Java 如何将CAS身份验证与spring安全性集成?
我已经将spring安全性集成到我的项目中,之前我使用hibernate验证用户详细信息。现在我必须用CAS来做。 这是我当前的Spring security.xmlJava 如何将CAS身份验证与spring安全性集成?,java,spring-security,cas,Java,Spring Security,Cas,我已经将spring安全性集成到我的项目中,之前我使用hibernate验证用户详细信息。现在我必须用CAS来做。 这是我当前的Spring security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/sc
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
">
<global-method-security pre-post-annotations="enabled" />
<http pattern="/css/**" security="none"/>
<http pattern="/images/**" security="none"/>
<http pattern="/js/**" security="none"/>
<http pattern="/index.jsp" security="none"/>
<http pattern="/app/addNewUser.json" security="none"/>
<http pattern="/dbcomplogin.jsp" security="none"/>
<http pattern="/loggedout.jsp" security="none"/>
<http use-expressions="true">
<!--
Allow all other requests. In a real application you should
adopt a whitelisting approach where access is not allowed by default
-->
<intercept-url pattern="/**" access="isAuthenticated()" />
<form-login login-page='/dbcomplogin.jsp'
authentication-failure-url="/dbcomplogin.jsp?login_error=1"
default-target-url="/index.jsp" />
<logout logout-success-url="/loggedout.jsp" delete-cookies="JSESSIONID"/>
<remember-me />
</http>
<beans:bean id="myUserService" class="com.tcs.ceg.services.impl.UserServiceImpl" />
<authentication-manager>
<authentication-provider user-service-ref="myUserService" />
</authentication-manager>
</beans:beans>
在UserServiceImpl类loadUserByUsername方法中,我使用Hibernate调用从数据库获取用户详细信息,并返回用户名和密码(如果它们存在于数据库中)
但现在我必须使用CAS服务器来完成。请告诉我我需要在我的spring-security.xml中更改哪些内容,这样,如果用户未经过身份验证,将打开CAS服务器的登录页,单击注销,将进行单次注销,并打开CAS服务器的注销页。
我是CAS和spring security的新手,请帮助我。查看您用于导入bean名称空间的别名。如果您的xml配置为xmlns:beans=http://www.springframework.org/schema/beans xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance 别名为beans:beanYa使用beans:bean我在附近遇到同样的错误,请停止多次发布相同的问题。