Java 深度系统-以前的';顶部';项目在更改时闪烁
我正在尝试建立一个深度处理系统。 其目标是使其功能类似于(Windows)窗口 我有一个名为“Window”的类,它可以接受一些参数,它将成功地绘制一个可以拖动的窗口 深度系统目前的工作状态。我无法单击当前窗口下的窗口,如果我单击另一个窗口,窗口的顺序将正确切换 问题是,每当我在窗口之间切换时,先前选择的窗口会闪烁(未绘制)一帧,然后再次出现 我根本不明白为什么会发生这种情况。这是我的密码,如果你需要进一步的信息,请告诉我 Windows.pde:Java 深度系统-以前的';顶部';项目在更改时闪烁,java,processing,Java,Processing,我正在尝试建立一个深度处理系统。 其目标是使其功能类似于(Windows)窗口 我有一个名为“Window”的类,它可以接受一些参数,它将成功地绘制一个可以拖动的窗口 深度系统目前的工作状态。我无法单击当前窗口下的窗口,如果我单击另一个窗口,窗口的顺序将正确切换 问题是,每当我在窗口之间切换时,先前选择的窗口会闪烁(未绘制)一帧,然后再次出现 我根本不明白为什么会发生这种情况。这是我的密码,如果你需要进一步的信息,请告诉我 Windows.pde: Window[] wins; int win_
Window[] wins;
int win_count = 0;
boolean win_drag = false;
int win_selected = 2;
void setup()
{
size(800, 600);
wins = new Window[3];
wins[0] = new Window("Test", 20, 20, 300, 200);
wins[1] = new Window("Test 2", 20, 260, 350, 225);
wins[2] = new Window("Test 3", 400, 20, 250, 150);
}
void draw()
{
background(10);
for (int i = 0; i < wins.length; i ++)
{
wins[i].draw_window();
}
}
void bringToTop(Window winID)
{
Window[] new_wins;
new_wins = new Window[wins.length];
int win_pos = -1;
for (int i = 0; i < wins.length; i ++)
{
if (wins[i] == winID)
{
win_pos = i;
break;
}
}
arrayCopy(wins, 0, new_wins, 0, win_pos);
arrayCopy(wins, win_pos + 1, new_wins, win_pos, wins.length - win_pos - 1);
new_wins[wins.length - 1] = winID;
arrayCopy(new_wins, wins);
}
boolean isOnTop(Window winID)
{
int win_pos = -1;
for (int i = 0; i < wins.length; i ++)
{
if (wins[i] == winID)
{
win_pos = i;
break;
}
}
Window[] top_wins;
top_wins = new Window[wins.length];
int winTopCount = 0;
for (int i = 0; i < wins.length; i ++)
{
if (mouse_in_rect(wins[i].winX, wins[i].winY, wins[i].winW, wins[i].winH + 24))
{
top_wins[winTopCount] = wins[i];
winTopCount ++;
}
}
int last_real_win = -1;
for (int i = 0; i < top_wins.length; i ++)
{
if (top_wins[i] != null)
{
last_real_win = i;
}
}
return (wins[win_pos] == top_wins[last_real_win]);
}
Window[]获胜;
int win_计数=0;
布尔值win_drag=false;
int win_selected=2;
无效设置()
{
尺寸(800600);
wins=新窗口[3];
wins[0]=新窗口(“测试”,20、20、300、200);
wins[1]=新窗口(“测试2”、20、260、350、225);
wins[2]=新窗口(“测试3”、400、20、250、150);
}
作废提款()
{
背景(10);
for(int i=0;i
WindowObj.pde:
class Window
{
String winT;
int winX;
int winY;
int winW;
int winH;
boolean dragging;
int winXOff;
int winYOff;
int winTH;
int my_id;
Window(String ttl, int WX, int WY, int WW, int WH)
{
winT = ttl;
winX = WX;
winY = WY;
winW = WW;
winH = WH;
dragging = false;
winXOff = 0;
winYOff = 0;
winTH = 24;
my_id = win_count ++;
}
void draw_window()
{
