Java 需要使用数组创建发票程序的帮助吗

Java 需要使用数组创建发票程序的帮助吗,java,arrays,invoice,invoices,Java,Arrays,Invoice,Invoices,我不知道我的代码应该放在哪里,同样在我的if循环中,它不允许我在第一个循环后输入更多的公司名称 分配4: import java.util.Scanner; public class Assign4 { private static int invoice; public static void main(String[] args) { Scanner scan = new Scanner(System.in); OurDate date

我不知道我的代码应该放在哪里,同样在我的if循环中,它不允许我在第一个循环后输入更多的公司名称

分配4:

import java.util.Scanner;

public class Assign4 {

    private static int invoice;

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        OurDate date = new OurDate();
        Invoice inv = new Invoice();
        Ledger led = new Ledger();

        System.out.print("Enter the amount of monthly invoices: ");
        invoice = scan.nextInt();

        for(int i = 0; i < invoice; i++){

            System.out.println("\nEnter info for invoice number " + i);
            inv.setCompanyNameFromUser();
            inv.toString();
            inv.setBillAmountFromUser();
            inv.setDateFromUser();
            date.setDayFromUser();
            date.setMonthFromUser();
            date.setYearFromUser(); 
        }
    }
}
发票:

import java.util.Scanner;

public class Invoice {

    private double billAmount;
    private String name;
    private OurDate dueDate;
    Scanner scan = new Scanner(System.in);

    public Invoice(){
        billAmount = 0;
    }
    public void setDateFromUser(){
        System.out.print("Enter invoice due date\n");
        //dueDate = scan.nextInt();
    }
    public void setCompanyNameFromUser(){
        System.out.print("Enter the company name : ");
        name = scan.nextLine();
    }
    public void setBillAmountFromUser(){
        System.out.print("Enter bill amount : ");
        billAmount = scan.nextDouble();
    }
    public String toString(){
        return name;

    }

}
分类账:

import java.util.Scanner;

public class Ledger {

    private Invoice [] invoices;
    private int numInvoices;
    Scanner scan = new Scanner(System.in);

    public Ledger(){

    }
    /*public Ledger(int){

    }*/
    public void getInvoiceInfo(){
        System.out.println("Enter info for the invoice number 0\n");
    }
    public void printInvoiceInfo(){

    }
    public double calculateMonthBills(){
        return numInvoices;

    }   
}

正如Manos Nikolaidis提到的链接所指出的,您需要调用nextLine跳过发票对象中包含的扫描仪对象上的readInt之后的\n

下面修改的代码应该可以解决您的问题

import java.util.Scanner;

public class Assign4 {

    private static int invoice;

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        OurDate date = new OurDate();
        Invoice inv = new Invoice();
        Ledger led = new Ledger();

        System.out.print("Enter the amount of monthly invoices: ");
        invoice = scan.nextInt();

        for(int i = 0; i < invoice; i++) {

            System.out.println("\nEnter info for invoice number " + i);
            inv.setCompanyNameFromUser();
            inv.toString();
            inv.setBillAmountFromUser();
            inv.setDateFromUser();
            date.setDayFromUser();
            date.setMonthFromUser();
            date.setYearFromUser();
            inv.scan.nextLine(); // Need this line so \n is skipped
        }
    }
}

什么是if循环?也许您应该解释代码在哪个特定步骤上失败。然后,您应该详细描述您如何尝试解决该问题。然后,您应该描述该解决方案中哪些不起作用。然后,你应该问一个具体的、可回答的问题。
import java.util.Scanner;

public class Assign4 {

    private static int invoice;

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        OurDate date = new OurDate();
        Invoice inv = new Invoice();
        Ledger led = new Ledger();

        System.out.print("Enter the amount of monthly invoices: ");
        invoice = scan.nextInt();

        for(int i = 0; i < invoice; i++) {

            System.out.println("\nEnter info for invoice number " + i);
            inv.setCompanyNameFromUser();
            inv.toString();
            inv.setBillAmountFromUser();
            inv.setDateFromUser();
            date.setDayFromUser();
            date.setMonthFromUser();
            date.setYearFromUser();
            inv.scan.nextLine(); // Need this line so \n is skipped
        }
    }
}