Java 如果Bean构造函数有一个源对象的参数，那么如何编写XML配置？

基本的通知类

public class Notice {

   public Notice (Object source)
   {
      //some constructor initialization.
   }

}

通知类的特例

public class OfferNotice  extends Notice {

   public OfferNotice  (Object source)
   {
      super(source);
      //some constructor initialization.
   }

}

abstract public class GenericNoticeRecord <E extends Notice> 
{
        abstract public void recordNotice();     
}

class OfferNoticeRecord extends GenericNoticeRecord <OfferNotice> 
{

    private OfferNotice notice;

    public void setNotice(OfferNotice notice) {
        this.notice= notice;
    }

    public void recordNotice() {        
        // some implementation on Notice
    }


}

public class Mainservice {

    private OfferNoticeRecord offerNoticeRecord;

    public void send()
    {
       offerNoticeRecord.recordNotice();
    }
}

public class App {

   ApplicationContext context = new ClassPathXmlApplicationContext("spring.xml");
   serv = context.getBean("MainService");

   serv.send()

}

一般通知记录类

public class OfferNotice  extends Notice {

   public OfferNotice  (Object source)
   {
      super(source);
      //some constructor initialization.
   }

}

abstract public class GenericNoticeRecord <E extends Notice> 
{
        abstract public void recordNotice();     
}

class OfferNoticeRecord extends GenericNoticeRecord <OfferNotice> 
{

    private OfferNotice notice;

    public void setNotice(OfferNotice notice) {
        this.notice= notice;
    }

    public void recordNotice() {        
        // some implementation on Notice
    }


}

public class Mainservice {

    private OfferNoticeRecord offerNoticeRecord;

    public void send()
    {
       offerNoticeRecord.recordNotice();
    }
}

public class App {

   ApplicationContext context = new ClassPathXmlApplicationContext("spring.xml");
   serv = context.getBean("MainService");

   serv.send()

}

在应用程序中类

public class OfferNotice  extends Notice {

   public OfferNotice  (Object source)
   {
      super(source);
      //some constructor initialization.
   }

}

abstract public class GenericNoticeRecord <E extends Notice> 
{
        abstract public void recordNotice();     
}

class OfferNoticeRecord extends GenericNoticeRecord <OfferNotice> 
{

    private OfferNotice notice;

    public void setNotice(OfferNotice notice) {
        this.notice= notice;
    }

    public void recordNotice() {        
        // some implementation on Notice
    }


}

public class Mainservice {

    private OfferNoticeRecord offerNoticeRecord;

    public void send()
    {
       offerNoticeRecord.recordNotice();
    }
}

public class App {

   ApplicationContext context = new ClassPathXmlApplicationContext("spring.xml");
   serv = context.getBean("MainService");

   serv.send()

}

现在，如何通过XML为这个示例应用程序注入依赖关系？ 下面是我在XML配置中尝试的内容

<bean id="MainService" class="com.test.MainService">    
    <property name="offerNoticeRecord">
         <ref bean="OfferNoticeRecordBean"/>
    </property>
</bean>

<bean id="OfferNoticeRecordBean" class="com.test.OfferNoticeRecord">    
    <property name="notice">
        <ref bean="OfferNoticeBean"/>
    </property>
</bean>

<bean id="OfferNoticeBean" class="com.test.OfferNotice">    
    //here is major confusion, constructor is expecting source Object
</bean>

//这里是主要的混乱，构造函数需要源对象

那么，如果在代码中创建一个

OfferNotice

，您会传递什么？@SotiriosDelimanolis问题是如何在XML配置中传递对象引用。请检查此处：以及第3.3.1.3部分。一些例子。@LuiggiMendoza一旦我们知道我们想要通过什么，这就变得容易了。OP，

source

的意思是什么？@Sotiros实际上在程序中，它就像

OfferNotice=newoffernotice（这个）那么如何像这样添加依赖项呢