声音不会从jar播放,但只有在我从NetBeans运行它时才会播放。(Javazoom播放器)

声音不会从jar播放,但只有在我从NetBeans运行它时才会播放。(Javazoom播放器),java,jar,netbeans-8,Java,Jar,Netbeans 8,我已经下载并导入了JLayer 1.0.1 () 使用这段代码,如果我从NetBeans运行它,我可以播放声音 package window; import java.io.BufferedInputStream; import java.io.FileInputStream; import java.io.InputStream; import java.io.IOException; import javazoom.jl.decoder.JavaLayerException; import

我已经下载并导入了JLayer 1.0.1 ()

使用这段代码,如果我从NetBeans运行它,我可以播放声音

package window;

import java.io.BufferedInputStream;
import java.io.FileInputStream;
import java.io.InputStream;
import java.io.IOException;
import javazoom.jl.decoder.JavaLayerException;
import javazoom.jl.player.AudioDevice;
import javazoom.jl.player.FactoryRegistry;
import javazoom.jl.player.advanced.AdvancedPlayer;

/**
 * Provide basic playing of MP3 files via the javazoom library.
 * See http://www.javazoom.net/
 * 
 * @author David J. Barnes and Michael Kölling
 * @version 2011.07.31
 */
public class MusicPlayer
{
    // The current player. It might be null.
    private AdvancedPlayer player;

    /**
     * Constructor for objects of class MusicFilePlayer
     */
    public MusicPlayer()
    {
        player = null;
    }

    /**
     * Play a part of the given file.
     * The method returns once it has finished playing.
     * @param filename The file to be played.
     */
    public void playSample(String filename)
    {
        try {
            setupPlayer(filename);
            player.play(500);
        }
        catch(JavaLayerException e) {
            reportProblem(filename);
        }
        finally {
            killPlayer();
        }
    }    

    /**
     * Start playing the given audio file.
     * The method returns once the playing has been started.
     * @param filename The file to be played.
     */
    public void startPlaying(final String filename)
    {
        try {
            setupPlayer(filename);
            Thread playerThread = new Thread() {
                public void run()
                {
                    try {
                        player.play(5000);
                    }
                    catch(JavaLayerException e) {
                        reportProblem(filename);
                    }
                    finally {
                        killPlayer();
                    }
                }
            };
            playerThread.start();
        }
        catch (Exception ex) {
            reportProblem(filename);
        }
    }

    public void stop()
    {
        killPlayer();
    }

    /**
     * Set up the player ready to play the given file.
     * @param filename The name of the file to play.
     */
    private void setupPlayer(String filename)
    {
        try {
            InputStream is = getInputStream(filename);
            player = new AdvancedPlayer(is, createAudioDevice());
        }
        catch (IOException e) {
            reportProblem(filename);
            killPlayer();
        }
        catch(JavaLayerException e) {
            reportProblem(filename);
            killPlayer();
        }
    }

    /**
     * Return an InputStream for the given file.
     * @param filename The file to be opened.
     * @throws IOException If the file cannot be opened.
     * @return An input stream for the file.
     */
    private InputStream getInputStream(String filename)
        throws IOException
    {
        return new BufferedInputStream(
                    new FileInputStream(filename));
    }

    /**
     * Create an audio device.
     * @throws JavaLayerException if the device cannot be created.
     * @return An audio device.
     */
    private AudioDevice createAudioDevice()
        throws JavaLayerException
    {
        return FactoryRegistry.systemRegistry().createAudioDevice();
    }

    /**
     * Terminate the player, if there is one.
     */
    private void killPlayer()
    {
        synchronized(this) {
            if(player != null) {
                player.stop();
                player = null;
            }
        }
    }

    /**
     * Report a problem playing the given file.
     * @param filename The file being played.
     */
    private void reportProblem(String filename)
    {
        System.out.println("There was a problem playing: " + filename);
    }

