Java 为复杂对象生成JSON消息
我启动了一个企业应用程序,其中web/mobile、android和ios是客户端。因此,我决定使用Jersey实现RESTFull资源,并使用SpringIO注入服务。但我主要被困在两个地方Java 为复杂对象生成JSON消息,java,json,spring,rest,jersey,Java,Json,Spring,Rest,Jersey,我启动了一个企业应用程序,其中web/mobile、android和ios是客户端。因此,我决定使用Jersey实现RESTFull资源,并使用SpringIO注入服务。但我主要被困在两个地方 1. To Use DI with Spring. -- If I use jersey 2.7, it can able to produce json. Here I can not use Spring DI. 2. Produce response for complex o
1. To Use DI with Spring. -- If I use jersey 2.7, it can able to produce
json. Here I can not use Spring DI.
2. Produce response for complex objects.-- If I use Jerse-Spring 1.8,
My Objects not converting as json.
非常感谢您的帮助 您可以使用带有gson库的HttpServlet来创建REST服务。请参见下面的简单示例
您可以使用带有gson库的HttpServlet来创建REST服务。请参见下面的简单示例
package com.nl.services.ws.sincronizacao;
import java.io.IOException;
import java.io.PrintWriter;
import javax.ejb.EJB;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.gson.Gson;
@WebServlet(value = "/TestGsonHttp")
public class TestGsonHttp extends HttpServlet{
@EJB
private yourEjbClass;
@Override
protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
// Your Entity
Client c = yourEjbClass.getClientById(1);
Gson g = new Gson();
String jsonResult = g.toJson(c);
PrintWriter writer = resp.getWriter();
writer.print(jsonResult);;
writer.flush();
writer.close();
}
}