Java 将零与字符串串联
我试图将零附加到字符串中,使其成为32位数字。但输出不显示附加的零。为什么会这样Java 将零与字符串串联,java,string,Java,String,我试图将零附加到字符串中,使其成为32位数字。但输出不显示附加的零。为什么会这样 System.out.print("\nEnter the linear Address (32bit) :\t"); String linear_hex= sc.nextLine(); String linear_bin= Integer.toBinaryString(Integer.parseInt(linear_hex,16)); if(linear_bin.length()
System.out.print("\nEnter the linear Address (32bit) :\t");
String linear_hex= sc.nextLine();
String linear_bin= Integer.toBinaryString(Integer.parseInt(linear_hex,16));
if(linear_bin.length() != 32)
{
for(int i= linear_bin.length(); i<=32; i++)
linear_bin= 0+linear_bin;
}
我还尝试了
linear\u bin=“0”+linear\u bin代码>和“0”。混凝土(线性)代码>但输出仍然相同。您的代码对我来说很好:
System.out.print("\nEnter the linear Address (32bit) :\t");
Scanner sc = new Scanner(System.in);
String linear_hex= sc.nextLine();
String linear_bin= Integer.toBinaryString(Integer.parseInt(linear_hex,16));
if(linear_bin.length() != 32) {
// Should be i < 32 instead of i <= 32, else you end up with an extra 0
// Also consider using StringBuilder instead of String concatenation here
for(int i= linear_bin.length(); i < 32; i++)
linear_bin= 0+linear_bin;
}
System.out.println(linear_bin);
输出:
Enter the linear Address (32bit) : 12345678
Linear Address = 10010001101000101011001111000
00000000000100100011010001010110
但是,使用String.format()
方法可以更容易地实现这一点。删除if
块,并添加此打印语句:
System.out.println(String.format("%32s", linear_bin).replace(' ', '0'));
你的代码对我来说很好:
System.out.print("\nEnter the linear Address (32bit) :\t");
Scanner sc = new Scanner(System.in);
String linear_hex= sc.nextLine();
String linear_bin= Integer.toBinaryString(Integer.parseInt(linear_hex,16));
if(linear_bin.length() != 32) {
// Should be i < 32 instead of i <= 32, else you end up with an extra 0
// Also consider using StringBuilder instead of String concatenation here
for(int i= linear_bin.length(); i < 32; i++)
linear_bin= 0+linear_bin;
}
System.out.println(linear_bin);
输出:
Enter the linear Address (32bit) : 12345678
Linear Address = 10010001101000101011001111000
00000000000100100011010001010110
但是,使用String.format()
方法可以更容易地实现这一点。删除if
块,并添加此打印语句:
System.out.println(String.format("%32s", linear_bin).replace(' ', '0'));