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带有通配符的java黑名单_Java_Algorithm_Lucene_Equals_Hashset - Fatal编程技术网

带有通配符的java黑名单

带有通配符的java黑名单,java,algorithm,lucene,equals,hashset,Java,Algorithm,Lucene,Equals,Hashset,我在数据库中有一个包含4个字符串列的表,每一行代表被阻止的用户或组 referrer | ip | userAgent | email 我所说的组是指其中一列(任何列)可以有通配符(星号),表示“阻止所有列” 例如这一行 www.google.com | 127.0.0.2 | * | yahoo.com 意味着每个用户请求以“谷歌.com”作为引用者,“127.0.0.2”ASIP和“雅虎.com”作为电子邮件,需要被阻止而不考虑用户代理,因为它具有通配符。 下面的代码以O(n)复杂度工作

我在数据库中有一个包含4个字符串列的表,每一行代表被阻止的用户或组

referrer | ip | userAgent | email
我所说的组是指其中一列(任何列)可以有通配符(星号),表示“阻止所有列”

例如这一行

www.google.com | 127.0.0.2 | * | yahoo.com

意味着每个用户请求以“谷歌.com”作为引用者,“127.0.0.2”ASIP和“雅虎.com”作为电子邮件,需要被阻止而不考虑用户代理,因为它具有通配符

。 下面的代码以O(n)复杂度工作,这对于一个小规模的表来说已经足够了,但是我的表包含超过百万行

class BlacklistEntry {

    private String referrer, ip, userAgent, email;
    private static List<BlacklistEntry> cache = new ArrayList<>();

    BlacklistEntry(String referrer, String ip, String userAgent, String email) {
        this.referrer = referrer;
        this.ip = ip;
        this.userAgent = userAgent;
        this.email = email;
    }

    private static boolean isBlacklisted(String ref, String ip, String ue, String email) {
        final String MATCH_ALL = "*";
        return cache.stream()
            .filter(e ->
                (MATCH_ALL.equals(e.getReferrer()) || e.getReferrer().equals(ref)) &&
                (MATCH_ALL.equals(e.getIp()) || e.getIp().equals(ip)) &&
                (MATCH_ALL.equals(e.getUserAgent()) || e.getUserAgent().equals(ue)) &&
                (MATCH_ALL.equals(e.getEmail()) || e.getEmail().equals(email)))
            .findFirst()
            .isPresent();
    }

    public String getReferrer() {
        return referrer;
    }

    public void setReferrer(String referrer) {
        this.referrer = referrer;
    }

    public String getIp() {
        return ip;
    }

    public void setIp(String ip) {
        this.ip = ip;
    }

    public String getUserAgent() {
        return userAgent;
    }

    public void setUserAgent(String userAgent) {
        this.userAgent = userAgent;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public static void main(String[] args) {

        cache.add(new BlacklistEntry("google.com", "127.0.0.2", "Mozilla", "yahoo.com"));
        cache.add(new BlacklistEntry("r1.com", "127.0.0.3", "Mozilla", "*"));
        cache.add(new BlacklistEntry("r2.com", "127.0.0.4", "Mozilla", "yahoo.com"));

