Java 当我的textInputLayout为空时如何设置错误

我正在对textInputLayout执行小数加法，问题是在调用isEmpty以显示字段为空时的错误时，此选项不会出现

我想这样做

 button.setOnClickListener {


            val numberOne = textInputLayout.editText?.text.toString().toDouble()
            val numberTwo = textInputLayout2.editText?.text.toString().toDouble()
            val reult = numberOne + numberTwo

            if (numberOne./*no appears isEmpty*/){
              textInputLayout.error = ("enter number")
            }else
                if (numberTwo./*no appears isEmpty*/){
                    textInputLayout2.error = ("enter number")
                }else {
                    textView.text = reult.toString()
                }
            
        }

xmlns

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数字一和数字二是双的 val numberOne=textInputLayout.editText？.text.toString.toDouble

isEmpty是一个字符串函数

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请尝试numberOne.toString.isEmpty，并且numberTwo也是相同的

numberOne和numberTwo是双精度的 val numberOne=textInputLayout.editText？.text.toString.toDouble

isEmpty是一个字符串函数

---

请尝试numberOne.toString.isEmpty，同样适用于numberTwo

您可以使用以下内容：

        <com.google.android.material.textfield.TextInputLayout>

            <com.google.android.material.textfield.TextInputEditText
                android:inputType="numberDecimal"
                .../>

---

您可以使用以下内容：

        <com.google.android.material.textfield.TextInputLayout>

            <com.google.android.material.textfield.TextInputEditText
                android:inputType="numberDecimal"
                .../>

---

好的，然后您可以尝试将num1、num2声明为字符串，并将结果转换为双精度值，如val numberOne=textInputLayout.editText？.text.toString val numberTwo=textInputLayout2.editText？.toString val reult=numberOne.toDouble+numberTwo.toDouble；好的，然后您可以尝试将num1、num2声明为字符串，并将结果转换为双精度值，如val numberOne=textInputLayout.editText？.text.toString val numberTwo=textInputLayout2.editText？.toString val reult=numberOne.toDouble+numberTwo.toDouble；准备好反映错误，但我不知道如何添加数字并显示结果只需在//Number is double中移动您的逻辑我这样做了：val double:double？=number1.editText？.text.toString.toDoubleOrNull double？.let{//Number is double….}？：number1.setErrorEnter Number val double 2:double？=number1.editText？.text.toString.toDoubleOrNull double2？.let{//Number is double….}？：number2.setErrorEnter Number我这样做是为了使错误出现在两个字段中，对不起，我是一个beginner@JorgeLeonardo以更简单的方式重写答案准备好反映错误，但我不知道如何添加数字并显示结果只需在//Number is double中移动您的逻辑我这样做了：val double:double？=number1.editText？.text.toString.toDoubleOrNull double？.let{//Number is double….}？：number1.setErrorEnter Number val double 2:double？=number1.editText？.text.toString.toDoubleOrNull double2？.let{//Number is double….}？：number2.setErrorEnter Number我这样做是为了在两个字段中都出现错误，对不起，我是beginner@JorgeLeonardo以更简单的方式改写了答案

val double: Double? = textInputLayout.editText?.text.toString().toDoubleOrNull()
val double2: Double? = textInputLayout2.editText?.text.toString().toDoubleOrNull()
    
if (double != null){
      //Double1 is a number
      textInputLayout.error = ""
      if (double2 != null){
         //Double2 is a number
          textInputLayout2.error = ""
          textview.text = (double+double2).toString()
       } else {
          //Double2 is not a number
          textInputLayout2.error = "Error"
           textview.text = ""
       }
 } else {
     //Double1 is not a number
     textInputLayout.error = "Error"
     textview.text = ""
 }