Java 在startActivityForResult()之后检索联系人姓名和电话
我已经开始了一项新的意图活动,以获得结果 代码: 现在我想得到电话和号码:Java 在startActivityForResult()之后检索联系人姓名和电话,java,android,Java,Android,我已经开始了一项新的意图活动,以获得结果 代码: 现在我想得到电话和号码: protected void onActivityResult(int requestCode, int resultCode, Intent data) { if (requestCode == 1) { if(resultCode == RESULT_OK){ Uri contactUri = data.getData(); String
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (requestCode == 1) {
if(resultCode == RESULT_OK){
Uri contactUri = data.getData();
String[] pN = {Phone.NUMBER};
String[] pNa = {Phone.CONTACT_ID};//idk
Cursor cP = getContentResolver().query(contactUri, pN, null, null, null);
cP.moveToFirst();
Cursor cPa = getContentResolver().query(contactUri, pNa, null, null, null);
cPa.moveToFirst();
int numc = cP.getColumnIndex(Phone.NUMBER);
String num = cP.getString(numc);
int namec = cPa.getColumnIndex(Phone.CONTACT_ID);//idk
String name = cPa.getString(namec);//idk
Log.i("", name);
}
if (resultCode == RESULT_CANCELED) {
//DO OTHER STUFF
}
}
}
电话号码很好,但我无法检索联系人的姓名 试试这段代码,它可能有助于进行一些小的更改
static final int PICK_CONTACT_=1;
Intent intent_1 = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent_1, PICK_CONTACT_);
@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);
switch (reqCode) {
case (PICK_CONTACT_) :
if (resultCode == Activity.RESULT_OK) {
Uri contactData = data.getData();
Cursor cursor = managedQuery(contactData, null, null, null, null);
if (cursor.moveToFirst()) {
String id =cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
String hasPhone =cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone.equalsIgnoreCase("1")) {
Cursor phones = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,
null, null);
phones.moveToFirst();
cNumber = phones.getString(phones.getColumnIndex("data_1"));
System.out.println("number is:"+cNumber);
}
String name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
}
}
break;
}
}
联系人的名字是
DISPLAY_name
,而不是contact_ID
String hasPhone=cursor.getString(cursor.getColumnIndex(Contacts contract.Contacts.HAS_PHONE_NUMBER));抛出错误这是因为,在您的情况下,它是'Number'而不是'HAS_PHONE_Number',所以您应该做一些小的更改以符合您的要求。好的,等我测试一下,没有Contacts contract.Contacts.Number这样的东西
static final int PICK_CONTACT_=1;
Intent intent_1 = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent_1, PICK_CONTACT_);
@Override
public void onActivityResult(int reqCode, int resultCode, Intent data) {
super.onActivityResult(reqCode, resultCode, data);
switch (reqCode) {
case (PICK_CONTACT_) :
if (resultCode == Activity.RESULT_OK) {
Uri contactData = data.getData();
Cursor cursor = managedQuery(contactData, null, null, null, null);
if (cursor.moveToFirst()) {
String id =cursor.getString(cursor.getColumnIndexOrThrow(ContactsContract.Contacts._ID));
String hasPhone =cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));
if (hasPhone.equalsIgnoreCase("1")) {
Cursor phones = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id,
null, null);
phones.moveToFirst();
cNumber = phones.getString(phones.getColumnIndex("data_1"));
System.out.println("number is:"+cNumber);
}
String name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
}
}
break;
}
}
Uri uri = data.getData();
Cursor cursor = getContentResolver().query(uri, null, null, null, null);
cursor.moveToFirst();
name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
cursor.moveToFirst();
number = cursor.getString(cursor.getColumnIndex(Phone.NUMBER));