Java 如何通过curlopostman测试Spring引导一对多jpapost请求_Java_Json_Spring Boot_Postman

Java 如何通过curlopostman测试Spring引导一对多jpapost请求

java json spring-boot postman

Java 如何通过curlopostman测试Spring引导一对多jpapost请求,java,json,spring-boot,postman,Java,Json,Spring Boot,Postman,在我的spring boot应用程序中，我有以下型号：- @Entity @Table(name = "STUDENT") public class Student { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; @Column private String name; @Column private int mo

在我的spring boot应用程序中，我有以下型号：-

@Entity
@Table(name = "STUDENT")
public class Student {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column
    private String name;

    @Column
    private int mobile;

    public Student() {

    }

    @JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
    @ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    @JoinColumn(name = "DEPT_ID", nullable = false)
    private Department department;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getMobile() {
        return mobile;
    }

    public void setMobile(int mobile) {
        this.mobile = mobile;
    }

    public Department getDepartment() {
        return department;
    }

    public void setDepartment(Department department) {
        this.department = department;
    }

    @Override
    public String toString() {
        return "Student{" +
                "id=" + id +
                ", name='" + name + '\'' +
                ", mobile=" + mobile +
                ", department=" + department +
                '}';
    }
}

    @Entity
@Table(name = "DEPARTMENT")
@JsonIdentityInfo(
        generator = ObjectIdGenerators.PropertyGenerator.class,
        property = "id")
public class Department {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column
    private String name;

    public Department() {

    }

    @JsonIgnoreProperties({"hibernateLazyInitializer", "handler"})
    @OneToMany(mappedBy = "department", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    private List<Student> studentList = new ArrayList<>();

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<Student> getStudentList() {
        return studentList;
    }

    public void setStudentList(List<Student> studentList) {
        this.studentList = studentList;
    }
}


@RestController
public class StudentController {

    @Autowired
    StudentService studentService;

    @Autowired
    DepartmentService departmentService;

    @RequestMapping(value = "/studentList", method = RequestMethod.GET)
    public @ResponseBody
    List<Student> getStudents(){
        return studentService.getStudents();
    }

    @PostMapping("/saveStudent/{deptName}")
    public String saveStudent(@RequestBody List<Student> studentList, @PathVariable String deptName){
        try {
            Department dept = departmentService.findDepartment(deptName.toUpperCase());

            for(Student student: studentList)
                student.setDepartment(dept);

            studentService.saveStudent(studentList);
            return "Student saved successfully..";
        }catch (Exception ex){
            ex.printStackTrace();
            return "Error in saving Student ..";
        }
    }
}

我得到了以下错误：-

决心[org.springframework.http.converter.httpMessageNodeTableException:JSON解析错误：无法反序列化

java.util.ArrayList

out-START\u对象标记的实例；嵌套异常为com.fasterxml.jackson.databind.exc.MismatchedInputException:无法反序列化

java.util.ArrayList

out-START\u对象标记的实例在[源：（PushbackInputStream）；行：1，列：1]]

邮差控制台日志：-

POST http://localhost:8080 /saveStudent/hr
400
183 ms
Network
Request Headers
Content-Type: application/json
User-Agent: PostmanRuntime/7.26.1
Accept: */*
Cache-Control: no-cache
Postman-Token: 57071c5d-e416-4b54-870a-9f318fee7166
Host: localhost:8080 
Accept-Encoding: gzip, deflate, br
Connection: keep-alive
Content-Length: 160
Request Body
Response Headers
Content-Type: application/json
Transfer-Encoding: chunked
Date: Wed, 15 Jul 2020 09:05:43 GMT
Connection: close
Response Body
{"timestamp":"2020-07-15T09:05:43.864+00:00","status":400,"error":"Bad Request","message":"","path":"/saveStudent/hr"}

我认为我的应用程序工作正常。如何通过邮递员或CURL发出正确的JSON请求？

你不应该在帖子正文中添加

学生

使用如下

 [
  {
    "name": "masi",
    "mobile": 12345,
    "department": {
      "field":"value"
    }
  },
  {
    "name": "masi2",
    "mobile": 1234500,
     "department": {
      "field":"value"
    }
  }
]

我不知道系课的字段，请进行相应编辑

您不应在帖子正文中添加学生使用如下

 [
  {
    "name": "masi",
    "mobile": 12345,
    "department": {
      "field":"value"
    }
  },
  {
    "name": "masi2",
    "mobile": 1234500,
     "department": {
      "field":"value"
    }
  }
]

我不知道部门类的字段，请进行相应编辑

你能分享你的控制器代码吗，我想看看你是如何接受帖子正文的？我的问题中有StudentController。我想测试

@PostMapping（“/saveStudent/{deptName}”）公共字符串saveStudent（@RequestBody List studentList，@PathVariable String deptName）{

controller。另外，我添加了邮递员控制台日志。你能分享你的控制器代码吗，我想看看你是如何使用它来接受邮件正文的？我的问题中有StudentController。我想测试

@PostMapping（/saveStudent/{deptName}）公共字符串saveStudent（@RequestBody List studentList，@PathVariable String deptName）{

controller。此外，我还添加了邮递员控制台日志。当我尝试此操作时，我发现此错误：-已解决[org.springframework.http.converter.httpMessageNodeTableException:JSON解析错误：无法从字符串“hr”反序列化类型

java.lang.Long

的值：不是有效的长值；嵌套异常是com.fasterxml.jackson.databind.exc.InvalidFormatException:无法从字符串“hr”反序列化类型

java.lang.Long

的值：在[Source:（PushbackInputStream）；行：5，列：19]（通过引用链：java.util.ArrayList[0]->com.example.onetomany.model.Student[“department”]）处不是有效的长值，在上述错误之后：-我厌倦了这个

[{“name”：“masi”，“mobile”：12345，“department”：“1”}，{“name”：“masi2”，“mobile”：1234500，“部门”：“1”}]

然后出现错误：.w.s.m.s.DefaultHandlerExceptionResolver:已解决[org.springframework.http.converter.httpMessageNodeTableException:JSON解析错误：未解析的正向引用：；嵌套异常为com.fasterxml.jackson.databind.desr.unsolvedForwardReference:未解析的正向引用：位于[Source:（PushbackInputStream）；第12行，第1列]对象id[1]（对于

com.example.onetomany.model.Department

）位于[Source:（PushbackInputStream）；行：5，列：22]，对象id[1]（对于

com.example.onetomany.model.Department

）位于[Source:（PushbackInputStream）；department是一个对象，就像我为学生所做的那样，您需要对department进行同样的操作。我更新了答案，请立即检查，并在我尝试此操作时编辑side department中的字段值。我发现此错误：-已解决[org.springframework.http.converter.httpMessageNodeTableException:JSON解析错误：无法从字符串“hr”反序列化类型

java.lang.Long

的值：不是有效的长值；嵌套异常是com.fasterxml.jackson.databind.exc.InvalidFormatException:无法从字符串“hr”反序列化类型

java.lang.Long

[{“name”：“masi”，“mobile”：12345，“department”：“1”}，{“name”：“masi2”，“mobile”：1234500，“部门”：“1”}]

com.example.onetomany.model.Department

）位于[Source:（PushbackInputStream）；行：5，列：22]，对象id[1]（对于

com.example.onetomany.model.Department

）位于[Source:（PushbackInputStream）；部门是一个对象，就像我为学生所做的一样，你也需要这样做。我更新了答案，请现在检查并编辑部门中的字段值