Java 防止工作重叠

我是石英2.1的新手，对此有疑问。我的工作如下

@PersistJobDataAfterExecution
@DisallowConcurrentExecution
public class HelloJob implements Job {

    public void execute(JobExecutionContext arg0) throws JobExecutionException {

我创造了2个工作岗位，如下所示

JobDetail jobDetail = JobBuilder.newJob(HelloJob.class).withIdentity("Job1").build();
JobDetail jobDetail2 = JobBuilder.newJob(HelloJob.class).withIdentity("Job2").storeDurably().build();
Trigger trigger = TriggerBuilder.newTrigger().forJob(jobDetail).withSchedule(
                        SimpleScheduleBuilder.simpleSchedule()
                                .withIntervalInSeconds(5).repeatForever()).build();
Trigger trigger2 = TriggerBuilder.newTrigger().forJob(jobDetail2).withSchedule(
                        SimpleScheduleBuilder.simpleSchedule()
                                .withIntervalInSeconds(10).repeatForever()).build();
        SchedulerFactory factory = new StdSchedulerFactory("quartz.properties");
        Scheduler scheduler = factory.getScheduler();
        scheduler.start();
        scheduler.scheduleJob(jobDetail, trigger);
        scheduler.scheduleJob(jobDetail2, trigger2);

如您所见，job1每5秒执行一次，job2每10秒执行一次。我想要的是，如果job1需要10秒以上才能完成，那么job2将一直执行到job1完成。但实际上，job2仍在执行，而job1未完成。你能帮帮我吗

P/s: this is the quartz.properties:
org.quartz.threadPool.class = org.quartz.simpl.SimpleThreadPool
org.quartz.threadPool.threadCount = 2
org.quartz.threadPool.threadsInheritContextClassLoaderOfInitializingThread = true

如果使用同一作业，则只需要一个JobDetail实例（而不是两个）

致电storeDurably了解您的工作详情

为trigger和trigger2设置相同的jobDetail

按以下方式安排作业：

scheduler.start();
scheduler.addJob(jobDetail, true);
scheduler.scheduleJob(trigger);
scheduler.scheduleJob(trigger2);

代码的其他部分是好的