        System.out.println(isBlacklisted("r2.com", "127.0.0.4", "Mozilla", "yahoo.com"));
        System.out.println(isBlacklisted("r1.com", "127.0.0.3", "Mozilla", "sould be true"));
        System.out.println(isBlacklisted("*", "127.0.0.3", "*", "*"));
    }
}
class BlacklistEntry{
私人字符串推荐人、ip、用户代理、电子邮件;
私有静态列表缓存=新的ArrayList();
BlacklistEntry(字符串引用者、字符串ip、字符串用户代理、字符串电子邮件){
this.referer=referer;
this.ip=ip;
this.userAgent=userAgent;
this.email=电子邮件;
}
私有静态布尔值被列入黑名单(字符串引用、字符串ip、字符串ue、字符串电子邮件){
最终字符串匹配_ALL=“*”;
返回cache.stream()
.过滤器(e->
(匹配所有.equals(e.getreferer())| e.getreferer().equals(ref))&&
(匹配所有.equals(e.getIp())| e.getIp().equals(ip))&&
(匹配所有.equals(e.getUserAgent())| e.getUserAgent().equals(ue))&&
(匹配所有.equals(e.getEmail())| | e.getEmail().equals(email)))
.findFirst()
.isPresent();
}
公共字符串getReferer(){
返回推荐人;
}
公共无效集合引用器(字符串引用器){
this.referer=referer;
}
公共字符串getIp(){
返回ip;
}
公共无效设置ip(字符串ip){
this.ip=ip;
}
公共字符串getUserAgent(){
返回用户代理;
}
public void setUserAgent(字符串userAgent){
this.userAgent=userAgent;
}
公共字符串getEmail(){
回复邮件;
}
公用电子邮件(字符串电子邮件){
this.email=电子邮件;
}
公共静态void main(字符串[]args){
add(新的BlacklistEntry(“google.com”、“127.0.0.2”、“Mozilla”、“yahoo.com”);
add(新的BlacklistEntry(“r1.com”、“127.0.0.3”、“Mozilla”、“*”));
add(新的BlacklistEntry(“r2.com”、“127.0.0.4”、“Mozilla”、“yahoo.com”);
System.out.println(被列入黑名单(“r2.com”、“127.0.0.4”、“Mozilla”、“yahoo.com”);
System.out.println(被列入黑名单(“r1.com”、“127.0.0.3”、“Mozilla”、“应该是真的”);
System.out.println(被列入黑名单(“*”、“127.0.0.3”、“*”、“*”);
}
}

有比O(n)更好的吗?我应该考虑使用

< P>我建议您使用RDB或.< /P> 然而,我认为使用二叉树可以降低成本。这保证了日志(n)时间成本

程序

  • 准备
    BlacklistEntry
    课程实施
  • 覆盖方法
    equals
    hashCode
    并实现比较器的
    比较
  • 声明
    TreeSet
    并附加数据
  • 执行
    BlacklistEntry#contains(object)
    ,它将返回它是否被列入黑名单

    此实现为基本的日志提供了有保证的日志(n)时间开销 操作(添加、删除和包含)

    样本

    黑名单

    package org.stackoverflow.btree;
    
    import java.util.Comparator;
    
    import lombok.AllArgsConstructor;
    import lombok.Data;
    import lombok.NoArgsConstructor;
    
    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    public class BlacklistEntry implements Comparator<BlacklistEntry> {
    
        private String referrer, ip, userAgent, email;
    
        @Override
        public boolean equals(Object obj) {
    
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (!(obj instanceof BlacklistEntry))
                return false;
    
            BlacklistEntry other = (BlacklistEntry) obj;
    
            // You need to deal with "*" for all elements
            // There should be another implementations to solve troublesome
            // boiler-plate codes, for example to use reflection or commons.lang.
            if (email == null) {
                if (other.email != null) {
                    return false;
                }
            } else if (!email.equals(other.email) && !(email.equals("*") || other.email.equals("*")) ) {
                return false;
            }
    
            if (ip == null) {
                if (other.ip != null) {
                    return false;
                }
            } else if (!ip.equals(other.ip) && !(ip.equals("*") || other.ip.equals("*")) ) {
                return false;
            }
    
            if (referrer == null) {
                if (other.referrer != null) {
                    return false;
                }
            } else if (!referrer.equals(other.referrer) && !(referrer.equals("*") || other.referrer.equals("*")) ) {
                return false;
            }
    
            if (userAgent == null) {
                if (other.userAgent != null) {
                    return false;
                }
            } else if (!userAgent.equals(other.userAgent) && !(userAgent.equals("*") || other.userAgent.equals("*")) ) {
                return false;
            }
    
            return true;
        }
    
        // I just generated #hashCode with eclipse
        @Override
        public int hashCode() {
            final int prime = 31;
            int result = 1;
            result = prime * result + ((email == null) ? 0 : email.hashCode());
            result = prime * result + ((ip == null) ? 0 : ip.hashCode());
            result = prime * result + ((referrer == null) ? 0 : referrer.hashCode());
            result = prime * result + ((userAgent == null) ? 0 : userAgent.hashCode());
            return result;
        }
    
        // if left obj & right obj is equals == true
        //   --> "*" or just completely matching
        // else
        //   --> detect which is larger than the another one
        //   (this #compare method is used by binary-tree)
        public int compare(BlacklistEntry o1, BlacklistEntry o2) {
            if (o1.equals(o2)) {
                return 0;
            } else {
                return (o1.hashCode() < o2.hashCode()) ? -1 : 1;
            }
        }
    
