具有多个单词的Java ask字符串输入
您好,我在使用Java询问直接全名时遇到问题具有多个单词的Java ask字符串输入,java,Java,您好,我在使用Java询问直接全名时遇到问题 System.out.println("DOCTOR"); System.out.println("Enter ID Number:"); idnumber = scan.next(); System.out.println("Enter Name"); name = scan.next(); System.out.println("Enter Field of Specialization:"); field = scan.next(); Sys
System.out.println("DOCTOR");
System.out.println("Enter ID Number:");
idnumber = scan.next();
System.out.println("Enter Name");
name = scan.next();
System.out.println("Enter Field of Specialization:");
field = scan.next();
System.out.println("ID " + idnumber);
System.out.println("Name " + name);
System.out.println("Specializtion " + field );
当我在下面输入此信息时:
ID=100 Name=Brandon Sullano
它给了我这个结果
ID 100
Name Brandon
Specializtion Sullano
我希望名称是动态的,这样我甚至可以输入两个单词如何操作?提前感谢。使用:
name = scan.nextLine();
此外,如果ID号是整数,请使用nextInt()
(确保还将idnumber
声明为int
,而不是字符串
)
固定代码:
System.out.println("DOCTOR");
System.out.println("Enter ID Number:");
idnumber = scan.nextInt();
scan.nextLine();
System.out.println("Enter Name");
name = scan.nextLine();
System.out.println("Enter Field of Specialization:");
field = scan.nextLine();
System.out.println("ID " + idnumber);
System.out.println("Name " + name);
System.out.println("Specializtion " + field );
仅使用next()
将获取空格前的所有输入nextLine()
将在按下return之前接受所有输入
有关扫描仪的详细信息
Pro提示:在大多数情况下,您将使用scan.nextLine()
而不是scan.next()
,因此您可能希望养成使用它的习惯。尝试以下代码:
import java.util.Scanner;
public class DoctorDoctor {
public static void main (String [] args) {
int idnumber;
String name, field;
Scanner sc = new Scanner(System.in);
System.out.println("DOCTOR");
/** Assuming ID number is an integer value */
System.out.print("Enter ID Number: ");
idnumber = sc.nextInt();
sc.nextLine(); // This is important, for clearing the new line character
System.out.print("Enter Name: ");
name = sc.nextLine();
System.out.print("Enter Field of Specialization: ");
field = sc.nextLine();
System.out.println();
System.out.printf("%-15s: %d%n", "ID Number", idnumber);
System.out.printf("%-15s: %s%n", "Name", name);
System.out.printf("%-15s: %s%n", "Specialization", field);
sc.close();
}
}
输入/输出示例:
DOCTOR
Enter ID Number: 100
Enter Name: Brandon
Enter Field of Specialization: Heart Surgeon
ID Number : 100
Name : Brandon
Specialization : Heart Surgeon
既然您说
scan.nextLine()
“不工作”,我建议使用BufferedReader
BufferedReader br=new BufferedReader(new InputStreamReader(System.in);
//in your code:
int idnumber = Integer.parseInt(br.readLine());
String name = br.readLine();
String field = br.readLine();
您必须导入
java.io.BufferedReader
和java.io.InputStreamReader
您看过扫描仪方法的文档了吗?我搜索了代码,但找不到将在该文档上查找尝试oracles文档。喜欢或神谕网站。或者,使用谷歌,但你知道怎么做吗?我看到了而不是扫描。下一步将使用scan.nextLine()但不起作用解释“不起作用”,我们对这个短语有点敏感。当我运行系统时,它不起作用。它会跳转询问我的姓名并跳过Id号。在我这方面效果很好。它会直接询问姓名并跳过Idnumber@UnknownOctopus专业提示:idnumber=scan.nextInt()
之后需要进行扫描.nextLine()
。否则,name=scan.nextLine()
将使用新行字符,导致程序跳转到“输入..字段”@Watermel0n Edited。谢谢