Java Jackson XML列表元素与其根名称匹配

使用Jackson的

XmlMapper

，是否有办法使对象列表中元素的名称与

@JacksonXmlRootElement

中给出的

localName

匹配

例如，给定以下类

interface Foo {}

@JacksonXmlRootElement(localName = "bar")
class Bar implements Foo {}

@JacksonXmlRootElement(localName = "baz")
class Baz implements Foo {}

@JacksonXmlRootElement(localName = "container")
class FooContainer {
    @JacksonXmlElementWrapper(useWrapping = false)
    private List<Foo> foos;

    FooContainer(List<Foo> foos) {
        this.foos = foos;
    }

    public List<Foo> getFoos() {
        return foos;
    }
}

我们得到以下XML

<container>
  <foos/>
  <foos/>
</container>

有没有办法取而代之呢

<container>
  <bar/>
  <baz/>
</container>

---

我在Jackson中找不到这样做的方法，但在JAXB中这几乎是微不足道的

interface Foo {}

class Bar implements Foo {}

class Baz implements Foo {}

@XmlRootElement(name = "container")
@XmlAccessorType(XmlAccessType.FIELD)
class FooContainer {
    @XmlElements({
        @XmlElement(name = "bar", type = Bar.class),
        @XmlElement(name = "baz", type = Baz.class)
    })
    private List<Foo> foos;

    FooContainer() {}

    FooContainer(List<Foo> foos) {
        this.foos = foos;
    }

    public List<Foo> getFoos() {
        return foos;
    }
}

interface Foo {}

class Bar implements Foo {}

class Baz implements Foo {}

@XmlRootElement(name = "container")
@XmlAccessorType(XmlAccessType.FIELD)
class FooContainer {
    @XmlElements({
        @XmlElement(name = "bar", type = Bar.class),
        @XmlElement(name = "baz", type = Baz.class)
    })
    private List<Foo> foos;

    FooContainer() {}

    FooContainer(List<Foo> foos) {
        this.foos = foos;
    }

    public List<Foo> getFoos() {
        return foos;
    }
}

FooContainer container = new FooContainer(Arrays.asList(new Bar(), new Baz()));

JAXBContext jaxbContext = JAXBContext.newInstance(FooContainer.class);
Marshaller marshaller = jaxbContext.createMarshaller();
marshaller.marshal(container, System.out);