Java Servlet错误:HTTP状态405-此URL不支持HTTP方法GET
当我尝试在eclipse中运行代码时,它不会传递参数。 请检查下面的图片url 但是当我单独运行html代码时,它会传递值 我不知道为什么会这样。 我的Servlet代码是Java Servlet错误:HTTP状态405-此URL不支持HTTP方法GET,java,eclipse,servlets,runtime-error,http-error,Java,Eclipse,Servlets,Runtime Error,Http Error,当我尝试在eclipse中运行代码时,它不会传递参数。 请检查下面的图片url 但是当我单独运行html代码时,它会传递值 我不知道为什么会这样。 我的Servlet代码是 package com.example; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public
package com.example;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class AddServelet extends HttpServlet
{
public void services(HttpServletRequest req, HttpServletResponse resp) {
int i = Integer.parseInt(req.getParameter("num1"));
int j = Integer.parseInt(req.getParameter("num2"));
int k = i+j;
System.out.println(k);
}
}
我的web.xml代码是
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://xmlns.jcp.org/xml/ns/javaee" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" id="WebApp_ID" version="4.0">
<servlet>
<servlet-name>abc</servlet-name>
<servlet-class>com.example.AddServelet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>abc</servlet-name>
<url-pattern>/add</url-pattern>
</servlet-mapping>
</web-app>
abc
com.example.AddServelet
abc
/加
我的html代码
<html>
<body>
<form action="add">
Number 1: <input type="number" name="num1"><br>
Number 2: <input type="number" name="num2"><br>
<input type="submit">
</form>
</body>
</html>
第一名:
第二条:
谁能帮我一下吗。
提前感谢。重写
HttpServlet
受保护的void doGet(HttpServletRequest-req,httpservletresp)
方法如果要处理GET请求,则需要重写doPost方法,因为您正在提交表单,并且它是post请求
公共类AddServlet扩展了HttpServlet{
私有静态最终长serialVersionUID=1L
/**
* @see HttpServlet#HttpServlet()
*/
public AddServelet() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
int i = Integer.parseInt(req.getParameter("num1"));
int j = Integer.parseInt(req.getParameter("num2"));
int k = i+j;
System.out.println(k);
}
}该方法称为
服务
,而不是服务
。但是,是的,如果您使用的是HttpServlet
,那么您还可以重写其中一个doXYZ
方法。