java中的零计数
我不知道我哪里做错了。我想通过递归数零,但我没有得到:java中的零计数,java,Java,我不知道我哪里做错了。我想通过递归数零,但我没有得到: public class countzeroes { public static int countZerosRec(int input){ int count=0; return countZerosRec(input,count); } private static int countZerosRec(int input ,int count){ if (input<0)
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
公共类countzero{
公共静态整数countZerosRec(整数输入){
整数计数=0;
返回countZerosRec(输入,计数);
}
私有静态int countZerosRec(int输入,int计数){
如果(输入按以下方式更改方法。始终返回计数
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
private static int countZerosRec(int input ,int count){
if (input <= 0) { // check if input is negative or zero
return count;
}
int m = input % 10;
input = input / 10;
if (m == 0) {
count++; // increment if current digit is zero
}
return countZerosRec(input,count);
}
私有静态int countZerosRec(int输入,int计数){
如果(输入按以下方式更改方法。始终返回计数
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
private static int countZerosRec(int input ,int count){
if (input <= 0) { // check if input is negative or zero
return count;
}
int m = input % 10;
input = input / 10;
if (m == 0) {
count++; // increment if current digit is zero
}
return countZerosRec(input,count);
}
私有静态int countZerosRec(int输入,int计数){
如果(输入
这会管用的
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
这将起作用您的计数逻辑非常出色。
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
在下面的一行中…您犯了逻辑错误…请修复它
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
private static int countZerosRec(int input, int count) {
if (input < 0) {
return -1;
}
if (input == 0) {
return count;
//return 1; /// you need to change your code here, in last its getting zero as (num < 10 )/10 is 0
// its entering here everytime, and returning one.
// since its the base condition to exit the recursion.
// for special case of 0 (zero) count, handle your logic when it is //returned.
//...... rest of your code
}
私有静态int countZerosRec(int输入,int计数){
如果(输入<0){
返回-1;
}
如果(输入==0){
返回计数;
//返回1;///您需要在这里更改代码,最后它得到零,因为(num<10)/10是0
//它每次都进入这里,然后返回一个。
//因为它是退出递归的基本条件。
//对于0(零)计数的特殊情况,在//返回时处理逻辑。
//……代码的其余部分
}
您的计数逻辑非常出色。
在下面的一行中…您犯了逻辑错误…请修复它
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
private static int countZerosRec(int input, int count) {
if (input < 0) {
return -1;
}
if (input == 0) {
return count;
//return 1; /// you need to change your code here, in last its getting zero as (num < 10 )/10 is 0
// its entering here everytime, and returning one.
// since its the base condition to exit the recursion.
// for special case of 0 (zero) count, handle your logic when it is //returned.
//...... rest of your code
}
私有静态int countZerosRec(int输入,int计数){
如果(输入<0){
返回-1;
}
如果(输入==0){
返回计数;
//返回1;///您需要在这里更改代码,最后它得到零,因为(num<10)/10是0
//它每次都进入这里,然后返回一个。
//因为它是退出递归的基本条件。
//对于0(零)计数的特殊情况,在//返回时处理逻辑。
//……代码的其余部分
}
您可以使用流:
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
System.out.println("11020304".chars().filter(c -> c == '0').count());
结果:3您可以使用流:
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
System.out.println("11020304".chars().filter(c -> c == '0').count());
结果:3正确的方法是:
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
public class countzeroes {
private static int countZerosRec(int input){
if (input<0) {
return -1;
}
if (input==0) {
return 1;
}
if(input < 10) {
return 0;
}
int m = (input%10 == 0)? 1: 0;
input = input/10;
return m + countZerosRec(input);
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
公共类countzero{
私有静态int countZerosRec(int输入){
如果(输入正确的方法是:
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
public class countzeroes {
private static int countZerosRec(int input){
if (input<0) {
return -1;
}
if (input==0) {
return 1;
}
if(input < 10) {
return 0;
}
int m = (input%10 == 0)? 1: 0;
input = input/10;
return m + countZerosRec(input);
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
公共类countzero{
私有静态int countZerosRec(int输入){
if(input==0)语句中的if(inputPutreturncount
,而不是
countZerosRec(input,count);return count;
putreturn countZerosRec(input,count);
if(input==0)语句中的putreturn count
,而不是
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}
countZerosRec(输入,计数);return count;
putreturn countZerosRec(输入,计数);
样本编号的正确结果是什么?例如120100。正确答案是3吗?您忽略递归调用的结果countZerosRec(输入,计数)
@hamidghasemi它应该是3,但它是0@AndyTurner我应该如何解决这个问题?样本号的正确结果是什么?例如120100。正确答案是3吗?您忽略递归调用的结果countZerosRec(输入,计数)
@hamidghasemi它应该是3,但它是0@AndyTurner我应该如何修复这看起来不错,但是countZerosRec(0)
将返回0而不是1。@DodgyCodeException你是对的。让我更正一下。@DodgyCodeException我刚刚添加了另一个if
语句来检查零。这看起来不错,但是countZerosRec(0)
将返回0而不是1。@DodgyCodeException你说得对。让我更正一下。@DodgyCodeException我刚刚添加了另一个if
语句来检查零。
public class countzeroes {
public static int countZerosRec(int input){
int count=0;
return countZerosRec(input,count);
}
private static int countZerosRec(int input ,int count){
if (input<0) {
return -1;
}
if(input==0) {
return 1;
}
int m = input%10;
input = input/10;
if(m==0){
count++;
}
countZerosRec(input,count);
return count;
}
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
int n = s.nextInt();
System.out.println(countZerosRec(n));
}
}