Java 隐藏和显示警告
我有一个表面视图和一个建议,我画了这样的建议:Java 隐藏和显示警告,java,android,adview,Java,Android,Adview,我有一个表面视图和一个建议,我画了这样的建议: g=new GameView(this ); setContentView(R.layout.activity_game); RelativeLayout layout = (RelativeLayout)findViewById(R.id.vMain); layout.addView(g); mAdView = new AdView(this); mAdView.setAdSize(AdSize
g=new GameView(this );
setContentView(R.layout.activity_game);
RelativeLayout layout = (RelativeLayout)findViewById(R.id.vMain);
layout.addView(g);
mAdView = new AdView(this);
mAdView.setAdSize(AdSize.BANNER);
mAdView.setAdUnitId(myId);
AdRequest adRequest = new AdRequest.Builder()
.addTestDevice(AdRequest.DEVICE_ID_EMULATOR)
.build();
if(mAdView.getAdSize() != null || mAdView.getAdUnitId() != null)
mAdView.loadAd(adRequest);
((RelativeLayout)findViewById(R.id.vMain)).addView(mAdView );
mAdView.bringToFront();
mAdView.setVisibility(View.GONE);
在表面上查看并隐藏它。现在我想通过从surfaceview调用它来展示它,这可能吗?
我尝试创建此函数:
public void hide(){
mAdView.setVisibility(View.GONE);
}
public void show(){
mAdView.setVisibility(View.VISIBLE);
}
并从surfaceview调用它,但它给了我“只有创建视图的原始线程才能接触其视图。”异常。我该怎么办?我不知道从哪个线程调用这些方法,但所有UI更新都必须从主线程调用。使用:
runOnUiThread(new Runnable() {
@Override
public void run() {
// Update you UI here.
}
});
例如:
public void hide(){
runOnUiThread(new Runnable() {
@Override
public void run() {
mAdView.setVisibility(View.GONE);
}
});
}
public void show(){
runOnUiThread(new Runnable() {
@Override
public void run() {
mAdView.setVisibility(View.VISIBLE);
}
});
}
等等,它会调用set visible或者无限次,因为它是可运行的吗?不是。顺便说一句,可运行只是一个要执行的命令,通常在单独的线程中运行。它不是无限的。