Java 如何从xml保存换行符？

当我从这个页面检索歌词时，换行符消失了。我以单个字符串检索xml，为了简化这个问题，我使用子字符串减去歌词。当我使用以下代码打印每个字符时，没有可见的换行符

if (response.contains("lyrics_body")) {
            lyrics = response.substring(response.indexOf("<lyrics_body>") + 13, response.indexOf("</lyrics_body>"));
            StringReader sr = new StringReader(lyrics);
            int l;
            try {
                while ((l = sr.read()) != -1) {
                    System.out.println(":" + l);
                }
            } catch (Exception ex) {

            }
        }

为了清晰起见，我在数字后面添加了单独的字符，显然在“baby”和“dog”之间应该有一个新行

---

如何解析此换行符？

在

BufferedReader

中包装

StringReader

，并使用

readLine（）

---

我从某处使用过这个来源：

public static String postData(String base, List<BasicNameValuePair> data) throws IOException {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(base);
    HttpResponse response = null;
    String line = "";
    StringBuilder total = new StringBuilder();
    HttpProtocolParams.setUseExpectContinue(httpclient.getParams(), false);

    try {
        httppost.setEntity(new UrlEncodedFormEntity(data));

        // Execute HTTP Post Request
        response = httpclient.execute(httppost);

        // Wrap a BufferedReader around the InputStream
        BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

        // Read response until the end
        while ((line = rd.readLine()) != null) {
            total.append(line);
            total.append("\n"); //I'VE JUST ADDED THIS LINE
        }

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    // Return full string
    return total.toString();
}

公共静态字符串postData（字符串基、列表数据）引发IOException{
//创建一个新的HttpClient和Post头
HttpClient HttpClient=新的DefaultHttpClient（）；
HttpPost HttpPost=新的HttpPost（基础）；
HttpResponse响应=null；
字符串行=”；
StringBuilder总计=新StringBuilder（）；
HttpProtocolParams.setUseExpectContinue（httpclient.getParams（），false）；
试一试{
setEntity（新的UrlEncodedFormEntity（数据））；
//执行HTTP Post请求
response=httpclient.execute（httppost）；
//在InputStream周围包装一个BufferedReader
BufferedReader rd=新的BufferedReader（新的InputStreamReader（response.getEntity（）.getContent（））；
//读取响应直到结束
而（（line=rd.readLine（））！=null）{
合计.追加（行）；
total.append（“\n”）；//我刚刚添加了这一行
}
}捕获（客户端协议例外e）{
//TODO自动生成的捕捉块
e、 printStackTrace（）；
}
//返回完整字符串
返回total.toString（）；
}

---

显然，它说“我刚刚添加了这一行”的部分是问题所在，谢谢Jon让我看这段代码

如何将元素作为字符串检索？请提供一个简短但完整的示例。该XML是错误的。XML不区分空格；他们需要摆脱他们的新台词。向公司投诉。

    BufferedReader bufferedReader = new BufferedReader(new StringReader(lyrics));

    for (String line = bufferedReader.readLine(); line != null; line = bufferedReader.readLine()) {
        // do something with line
    }

public static String postData(String base, List<BasicNameValuePair> data) throws IOException {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(base);
    HttpResponse response = null;
    String line = "";
    StringBuilder total = new StringBuilder();
    HttpProtocolParams.setUseExpectContinue(httpclient.getParams(), false);

    try {
        httppost.setEntity(new UrlEncodedFormEntity(data));

        // Execute HTTP Post Request
        response = httpclient.execute(httppost);

        // Wrap a BufferedReader around the InputStream
        BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));

        // Read response until the end
        while ((line = rd.readLine()) != null) {
            total.append(line);
            total.append("\n"); //I'VE JUST ADDED THIS LINE
        }

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    // Return full string
    return total.toString();
}