Java SqlExceptionHelper:错误：语法错误（近似位置：“用户”）

我试图启动项目，但我得到了错误。请在下面找到我的密码

在日志中，我将此作为错误：

    2021-05-08 06:13:01.474  INFO 18080 --- [nio-8080-exec-2] c.e.demo.controller.UserController       : Handling save users: UserDto(id=null, name=test_name, surname=iva, login=test_login, password=1234567890, email=email@gmail.com)
    2021-05-08 06:13:01.529  WARN 18080 --- [nio-8080-exec-2] o.h.engine.jdbc.spi.SqlExceptionHelper   : SQL Error: 0, SQLState: 42601
    2021-05-08 06:13:01.529 ERROR 18080 --- [nio-8080-exec-2] o.h.engine.jdbc.spi.SqlExceptionHelper   : Error: syntax error (approximate position: "user")
      Position: 13
    2021-05-08 06:13:01.548 ERROR 18080 --- [nio-8080-exec-2] o.a.c.c.C.[.[.[/].[dispatcherServlet]    : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.InvalidDataAccessResourceUsageException: could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not execute statement] with root cause

我使用以下方法保存在控制器中：

@RestController
@RequestMapping("/users")
@Log
@AllArgsConstructor
@Data
public class UserController {

    private final UserService userService;

    @PostMapping("/save")
        public UserDto saveUsers(@RequestBody UserDto usersDto) throws ValidationException {
            log.info("Handling save users: " + usersDto);
            return userService.saveUser(usersDto);
        }

用户实体：

    @Entity
@Table(name = "user")
@Data
@NoArgsConstructo
@AllArgsConstructor
@Builder
public class User {

    @Id
    @SequenceGenerator(name = "user_id_seq", sequenceName = "user_id_seq", allocationSize = 1)
    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "user_id_seq")
    private Integer id;

    @Column(name = "name")
    private String name;

    @Column(name = "surname")
    private String surname;

    @Column(name = "login")
    private String login;

    @Column (name = "password")
    private String password;

    @Column (name = "email")
    private String email;

}

---

我的错误是什么？

用户

是Postgres中的保留字。试试别的名字。虽然一个体面的ORM应该引用它来避免人们可能会认为。。。