Java 使用Jakarta HttpClient模拟POST网络请求_Java

Java 使用Jakarta HttpClient模拟POST网络请求

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Java 使用Jakarta HttpClient模拟POST网络请求,java,Java,我尝试模拟由封闭源代码应用程序发送的网络请求。以下是否从封闭源应用程序捕获网络请求快照： - Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage Command: POST - URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage? Location: /%5bvUpJY

我尝试模拟由封闭源代码应用程序发送的网络请求。以下是否从封闭源应用程序捕获网络请求快照：

- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage
    Command: POST
  - URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage?
     Location: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage
    ProtocolVersion: HTTP/1.1
  - ContentType:  application/x-www-form-urlencoded
     MediaType:  application/x-www-form-urlencoded
    Cache-Control:  no-cache
    Pragma:  no-cache
    UserAgent:  Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06
    Host:  www.xxx.com:20000
    Accept:  text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2
    Connection:  keep-alive
    ContentLength:  164
    HeaderEnd: CRLF
  - payload: HttpContentType =  application/x-www-form-urlencoded
     [SORT]: 0,1,0,10,5,0,KL,0
     [FIELD]: 33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82
     [LIST]: 1155.KL,1295.KL,7191.KL,0097.KL,2267.KL

我使用httpclient模拟上述请求

/**
 * @param args the command line arguments
 */
public static void main(String[] args) {
    try {
        // TODO code application logic here
        HttpClient httpClient = new HttpClient();
        httpClient.getParams().setParameter(HttpMethodParams.USER_AGENT, "Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06");

        PostMethod post = new PostMethod("http://www.xxx.com:20000/%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage?");

        NameValuePair[] data = {
            new NameValuePair("SORT", "0,1,0,10,5,0,KL,0"),
            new NameValuePair("FIELD", "33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82"),
            new NameValuePair("LIST", "1155.KL,1295.KL,7191.KL,0097.KL,2267.KL")
        };
        post.setRequestBody(data);
        httpClient.executeMethod(post);
        System.out.println(post.getResponseBodyAsString());       
    }
    catch (Exception exp) {
        exp.printStackTrace();
    }
}

然而，服务器端并没有响应。我尝试捕获自己的网络请求快照：

- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    Command: POST
  - URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage
     Location: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    ProtocolVersion: HTTP/1.1
    UserAgent:  Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06
    Host:  www.xxx.com:20000
    ContentLength:  234
  - ContentType:  application/x-www-form-urlencoded
     MediaType:  application/x-www-form-urlencoded
    HeaderEnd: CRLF
  - payload: HttpContentType =  application/x-www-form-urlencoded
     SORT: 0%2C1%2C0%2C10%2C5%2C0%2CKL%2C0
     FIELD: 33%2C38%2C51%2C58%2C68%2C88%2C78%2C98%2C99%2C101%2C56%2C57%2C69%2C70%2C71%2C72%2C89%2C90%2C91%2C92%2C59%2C60%2C61%2C62%2C79%2C80%2C81%2C82
     LIST: 1155.KL%2C1295.KL%2C7191.KL%2C0097.KL%2C2267.KL

似乎有两种主要的不同：

（1） URI

（2）有效载荷

我的httpclient代码中有没有遗漏什么

经过几次实验，我意识到，httpclient对我的负载执行URL编码。它明确地转变为

1155.KL，1295.KL，7191.KL，0097.KL，2267.KL

到

1155.KL%2C1295.KL%2C7191.KL%2C0097.KL%2C2267.KL

为了避免这种情况，我编写了一个测试代码。下面的测试代码有效

try {
    Socket socket = new Socket("www.xxx.com", 20000);
    PrintWriter out = new PrintWriter(socket.getOutputStream(), true);
    final String body = "[SORT]=0,1,0,10,5,0,KL,0&[FIELD]=33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82&[LIST]=1155.KL,1295.KL,7191.KL,0097.KL,2267.KL";
    final int length = body.length();
    final String s = "POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage? HTTP/1.1\r\nContent-Type: application/x-www-form-urlencoded\r\nCache-Control: no-cache\r\nPragma: no-cache\r\nUser-Agent: Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06\r\nHost: www.xxx.com:20000\r\nAccept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2\r\nConnection: keep-alive\r\nContent-Length: "+length+"\r\n\r\n" + body;
    out.println(s);

     BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
     while(true) {
          String ss = in.readLine();
          if (ss == null) break;
            System.out.println(ss);
     }

}
catch (Exception exp) {
}

以下是捕获的快照：

  Frame: Number = 16, Captured Frame Length = 597, MediaType = ETHERNET 
+ Ethernet: Etype = Internet IP (IPv4),DestinationAddress:[7C-04-20-00-01-00],SourceAddress:[01-00-01-00-00-00]
+ Ipv4: Src = 10.176.181.55, Dest = 202.75.55.23, Next Protocol = TCP, Packet ID = 956, Total IP Length = 583
+ Tcp: Flags=...AP..., SrcPort=49253, DstPort=20000, PayloadLen=543, Seq=3920474750 - 3920475293, Ack=3537289604, Win=4380 (scale factor 0x2) = 17520
- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage
    Command: POST
  + URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage?
    ProtocolVersion: HTTP/1.1
  + ContentType:  application/x-www-form-urlencoded
    Cache-Control:  no-cache
    Pragma:  no-cache
    UserAgent:  Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06
    Host:  n2ntbfd03.asiaebroker.com:20000
    Accept:  text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2
    Connection:  keep-alive
    ContentLength:  164
    HeaderEnd: CRLF
  - payload: HttpContentType =  application/x-www-form-urlencoded
     [SORT]: 0,1,0,10,5,0,KL,0
     [FIELD]: 33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82
     [LIST]: 1155.KL,1295.KL,7191.KL,0097.KL,2267.KL

您是如何创建快照的？参数名称周围的括号是什么意思？同一个参数是否有多个值，而不是一个用逗号分隔的值，或者参数名称是否应该用括号括起来？

您还缺少标题：接受缓存控制布拉格马

仅Accept头就足以让服务器做出有意义的响应。对于httpclient 4，请尝试以下操作：

   httpclient.addRequestInterceptor(new HttpRequestInterceptor() {
      public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException {
        request.setHeader("Pragma","no-cache");
        request.setHeader("Cache-Control","no-cache");
        request.setHeader("Accept","text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2");
      }
    });

或者类似于httpclient 3.x的内容：

method.setRequestHeader("Pragma","no-cache");
method.setRequestHeader("Cache-Control","no-cache");
method.setRequestHeader("Accept","text/html, image/gif, image/jpeg, *; q=.2, */*;

根据捕获排序与[排序]中参数名称的显示方式判断。我怀疑服务器希望您发送带有多个表单控件的数组，如

排序=0&SORT=1&SORT=0

他们可能将此作为一种安全措施，因为这不能用HTML实现

编辑：您需要像这样传递参数

    NameValuePair[] data = {
        new NameValuePair("SORT", "0"),
        new NameValuePair("SORT", "1"),
        ...
        new NameValuePair("FIELD", "33"),
        ...
    };

很抱歉我正在使用HttpClient 3.1您能捕获原始请求吗？可能快照中出现的列表如下所示：SORT=0&SORT=1&SORT=0。。。但是您用于捕获请求的软件正在对列表进行漂亮的打印。现在真正的问题是，如何避免HttpClient对我的负载执行URL编码？请尝试捕获原始请求，以便我们可以查看列表是如何发布的。Fiddler是免费的，但只在windows上工作。查尔斯有30天的免费试用期。@Yan。您永远不希望在没有URL编码的情况下发送有效负载。它总是被编码的。你的捕获程序为你解码并组合了它。请参阅我编辑的答案。这是“选择多个值”的发布方式。否。这不管用。服务器希望看到原始“[SORT]=0,1,0,10,5,0，KL，0&[FIELD]=33，…”。但是HttpClient将始终执行URL编码。我使用原始TCP套接字对数据进行测试，没有编码，效果非常好。但是，我需要使用HttpClient，因为它支持NTLM。服务器当时不使用HTTP。只需组成你自己的身体和回应。setBody（）。请参阅了解解决方案