Java-can'；t执行1-7系列中的最后一个if语句

“selection”变量用于调用不同的方法和执行不同的代码块。除了我想退出程序（即选择==7）外，其他一切都正常。有人知道这是为什么吗

public class HW5Main {

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);
    boolean breakRequest = false;

    while(breakRequest == false){
    System.out.println("\nWelcome to JVHS, what would you like to do?");
    System.out.println("1. Admit a new dog (description unknown)");
    System.out.println("2. Admit a new dog (description known)");
    System.out.println("3. Display information about a particular dog");
    System.out.println("4. Adopt a dog");
    System.out.println("5. Euthanize a dog");
    System.out.println("6. Display information about the JVHS");
    System.out.println("7. Exit");
    int selection = scanner.nextInt();
    System.out.println("\nYour selection is "+ selection);

    HW5Dog dogObject = new HW5Dog();

    if(selection == 1)
        dogObject.addDog();

    if(selection == 2)
        dogObject.addDog2();

    if(selection == 3){
        dogObject.getAllDogs();
        //Ask which Dog you want and get its info
        System.out.println("Please enter the ID number of the dog you wish to display:");
        if(scanner.hasNextInt()){
            int dogID = scanner.nextInt();
            dogObject.getDog(dogID);    
        }
        else
            System.out.println("ERROR - INVALID INPUT: EXPECTING INTERGER, TRY AGAIN");
    }

    if(selection == 4){
        dogObject.getAllDogs();
        //Ask which Dog you want and get its info
        System.out.println("Please enter the ID number of the dog you wish to adopt:");
        if(scanner.hasNextInt()){
            int dogID = scanner.nextInt();
            dogObject.adopt(dogID);
        }
    }

    if(selection == 5){
        dogObject.getAllDogs();
        //Ask which Dog you want and get its info
        System.out.println("Please enter the ID number of the dog you wish to euthanize:");
        if(scanner.hasNextInt()){
            int dogID = scanner.nextInt();
            dogObject.euth(dogID);
    }

    if(selection == 6){
        dogObject.getJVHS();
    }

    if(selection == 7){
        System.out.println("Goodbye");
        scanner.close();
        breakRequest = true;
    }

    }
        }
    }
}

---

问题在上面的选择框中：

if(selection == 5){
    dogObject.getAllDogs();
    //Ask which Dog you want and get its info
    System.out.println("Please enter the ID number of the dog you wish to euthanize:");
    if(scanner.hasNextInt()){
        int dogID = scanner.nextInt();
        dogObject.euth(dogID);
}

不关闭第二条

if

语句上的大括号。它应该是这样的：

if(selection == 5){
    dogObject.getAllDogs();
    //Ask which Dog you want and get its info
    System.out.println("Please enter the ID number of the dog you wish to euthanize:");
    if(scanner.hasNextInt()) {
        int dogID = scanner.nextInt();
        dogObject.euth(dogID);
    }
}

---

正如一些评论中提到的，您应该坚持使用清晰一致的缩进样式，以便将来更容易发现此问题。

问题在上面的选择框中：

if(selection == 5){
    dogObject.getAllDogs();
    //Ask which Dog you want and get its info
    System.out.println("Please enter the ID number of the dog you wish to euthanize:");
    if(scanner.hasNextInt()){
        int dogID = scanner.nextInt();
        dogObject.euth(dogID);
}

不关闭第二条

if

语句上的大括号。它应该是这样的：

if(selection == 5){
    dogObject.getAllDogs();
    //Ask which Dog you want and get its info
    System.out.println("Please enter the ID number of the dog you wish to euthanize:");
    if(scanner.hasNextInt()) {
        int dogID = scanner.nextInt();
        dogObject.euth(dogID);
    }
}

---

正如一些评论中提到的，您应该坚持使用清晰一致的缩进样式，以便将来更容易发现此问题。

什么不起作用？它怎么不起作用？你期望它做什么？取而代之的是什么呢？看看选择5和下面的{}。正确的缩进是奇迹…什么不起作用？它怎么不起作用？你期望它做什么？取而代之的是什么呢？看看选择5和下面的{}。正确的缩进是奇迹…这就是为什么你总是修正缩进。不仅修正标识，而且在控制语句中使用括号…我不知道你使用哪个IDE，但我建议启用一些文件保存操作，如组织导入和格式化文件，这就是为什么您总是修复缩进。不仅修复标识，而且在控制语句中使用括号…我不知道您使用哪个IDE，但我建议启用一些文件保存操作，如组织导入和格式化文件