如何使用xpath dom java获取子节点的节点列表？

如何获取子节点的节点列表，即我需要获取“b”的子节点（节点列表有3个“c”节点）

您可以使用

DocumentBuilderFactory dBFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dB = dBFactory.newDocumentBuilder();
Document doc = dB.parse(url);     
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());

对DOM执行同样的操作将变得非常冗长：

// This will find all "c" elements, and then return all children thereof
$(doc).find("c").children();

// This will return "d", "f", "d", "f", "d", "f":
List<String> tags = $(doc).find("c").children().tags();

// This will return "1", "2", "2, "2", "v", "d":
List<String> texts = $(doc).find("c").children().texts();

你可以使用它，然后再写

DocumentBuilderFactory dBFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dB = dBFactory.newDocumentBuilder();
Document doc = dB.parse(url);     
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());

对DOM执行同样的操作将变得非常冗长：

// This will find all "c" elements, and then return all children thereof
$(doc).find("c").children();

// This will return "d", "f", "d", "f", "d", "f":
List<String> tags = $(doc).find("c").children().tags();

// This will return "1", "2", "2, "2", "v", "d":
List<String> texts = $(doc).find("c").children().texts();

---

下面是一个使用XPath的示例

XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expression = xpath.compile("//c/*");
NodeList nodes = (NodeList) expression.evaluate(
  document.getDocumentElement(), XPathConstants.NODESET);

---

下面是一个使用XPath的示例

XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expression = xpath.compile("//c/*");
NodeList nodes = (NodeList) expression.evaluate(
  document.getDocumentElement(), XPathConstants.NODESET);

---

假设我想要“c”的子节点？抱歉，我有一个复杂的xml，我必须在其中获取子节点，grand child nodelist（child has child及其子nodelist）。。。代码有帮助，我可以说doc.getElementsByTagName（“c”）.item（0.getchildnode（）；感谢您的回复，但我只需要使用xpath。。。。我的代码已经完成70%。。由于时间所剩无几，我无法使用新方法..除了XPath标记，您的问题中没有任何内容表明。。。你能不能至少相应地更新你的问题？假设我想要“c”的子节点？抱歉，我有一个复杂的xml，我必须在其中获取子节点，grand child nodelist（child has child及其子nodelist）。。。代码有帮助，我可以说doc.getElementsByTagName（“c”）.item（0.getchildnode（）；感谢您的回复，但我只需要使用xpath。。。。我的代码已经完成70%。。由于时间所剩无几，我无法使用新方法..除了XPath标记，您的问题中没有任何内容表明。。。请你至少更新一下你的问题好吗

XPath xpath = XPathFactory.newInstance().newXPath();
XPathExpression expression = xpath.compile("//c/*");
NodeList nodes = (NodeList) expression.evaluate(
  document.getDocumentElement(), XPathConstants.NODESET);

String xmlSource = "<a>" +
                    "<b>" +
                        "<c type='lol'>" +
                            "<d>1</d>" +
                            "<f>2</f>" +
                        "</c>" +
                        "<c type='lol'>" +
                            "<d>2</d>" +
                            "<f>2</f>" +
                        "</c>" +
                        "<c type='h'>" +
                            "<d>v</d>" +
                            "<f>d</f>" +
                        "</c>" +
                    "</b>" +
                "</a>";

XPath xPath = XPathFactory.newInstance().newXPath(); 
String expression = "/a/b/c";   

InputSource inputSource = new InputSource(new StringReader(xmlSource));             
NodeList nodes = (NodeList) xPath.evaluate(expression, inputSource, XPathConstants.NODESET);

for(int i = 0; i < nodes.getLength(); i++) {
    System.out.println(nodes.item(i).getAttributes().getNamedItem("type").getNodeValue());    
}

import java.io.StringReader;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;