if (win_selected == my_id)
{
fill(60);
}
else
{
fill(40);
}
rect(winX, winY, winW, winTH);
fill(25);
rect(winX, winY + 24, winW, winH);
if (dragging == true)
{
winX = mouseX + winXOff;
winY = mouseY + winYOff;
if (winX < 0)
{
winX = 0;
}
if (winX > width - winW - 1)
{
winX = width - winW - 1;
}
if (winY < 0)
{
winY = 0;
}
if (winY > height - winH - winTH - 1)
{
winY = height - winH - winTH - 1;
}
}
Window win_pos = wins[0];
for (int i = 0; i < wins.length; i ++)
{
if (wins[i].my_id == my_id)
{
win_pos = wins[i];
}
}
if (mouse_in_rect(winX, winY, winW, 24) && mousePressed && mouseButton == LEFT && dragging == false && isOnTop(win_pos) && win_drag == false)
{
dragging = true;
winXOff = winX - mouseX;
winYOff = winY - mouseY;
win_drag = true;
win_selected = my_id;
bringToTop(win_pos);
}
if (mouse_in_rect(winX, winY + 24, winW, winH) && mousePressed && mouseButton == LEFT && dragging == false && isOnTop(win_pos) && win_drag == false)
{
win_selected = my_id;
bringToTop(win_pos);
}
if (dragging == true)
{
if (mouseButton != LEFT)
{
win_drag = false;
dragging = false;
winXOff = 0;
winYOff = 0;
}
}
}
}
类窗口
{
字符串winT;
int-winX;
温妮;
int winW;
int winH;
布尔拖动;
int-winXOff;
温约夫;
int winTH;
输入我的id;
窗口(字符串ttl、int WX、int WY、int WW、int WH)
{
winT=ttl;
winX=WX;
winY=WY;
winW=WW;
winH=WH;
拖动=假;
winXOff=0;
winYOff=0;
winTH=24;
my_id=win_count++;
}
无效绘图窗口()
{
如果(win\u selected==我的\u id)
{
填充(60);
}
其他的
{
填充(40);
}
rect(winX,winY,winW,winTH);
填充(25);
rect(winX,winY+24,winW,winH);
如果(拖动==true)
{
winX=mouseX+winXOff;
winY=mouseY+winYOff;
如果(winX<0)
{
winX=0;
}
如果(winX>width-winW-1)
{
winX=宽度-winW-1;
}
如果(winY<0)
{
winY=0;
}
if(winY>height-winH-winTH-1)
{
winY=高度-winH-winTH-1;
}
}
窗口win_pos=wins[0];
for(int i=0;i
mouseFunctions.pde:
boolean mouse_in_rect(int mX, int mY, int mW, int mH)
{
int but_x = mX;
int but_y = mY;
int but_w = mW;
int but_h = mH;
if (mouseX > but_x && mouseY > but_y && mouseX < but_x + but_w && mouseY < but_y + but_h)
{
return true;
}
else
{
return false;
}
}
boolean鼠标右键(intmx、intmy、intmw、intmh)
{
int但_x=mX;
int但_y=mY;
int,但w=mW;
int但_h=mH;
if(mouseX>but_x&&mouseY>but_y&&mouseX
问题是由您在单个循环中计算窗口顺序和图形引起的。如果一个窗口的位置发生了变化,则可以省略一个窗口的绘制,而另一个窗口的绘制会进行两次。注意,数组
wins
中窗口的索引已更改
将图形和窗口更新拆分为两种不同的方法:
类窗口
{
// ...
无效绘图窗口()
{
如果(win\u selected==我的\u id)
{
填充(60);
}
其他的
{
填充(40);
}
rect(winX,winY,winW,winTH);
填充(25);
rect(winX,winY+24,winW,winH);
}
无效更新_窗口()
{
如果(拖动==true)
{
// ...
}
// ...
}
首先更新窗口的顺序并计算其新位置。然后在单独的循环中绘制所有窗口:
void draw()
{
背景(10);
for(int i=0;i
Howdy Rabbid,这完全是个错误!重新添加:)。