    }
    

    我建议您使用RDB或

    然而,我认为使用二叉树可以降低成本。这保证了日志(n)时间成本

    程序

  • 准备
    BlacklistEntry
    课程实施
  • 覆盖方法
    equals
    hashCode
    并实现比较器的
    比较
  • 声明
    TreeSet
    并附加数据
  • 执行
    BlacklistEntry#contains(object)
    ,它将返回它是否被列入黑名单

    此实现为基本的日志提供了有保证的日志(n)时间开销 操作(添加、删除和包含)

    样本

    黑名单

    package org.stackoverflow.btree;
    
    import java.util.Comparator;
    
    import lombok.AllArgsConstructor;
    import lombok.Data;
    import lombok.NoArgsConstructor;
    
    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    public class BlacklistEntry implements Comparator<BlacklistEntry> {
    
        private String referrer, ip, userAgent, email;
    
        @Override
        public boolean equals(Object obj) {
    
            if (this == obj)
                return true;
            if (obj == null)
                return false;
            if (!(obj instanceof BlacklistEntry))
                return false;
    
            BlacklistEntry other = (BlacklistEntry) obj;
    
            // You need to deal with "*" for all elements
            // There should be another implementations to solve troublesome
            // boiler-plate codes, for example to use reflection or commons.lang.
            if (email == null) {
                if (other.email != null) {
                    return false;
                }
            } else if (!email.equals(other.email) && !(email.equals("*") || other.email.equals("*")) ) {
                return false;
            }
    
            if (ip == null) {
                if (other.ip != null) {
                    return false;
                }
            } else if (!ip.equals(other.ip) && !(ip.equals("*") || other.ip.equals("*")) ) {
                return false;
            }
    
            if (referrer == null) {
                if (other.referrer != null) {
                    return false;
                }
            } else if (!referrer.equals(other.referrer) && !(referrer.equals("*") || other.referrer.equals("*")) ) {
                return false;
            }
    
            if (userAgent == null) {
                if (other.userAgent != null) {
                    return false;
                }
            } else if (!userAgent.equals(other.userAgent) && !(userAgent.equals("*") || other.userAgent.equals("*")) ) {
                return false;
            }
    
            return true;
        }
    
        // I just generated #hashCode with eclipse
        @Override
        public int hashCode() {
            final int prime = 31;
            int result = 1;
            result = prime * result + ((email == null) ? 0 : email.hashCode());
            result = prime * result + ((ip == null) ? 0 : ip.hashCode());
            result = prime * result + ((referrer == null) ? 0 : referrer.hashCode());
            result = prime * result + ((userAgent == null) ? 0 : userAgent.hashCode());
            return result;
        }
    
        // if left obj & right obj is equals == true
        //   --> "*" or just completely matching
        // else
        //   --> detect which is larger than the another one
        //   (this #compare method is used by binary-tree)
        public int compare(BlacklistEntry o1, BlacklistEntry o2) {
            if (o1.equals(o2)) {
                return 0;
            } else {
                return (o1.hashCode() < o2.hashCode()) ? -1 : 1;
            }
        }
    
    }
    

    假设对于每一行,四个列中只有一个可以有通配符,一种简单的方法是有五个哈希集:一个哈希集匹配所有列,一个哈希集匹配三个非通配符列。然后,检查黑名单包括在五个集合中的每一个集合中查找条目,这是渐近恒定时间(
    O(1)

    概念验证代码(当然可以改进):

    import java.util.ArrayList;
    导入java.util.array;
    导入java.util.HashSet;
    导入java.util.List;
    导入java.util.Objects;
    导入java.util.Set;
    公共类黑名单{
    私有静态类BlacklistEntry{
    私有字符串[]字段;
    私有BlacklistEntry(字符串…字段){
    this.fields=字段;
    }
    @凌驾
    公共int hashCode(){
    返回Objects.hash(字段);
    }
    @凌驾
    公共布尔等于(最终对象obj){
    返回BlacklistEntry和array.equals(fields,((BlacklistEntry)obj.fields)的obj实例;
    }
    }
    私有静态列表通配符集=新ArrayList();
    私有静态最终整型字段_计数=4;
    静止的{
    对于(int i=0;ifalse
    true
    false
    false
    false
    
    import java.util.ArrayList;
    import java.util.Arrays;
    import java.util.HashSet;
    import java.util.List;
    import java.util.Objects;
    import java.util.Set;
    
    public class Blacklist {
    
        private static class BlacklistEntry {
            private String[] fields;
    
            private BlacklistEntry(String... fields) {
                this.fields = fields;
            }
    
