在httpget上将mysql参数从java发送到php

在httpget上将mysql参数从java发送到php,java,php,android,eclipse,Java,Php,Android,Eclipse,这是android应用程序的一部分。。。当我指定mysql_查询时,php脚本可以正常工作,而不使用。$\u POST['varname']。要使用用户可定义的不同参数向应用程序添加搜索功能,我正在尝试使用调用httpget时从应用程序传递的值在PHP脚本中构建查询。。。php脚本的行如下所示: $result = mysql_query("SELECT * FROM businessdata WHERE '" . $_POST['varQuery2']."' = '" .

这是android应用程序的一部分。。。当我指定mysql_查询时,php脚本可以正常工作,而不使用。$\u POST['varname']。要使用用户可定义的不同参数向应用程序添加搜索功能,我正在尝试使用调用httpget时从应用程序传递的值在PHP脚本中构建查询。。。php脚本的行如下所示:

$result = mysql_query("SELECT * FROM businessdata WHERE '"
    . $_POST['varQuery2']."' =  '" 
    . $_POST['varQuery1']"'") 
    or die(mysql_error());
然后方法如下所示:(为了完整性,在调用该方法时,这里为该方法指定了字符串值“GET”)

公共JSONObject makeHttpRequest(字符串url、字符串方法、, 列表参数、字符串值、字符串值2){ //发出HTTP请求 试一试{ //检查请求方法 如果(方法==“POST”){ //请求方法为POST //defaultHttpClient DefaultHttpClient httpClient=新的DefaultHttpClient(); 添加参数(新的BasicNameValuePair(“varQuery2”,值)); 添加参数(新的BasicNameValuePair(“varQuery1”,value2)); HttpPost HttpPost=新的HttpPost(url); setEntity(新的UrlEncodedFormEntity(参数)); HttpResponse HttpResponse=httpClient.execute(httpPost); HttpEntity HttpEntity=httpResponse.getEntity(); is=httpEntity.getContent(); }else if(方法==“GET”){ //请求方法是GET DefaultHttpClient httpClient=新的DefaultHttpClient(); 添加参数(新的BasicNameValuePair(“varQuery2”,值)); 添加参数(新的BasicNameValuePair(“varQuery1”,value2)); String paramString=URLEncodedUtils.format(params,“UTF-8”); url+=“?”+参数字符串; HttpGet HttpGet=新的HttpGet(url); HttpResponse HttpResponse=httpClient.execute(httpGet); HttpEntity HttpEntity=httpResponse.getEntity(); is=httpEntity.getContent(); } }捕获(不支持的编码异常e){ e、 printStackTrace(); }捕获(客户端协议例外e){ e、 printStackTrace(); }捕获(IOE异常){ e、 printStackTrace(); } 试一试{ BufferedReader reader=新的BufferedReader(新的InputStreamReader( is,“iso-8859-1”),8); StringBuilder sb=新的StringBuilder(); 字符串行=null; 而((line=reader.readLine())!=null){ sb.追加(第+行“\n”); } is.close(); json=sb.toString(); }捕获(例外e){ Log.e(“缓冲区错误”,“错误转换结果”+e.toString()); } //尝试将字符串解析为JSON对象 试一试{ jObj=新的JSONObject(json); }捕获(JSONException e){ Log.e(“JSON解析器”,“错误解析数据”+e.toString()); } //返回JSON字符串 返回jObj; }
使用*\u real\u escape\u字符串处理sql注入。

行字符串paramString=URLEncodedUtils.format(params,“UTF-8”);在你添加参数后再来?不知道,但听起来很合理。。。让我看看会发生什么…我将在尝试后用当前代码更新帖子…您的PHP代码和问题涉及HTTPPost,但您正在HTTPClient中执行HTTPGet。代码中似乎存在断开连接。已更改发布的代码以反映此情况。。。但它的失败在于“意外停止”。。。我曾尝试使用断点查看变量中的数据,但eclipse不注意我设置的任何断点,无论我将它们放在何处
    public JSONObject makeHttpRequest(String url, String method,
        List<NameValuePair> params, String value, String value2) {

    // Making HTTP request
    try {

        // check for request method
        if(method == "POST"){
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
           params.add(new BasicNameValuePair("varQuery2", value));
           params.add(new BasicNameValuePair("varQuery1", value2)); 
           HttpPost httpPost = new HttpPost(url);
            httpPost.setEntity(new UrlEncodedFormEntity(params));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }else if(method == "GET"){
            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient();

            params.add(new BasicNameValuePair("varQuery2", value));
            params.add(new BasicNameValuePair("varQuery1", value2)); 
            String paramString = URLEncodedUtils.format(params, "UTF-8");
            url += "?" + paramString;
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();
        }           

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {
        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

}
$result = mysql_query("SELECT * FROM businessdata WHERE '"
    . mysql_real_escape_string($_REQUEST['varQuery2'])."' =  '" 
    . mysql_real_escape_string($_REQUEST['varQuery1'])."'") 
    or die(mysql_error());