Java 从返回的openweathermap json数据访问rain
这是我的Java 从返回的openweathermap json数据访问rain,java,android,json,openweathermap,Java,Android,Json,Openweathermap,这是我的JSON { "city": { "id": 2961297, "name": "Swords", "coord": { "lon": -6.21806, "lat": 53.459721 }, "country": "IE", "population": 0 }, "cod": "200", "message": 0.3535, "cnt": 1, "list": [ {
JSON
{
"city": {
"id": 2961297,
"name": "Swords",
"coord": {
"lon": -6.21806,
"lat": 53.459721
},
"country": "IE",
"population": 0
},
"cod": "200",
"message": 0.3535,
"cnt": 1,
"list": [
{
"dt": 1481025600,
"temp": {
"day": 284.68,
"min": 284.68,
"max": 285.36,
"night": 285.36,
"eve": 284.8,
"morn": 284.68
},
"pressure": 1028.26,
"humidity": 95,
"weather": [
{
"id": 500,
"main": "Rain",
"description": "light rain",
"icon": "10d"
}
],
"speed": 9.01,
"deg": 186,
"clouds": 92,
"rain": 0.5
}
]
}
我正在尝试访问rain值“rain”:0.5,如上面返回的JSON
数据所示,我不确定如何准确地执行此操作,因为我没有太多处理JSON
数据的经验
这是我的密码
JSONObject topLevel = new JSONObject(builder.toString());
JSONArray ListArray = topLevel.getJSONArray("list");
weather = String.valueOf(ListArray);
for(int x = 0;x < ListArray.length();x++) {
JSONObject myObj = ListArray.getJSONObject(x);
myObj.getInt("rain");
Log.d("TODAYS Rain"+rain,"");
//System.out.Print("Current Weather" +id+main+icon+dscription+rain);
}
JSONObject topLevel=新的JSONObject(builder.toString());
JSONArray ListArray=topLevel.getJSONArray(“列表”);
weather=String.valueOf(ListArray);
对于(int x=0;x
非常感谢您的帮助。解析Json最简单的方法是使用POJO类将Json映射到对象实例中
JSONObject topLevel = new JSONObject(builder.toString());
JSONArray listArray = topLevel.getJSONArray("list");
JSONObject firstObject = (JSONObject)listArray.get(0);
Double rain = firstObject.getDouble("rain");
System.out.println("TODAYs rain :" + rain);
}
您定义了类结构,它将被检索到的数据填充
这个网站上有一个关于这个主题的指南:jsonobjecttoplevel=newjsonobject(builder.toString());
JSONArray ListArray=topLevel.getJSONArray(“列表”);
weather=String.valueOf(ListArray);
对于(int x=0;x
您只需要使用myobj.getDouble(“rain”)而不是myobj.getInt(“rain”),因为rain的值不是整数。现在您的日志中出现了什么?它返回了JSON数据中的所有内容,但在我尝试将rain添加到文本字段时告诉我rain不在那里,我已经修复了它,谢谢
JSONObject topLevel = new JSONObject(builder.toString());
JSONArray ListArray = topLevel.getJSONArray("list");
weather = String.valueOf(ListArray);
for(int x = 0;x < ListArray.length();x++) {
JSONObject myObj = ListArray.getJSONObject(x);
myObj.getDouble("rain");
Log.d("TODAYS Rain"+rain,"");
//System.out.Print("Current Weather" +id+main+icon+dscription+rain);
}