            @Override
            public int hashCode() {
                return Objects.hash(fields);
            }
    
            @Override
            public boolean equals(final Object obj) {
                return obj instanceof BlacklistEntry && Arrays.equals(fields, ((BlacklistEntry)obj).fields);
            }
        }
    
        private static List<Set<BlacklistEntry>> wildcardSets = new ArrayList<>();
    
        private static final int FIELD_COUNT = 4;
    
        static {
            for (int i = 0; i < FIELD_COUNT; i++) {
                wildcardSets.add(new HashSet<>());
            }
        }
        private static Set<BlacklistEntry> fullMatchSet = new HashSet<>();
    
        private static boolean isBlacklisted(String... fields) {
            if (fullMatchSet.contains(new BlacklistEntry(fields))) {
                return true;
            }
            for (int i = 0; i < FIELD_COUNT; i++) {
                if (wildcardSets.get(i).contains(new BlacklistEntry(removeField(fields, i)))) {
                    return true;
                }
            }
            return false;
        }
    
        private static void addEntry(BlacklistEntry entry) {
            if (entry.fields.length != FIELD_COUNT) {
                throw new RuntimeException("Invalid entry, should contain four fields");
            }
            for (int i = 0; i < FIELD_COUNT; i++) {
                if ("*".equals(entry.fields[i])) {
                    // Make a copy of the fields list without the wildcard, and add it to the correct set.
                    String[] fields = removeField(entry.fields, i);
                    wildcardSets.get(i).add(new BlacklistEntry(fields));
                    return;
                }
            }
            // No wildcards in field list.
            fullMatchSet.add(entry);
        }
    
        private static String[] removeField(final String[] fields, final int index) {
            String[] newFields = new String[fields.length - 1];
            for (int i = 0; i < index; i++) {
                newFields[i] = fields[i];
            }
            for (int i = index + 1; i < FIELD_COUNT; i++) {
                newFields[i - 1] = fields[i];
            }
            return newFields;
        }
    
    
        public static void main(String[] args) {
    
            addEntry(new BlacklistEntry("r1.com", "127.0.0.1", "UA1", "*"));
            addEntry(new BlacklistEntry("r2.com", "127.0.0.2", "*", "e1.com"));
            addEntry(new BlacklistEntry("r3.com", "*", "UA2", "e2.com"));
            addEntry(new BlacklistEntry("*", "127.0.0.3", "UA3", "e3.com"));
            addEntry(new BlacklistEntry("r4.com", "127.0.0.4", "UA4", "e4.com"));
    
            // All these should return true
            System.out.println(isBlacklisted("r1.com", "127.0.0.1", "UA1", "wildcard"));
            System.out.println(isBlacklisted("r2.com", "127.0.0.2", "wildcard", "e1.com"));
            System.out.println(isBlacklisted("r3.com", "wildcard", "UA2", "e2.com"));
            System.out.println(isBlacklisted("wildcard", "127.0.0.3", "UA3", "e3.com"));
            System.out.println(isBlacklisted("r4.com", "127.0.0.4", "UA4", "e4.com"));
    
            // All these should return false
            System.out.println(isBlacklisted("r1.com", "127.0.0.1", "no match", "wildcard"));
            System.out.println(isBlacklisted("no match", "127.0.0.2", "wildcard", "e1.com"));
            System.out.println(isBlacklisted("r3.com", "wildcard", "no match", "e2.com"));
            System.out.println(isBlacklisted("wildcard", "127.0.0.3", "UA3", "no match"));
            System.out.println(isBlacklisted("r5.com", "127.0.0.5", "UA4", "e5.com"));
        }
    
