Java 如何使用JAX-RS捕获WebApplicationException
我试图用我的Java 如何使用JAX-RS捕获WebApplicationException,java,jersey,jax-rs,jersey-2.0,jersey-client,Java,Jersey,Jax Rs,Jersey 2.0,Jersey Client,我试图用我的javax.ws.rs.ext.ExceptionMapper类捕获WebApplicationException,但我得到了一个奇怪的行为 这是我的简单休息方法: @GET @Path("/saySomething") public List<String> saySomething() { String response = EchoRestClient.ping(); List<String> list = new ArrayList&l
javax.ws.rs.ext.ExceptionMapper
类捕获WebApplicationException
,但我得到了一个奇怪的行为
这是我的简单休息方法:
@GET
@Path("/saySomething")
public List<String> saySomething() {
String response = EchoRestClient.ping();
List<String> list = new ArrayList<>();
list.add(response);
list.add("okay");
return list;
}
public class EchoRestClient {
private static Client client = ClientBuilder.newClient();
public static String ping() {
String serviceUrl = PropertyReader.getProperty(ServiceUrl.ECHO_SERVICE);
Response response = client
.target(serviceUrl)
.path("saySomething")
.request(ExtendedMediaType.APPLICATION_UTF8)
.get();
if (response.getStatus() == Response.Status.OK.getStatusCode()) {
return response.getEntity(String.class);
}
throw new WebApplicationException(response);
}
}
@Provider
public class WebservletExceptionMapper implements ExceptionMapper<Exception> {
@Override
public Response toResponse(Exception exception) {
System.out.println("caught exception");
Response response;
if (exception instanceof WebApplicationException) {
response = ((WebApplicationException) exception).getResponse();
} else {
response = Response....build();
}
return response;
}
}
和我的自定义异常处理程序,它不会捕获上述抛出的异常:
@GET
@Path("/saySomething")
public List<String> saySomething() {
String response = EchoRestClient.ping();
List<String> list = new ArrayList<>();
list.add(response);
list.add("okay");
return list;
}
public class EchoRestClient {
private static Client client = ClientBuilder.newClient();
public static String ping() {
String serviceUrl = PropertyReader.getProperty(ServiceUrl.ECHO_SERVICE);
Response response = client
.target(serviceUrl)
.path("saySomething")
.request(ExtendedMediaType.APPLICATION_UTF8)
.get();
if (response.getStatus() == Response.Status.OK.getStatusCode()) {
return response.getEntity(String.class);
}
throw new WebApplicationException(response);
}
}
@Provider
public class WebservletExceptionMapper implements ExceptionMapper<Exception> {
@Override
public Response toResponse(Exception exception) {
System.out.println("caught exception");
Response response;
if (exception instanceof WebApplicationException) {
response = ((WebApplicationException) exception).getResponse();
} else {
response = Response....build();
}
return response;
}
}
我上面的代码工作正常,当我从web浏览器调用saySomething
rest方法时,我得到了正确的响应
但是,如果我取消部署EchoService
rest(包含调用的ping
rest方法),则在第一种情况下不会捕获HTTP 404。我需要抛出RuntimeException,因为WebApplicationException未被捕获(第二种情况)
根据文档,异常层次结构是WebApplicationException extends RuntimeException
这里怎么了
--编辑--
如果我抛出这个异常,那么它就被捕获了:抛出新的WebApplicationException(response.getStatus())
但这一个不起作用:抛出新的WebApplicationException(response)
响应对象中是否有问题?这是由Jersey中的问题引起的。如果代码抛出包含响应对象的WebApplicationException,则不会调用ExceptionAppers 另见:
- 这是由泽西岛的一个问题引起的。如果代码抛出包含响应对象的WebApplicationException,则不会调用ExceptionAppers
另见: