Java 滚动2个六边形骰子1000次，意外结果

当模拟滚动2个骰子1000次并显示结果时，它会不断返回意外值。我的计划是：

import java.util.*;

public class Prob1 {
    private int sides; //Amount of sides on die
    private int sumOfRolls; 
    private int[] arr; //Array that holds the count of each sum of the rolls
    private int count; //Temporarily holds value of sum of rolls before passing to array
    public Prob1() { //Default constructor, sets sides to 6
        sides = 6;
        sumOfRolls = 0;
        count =0;
        arr = new int[(sides*2)+1];
    }
    public void roll() { //Method that rolls the 2 dice
        for(int i=0;i<1000;i++) { //Repeats 1000 times
            int roll1 = (int) (Math.random()*sides)+1; //Rolls 1 die
            int roll2 = (int) (Math.random()*sides)+1; //Rolls other die
            sumOfRolls = roll1+roll2; //Sums both rolls
            for(int j=2;j<(sides*2)+1;j++) { //Goes through all the possible values of sums of roll
                if(sumOfRolls==j) { //Checks if sum of rolls is equal to the value presented by the for loop
                    count++; //Adds 1 to count of value of sum of roll
                    arr[j]=count; //Adds that value to array
                }
            }
        }
        System.out.println("Roll: " + sides + "-sided dice"); //Displays what kind of dice
    }
    public void frequency() { //Frequency table
        System.out.println("\n\n\nRoll Total  Frequency");
        System.out.println("---------------------");
        for(int i=2; i<(sides*2)+1; i++) { //Displays each value of array
            System.out.print(i + "           " + arr[i] + "\n");

        }

    }


}

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这是错误的，因为每个值的总和超过1000，两个骰子的滚动次数。有什么解决办法吗？

问题在于每次滚动后都没有重置计数变量

消除

count++

，只需执行

arr[j]++

编辑

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如中所述，循环是不必要的，因为您只需执行

arr[sumOfRolls]++

您没有在每次滚动后重置计数如果没有循环，那么

arr[sumOfRolls]++

不会更好吗？@Andreas，的确如此

Roll: 6-sided dice



Roll Total  Frequency
---------------------
2           952
3           995
4           976
5           989
6           991
7           999
8           1000
9           998
10           992
11           994
12           997