    }
    
    private static boolean check(Set cache, String ref, String ip, String ue, String mail) {
        return Sets.powerSet(ImmutableSet.of(0, 1, 2, 3)).stream().map(set -> {
            BlacklistKey key = new BlacklistKey("*", "*", "*", "*");
            for (Integer idx : set) {
                switch (idx) {
                    case 0:
                        key.setReferrer(ref);
                        break;
                    case 1:
                        key.setIp(ip);
                        break;
                    case 2:
                        key.setUserAgent(ue);
                        break;
                    case 3:
                        key.setEmail(mail);
                }
            }
            return key;
        }).anyMatch(keys::contains);
    }
    
    import org.apache.lucene.analysis.standard.StandardAnalyzer;
    import org.apache.lucene.document.Document;
    import org.apache.lucene.document.Field;
    import org.apache.lucene.document.StringField;
    import org.apache.lucene.index.DirectoryReader;
    import org.apache.lucene.index.IndexWriter;
    import org.apache.lucene.index.IndexWriterConfig;
    import org.apache.lucene.index.Term;
    import org.apache.lucene.search.BooleanClause;
    import org.apache.lucene.search.BooleanQuery;
    import org.apache.lucene.search.IndexSearcher;
    import org.apache.lucene.search.TermQuery;
    import org.apache.lucene.store.RAMDirectory;
    
    import java.io.IOException;
    
    class Blacklist {
    
        private static final String MATCH_ALL = "*";
        private static IndexSearcher cache;
    
        private enum Fields {
            REFERRER, IP, USER_AGENT, EMAIL
        }
    
        private static Document getDocument(String referrer, String ip, String userAgent, String email) {
            Document doc = new Document();
            doc.add(getStringField(referrer, Fields.REFERRER.name()));
            doc.add(getStringField(ip, Fields.IP.name()));
            doc.add(getStringField(userAgent, Fields.USER_AGENT.name()));
            doc.add(getStringField(email, Fields.EMAIL.name()));
            return doc;
        }
    
        private static StringField getStringField(String val, String field) {
            return new StringField(field, val, Field.Store.NO);
        }
    
        private static BooleanQuery createQuery(String referrer, String ip, String userAgent, String email) {
            return new BooleanQuery.Builder()
                    .add(createBooleanQuery(Fields.REFERRER.name(), referrer), BooleanClause.Occur.FILTER)
                    .add(createBooleanQuery(Fields.IP.name(), ip), BooleanClause.Occur.FILTER)
                    .add(createBooleanQuery(Fields.USER_AGENT.name(), userAgent), BooleanClause.Occur.FILTER)
                    .add(createBooleanQuery(Fields.EMAIL.name(), email), BooleanClause.Occur.FILTER)
                    .build();
        }
    
        private static BooleanQuery createBooleanQuery(String key, String value) {
            return new BooleanQuery.Builder()
                    .add(new TermQuery(new Term(key, value)), BooleanClause.Occur.SHOULD)
                    .add(new TermQuery(new Term(key, MATCH_ALL)), BooleanClause.Occur.SHOULD)
                    .build();
        }
    
        private static boolean isBlacklisted(String ref, String ip, String ue, String email) throws IOException {
            BooleanQuery query = createQuery(ref, ip, ue, email);
            return cache.search(query, 1).totalHits > 0;
        }
    
    
        public static void main(String[] args) throws IOException {
            RAMDirectory directory = new RAMDirectory();
            IndexWriter writer = new IndexWriter(directory, new IndexWriterConfig(new StandardAnalyzer()));
            writer.addDocument(getDocument("ref1", "127.0.0.ip1", "Mozilla UserAgent1", "email.com"));
            writer.addDocument(getDocument("ref2", "127.0.0.ip2", "Mozilla UserAgent2", "*"));
            writer.close();
            DirectoryReader reader = DirectoryReader.open(directory);
            cache = new IndexSearcher(reader);
    
            System.out.println(isBlacklisted("ref1", "127.0.0.ip1", "Mozilla UserAgent1", "email.com"));
            System.out.println(isBlacklisted("r2.com", "127.0.0.4", "Mozilla", "yahoo.com"));
            System.out.println(isBlacklisted("ref2", "127.0.0.ip2", "Mozilla UserAgent2", "this is ignored"));
            System.out.println(isBlacklisted("*", "127.0.0.ip2", "Mozilla UserAgent2", "*"));
        }
    }