需要将POJO类添加到映射器中
String json = mapper.writeValueAsString(pojo);

使用下面的引用将JSON转换为POJO，反之亦然
假设您的JSON模式如下所示：
{
  "type":"object",
  "properties": {
    "dataOne": {
      "type": "string"
    },
    "dataTwo": {
      "type": "integer"
    },
    "dataThree": {
      "type": "boolean"
    }
  }
}

然后，要转换为POJO，您需要按照下面的风格解释一些类：
==================================
package ;
public class DataOne
{
    private String type;

    public void setType(String type){
        this.type = type;
    }
    public String getType(){
        return this.type;
    }
}

==================================
package ;
public class DataTwo
{
    private String type;

    public void setType(String type){
        this.type = type;
    }
    public String getType(){
        return this.type;
    }
}

==================================
package ;
public class DataThree
{
    private String type;

    public void setType(String type){
        this.type = type;
    }
    public String getType(){
        return this.type;
    }
}

==================================
package ;
public class Properties
{
    private DataOne dataOne;

    private DataTwo dataTwo;

    private DataThree dataThree;

    public void setDataOne(DataOne dataOne){
        this.dataOne = dataOne;
    }
    public DataOne getDataOne(){
        return this.dataOne;
    }
    public void setDataTwo(DataTwo dataTwo){
        this.dataTwo = dataTwo;
    }
    public DataTwo getDataTwo(){
        return this.dataTwo;
    }
    public void setDataThree(DataThree dataThree){
        this.dataThree = dataThree;
    }
    public DataThree getDataThree(){
        return this.dataThree;
    }
}

==================================
package ;
public class Root
{
    private String type;

    private Properties properties;

    public void setType(String type){
        this.type = type;
    }
    public String getType(){
        return this.type;
    }
    public void setProperties(Properties properties){
        this.properties = properties;
    }
    public Properties getProperties(){
        return this.properties;
    }
}

Thnx但是。。。我想知道，如果我得到一个Pojo，我可以传递Pojo对象，这样库就可以构造JSON对象。。。格森能做到吗？你能给我举个例子吗？thnx alot@Bruno我们如何使用这个JSONObject获取List或Set的值。我喜欢这种方法——不幸的是，它对我不起作用。我收到错误消息：“构造函数JSONObject（Person）未定义”。。知道为什么吗？我用一些Android代码调用它。。它是纯Java。Thanks@gnB：即使我也会遇到同样的错误，我想如果你在安卓系统中尝试，那么它指的是。所以试着创建一个