用Java实现继承类型接口

如何在界面中创建addWorker？OfficeWorker继承自Worker，现在我想为几个Worker创建接口。我不知道怎么做才对。void addWorker（Worker-Worker）和void addWorker（Worker-Worker）错误

接口

public interface TypeOfWorker {        
    void addWorker(Worker worker);
}

oficeworker

public class OfiiceWorker extends Worker implements TypeOfWorker {
    private int officeID;
    private int intelectl;
    private List<OfiiceWorker> ofiiceWorkers = new ArrayList<>();

    public OfiiceWorker(String name, String surname, int age, int experience, String street, int building,
            int local, String city, int officeID, int intelectl) {
        super(name, surname, age, experience, street, building, local, city);
        this.officeID = officeID;
        this.intelectl = intelectl;
    }

    @Override
    public void addWorker(OfiiceWorker ofiiceWorker) {
        ofiiceWorkers.add(ofiiceWorker);
    }
}

public abstract class Worker {
    private int identifier;
    private String name;
    private String surname;
    private int age;
    private int experience;
    private String street;
    private int building;
    private int local;
    private String city;

    public Worker() {
    }

    public Worker(String name, String surname, int age, int experience, String street, int building, int local,
            String city) {
        setIdentifier();
        this.name = name;
        this.surname = surname;
        this.age = age;
        this.experience = experience;
        this.street = street;
        this.building = building;
        this.local = local;
        this.city = city;
    }

    public void setIdentifier() {
        this.identifier = (int) (System.currentTimeMillis() / 1000);
    }
}

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您应该使用泛型让编译器轻松处理您的类型。首先，使您的界面通用：

public interface TypeOfWorker<T extends Worker> {
    void addWorker(T worker);
}

---

您应该使用泛型让编译器轻松处理您的类型。首先，使您的界面通用：

public interface TypeOfWorker<T extends Worker> {
    void addWorker(T worker);
}

---

也许你应该解释一下你想要用你的界面实现什么，否则它将很难帮助你。此外，您当前的解决方案看起来像一个糟糕的设计，OficeWorker的每个实例都将包含一个其他实例的列表。为什么你想要这个，这个列表不应该在另一个类中，而应该像某种工作者处理程序类一样。也许你应该解释一下你想用你的接口实现什么，否则它将很难帮助你。此外，您当前的解决方案看起来像一个糟糕的设计，OficeWorker的每个实例都将包含一个其他实例的列表。为什么您想要这个，这个列表不应该在另一个类中，而应该像某种工作者处理程序类一样。

@Override
public void addWorker(OfiiceWorke worker) {