}
我可以从另一个类中这样称呼它

private MusicPlayer player = new MusicPlayer();
player.startPlaying("src/audio/SuperheroKeygen.mp3"); 
音频文件也将导入到项目中

但是如果我运行.jar,我就没有音频了

如果我用Winrar打开.jar文件,我会立即得到一个包含mp3的文件夹audio,因此mp3包含在.jar中

从命令行运行jar给了我

播放时出现问题:src/audio/SuperheroKeygen.mp3
线程“thread-2”java.lang.NullPointerException中的异常
在window.MusicPlayer$1.run(MusicPlayer.java:64)


p.S Java新手

jar文件可能不是玩家可以访问的文件路径。你可以做几件事。您可能需要将文件复制到本地磁盘,如下所示:

Path soundPath = Files.createTempFile("SuperheroKeygen", ".mp3");
try (InputStream jarSound= getClass().getResourceAsStream("/src/audio/SuperheroKeygen.mp3")){
    Files.copy(jarSound, soundPath, StandardCopyOption.REPLACE_EXISTING);        
} catch (IOException e){
    //handle the exception
}
然后
soundPath
包含可以传递给播放机的声音文件的路径

您可能只需要更改它,以便在
getInputStream
方法中,只需使用
getClass().getResourceAsStream()
来获取
InputStream
,而不是创建新的
FileInputStream
。如果这样做,则必须以
/
开始资源路径,以便它从根目录开始,而不是从当前包目录开始:

private InputStream getInputStream(String filename) throws IOException {
    return new BufferedInputStream(getClass().getResourceAsStream(filename));
}
您可以使用类加载器将所有文件名作为绝对路径读取,这样就不需要像这样的前导
/

private InputStream getInputStream(String filename) throws IOException {
    return new BufferedInputStream(getClass().getClassLoader().getResourceAsStream(filename));
} 

jar文件可能不是玩家可以访问的文件路径。你可以做几件事。您可能需要将文件复制到本地磁盘,如下所示:

Path soundPath = Files.createTempFile("SuperheroKeygen", ".mp3");
try (InputStream jarSound= getClass().getResourceAsStream("/src/audio/SuperheroKeygen.mp3")){
    Files.copy(jarSound, soundPath, StandardCopyOption.REPLACE_EXISTING);        
} catch (IOException e){
    //handle the exception
}
然后
soundPath
包含可以传递给播放机的声音文件的路径

您可能只需要更改它,以便在
getInputStream
方法中,只需使用
getClass().getResourceAsStream()
来获取
InputStream
,而不是创建新的
FileInputStream
。如果这样做,则必须以
/
开始资源路径,以便它从根目录开始,而不是从当前包目录开始:

private InputStream getInputStream(String filename) throws IOException {
    return new BufferedInputStream(getClass().getResourceAsStream(filename));
}
您可以使用类加载器将所有文件名作为绝对路径读取,这样就不需要像这样的前导
/

private InputStream getInputStream(String filename) throws IOException {
    return new BufferedInputStream(getClass().getClassLoader().getResourceAsStream(filename));
} 

我假设您的JAR旁边没有一个名为src的文件夹,其中包含一个名为audio的文件夹,其中包含一个名为SuperheroKeygen.mp3的文件,因为您的程序正在查找声音文件.player.startPlaying(“SuperheroKeygen.mp3”);删除url路径,只需给它一个文件名,这个文件应该在您试图运行jar文件的同一目录中。这样你就会知道问题所在。路径问题或elseI假设您的JAR旁边没有一个名为src的文件夹,其中包含一个名为audio的文件夹,其中包含一个名为SuperheroKeygen.mp3的文件,因为您的程序正在查找声音文件.player.startPlaying(“SuperheroKeygen.mp3”);删除url路径,只需给它一个文件名,这个文件应该在您试图运行jar文件的同一目录中。这样你就会知道问题所在。路径问题或其他