Java 在每次单击按钮时显示不同的随机数
我正在构建我的第一个Java应用程序,但似乎无法使其正常工作。这是一个带有GUI和独立类的老虎机,它自己可以很好地工作 这是addSlots方法:Java 在每次单击按钮时显示不同的随机数,java,swing,Java,Swing,我正在构建我的第一个Java应用程序,但似乎无法使其正常工作。这是一个带有GUI和独立类的老虎机,它自己可以很好地工作 这是addSlots方法: lblSlot1 = new JLabel("?"); lblSlot1.setBounds(10, 50, 100, 20); panel.add(lblSlot1); lblSlot2 = new JLabel("?"); lblSlot2.setBounds(110, 50, 100, 20);
lblSlot1 = new JLabel("?");
lblSlot1.setBounds(10, 50, 100, 20);
panel.add(lblSlot1);
lblSlot2 = new JLabel("?");
lblSlot2.setBounds(110, 50, 100, 20);
panel.add(lblSlot2);
lblSlot3 = new JLabel("?");
lblSlot3.setBounds(210, 50, 100, 20);
panel.add(lblSlot3);
lblResult = new JLabel("Result goes here");
lblResult.setBounds(10, 100, 100, 20);
panel.add(lblResult);
}
public void addButtons(){
btnSpin = new JButton("Spin");
btnSpin.setBounds(50, 200, 100, 20);
btnSpin.addActionListener(new SpinHandler());
panel.add(btnSpin);
btnExit = new JButton("Exit");
btnExit.setBounds(250, 200, 100, 20);
btnExit.addActionListener(new ExitHandler());
panel.add(btnExit);
操作侦听器:
class SpinHandler implements ActionListener{
@Override
public void actionPerformed(ActionEvent arg0) {
System.out.println("Spin");
SlotMachine sm = new SlotMachine();
lblSlot1.setText(String.valueOf(sm.getSlot1()));
lblSlot2.setText(String.valueOf(sm.getSlot2()));
lblSlot3.setText(String.valueOf(sm.getSlot3()));
lblResult.setText(String.valueOf(sm.getResult()));
}
它只生成0,0,0,而不是随机数
这是slotmachine类:
public int getSlot1(){
return slot1;
}
public int getSlot2(){
return slot2;
}
public int getSlot3(){
return slot3;
}
public void spin(){
Random rand = new Random();
slot1 = rand.nextInt(10);
slot2 = rand.nextInt(10);
slot3 = rand.nextInt(10);
似乎您忘记了在getSlot#()方法中调用spin()方法您忘记了在
actionPerformed
中调用spin
方法。只需添加sm.spin();动作处理者,谢谢!