Apache Drill:从Json数据中选择时发生创建表错误

下面的命令工作正常

选择时间戳（'ts`、'yyyyymmddhhmmss'））
来自dfs.tmp`/mapr/my.cluster.com/hive/cpf_sales.json

但当我试图从select语句创建一个表时，它给出了一个错误。下面是我试过的

ALTER SESSION SET `store.format`='json';
use dfs;

CREATE TABLE by_yr (gen_date)  AS SELECT TO_TIMESTAMP(`ts`,'yyyyMMddHHmmss') FROM dfs.`/mapr/my.cluster.com/hive/cpf_sales.json` LIMIT 100;

**Error:**
org.apache.drill.common.exceptions.UserRemoteException: PARSE ERROR: Encountered ";" at line 1, column 8. Was expecting one of: "." ... "[" ... SQL Query use dfs; ^ CREATE TABLE by_yr (gen_date) AS SELECT TO_TIMESTAMP(`ts`,'yyyyMMddHHmmss') FROM dfs.`/mapr/my.cluster.com/hive/cpf_sales.json` LIMIT 100 [Error Id: 81cbe394-b3c6-4c34-80ad-83325f748ae1 on iot3:31010]

use dfs.tmp;

CREATE TABLE by_yr (gen_date)  AS SELECT TO_TIMESTAMP(`ts`,'yyyyMMddHHmmss') FROM dfs.tmp`/mapr/my.cluster.com/hive/cpf_sales.json` LIMIT 100;

**Error:**
org.apache.drill.common.exceptions.UserRemoteException: PARSE ERROR: Encountered ";" at line 1, column 12. Was expecting one of: "." ... "[" ... SQL Query use dfs.tmp; ^ SELECT COLUMNS[0], COLUMNS[1] from dfs.tmp.`/mapr/my.cluster.com/donuts.json` [Error Id: 5e9d1d20-a804-4d09-8b69-d76b3c009647 on iot2:31010]

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能否尝试在路径周围加上单引号，例如：

ALTER SESSION SET store.format='json'; use dfs;

CREATE TABLE by_yr (gen_date) AS 
SELECT TO_TIMESTAMP(ts,'yyyyMMddHHmmss') 
FROM dfs.'/mapr/my.cluster.com/hive/cpf_sales.json' LIMIT 100;

这是有效的

创建表myHDFS.testdata.`/xuser/sample2.json`AS SELECT*FROM myHDFS.testdata.`sample.json``

使用存储配置

“测试数据”：{ “位置”：“/dir/data/test”， “可写”：正确， “defaultInputFormat”：“json”

---

}，

它仍然不起作用。错误：org.apache.drill.common.exceptions.UserRemoteException:解析错误：在第1行第38列遇到“；”。他期待着……中的一个。。。“UESCAPE”。。。SQL查询更改会话集存储。format='json'；^使用dfs；按年（生成日期）创建表，从dfs中选择时间戳（ts，'yyyyMMddHHmmss'）。/mapr/my.cluster.com/hive/cpf_sales.json'LIMIT 100