如何在java中正确格式化或合并两个直方图?

如何在java中正确格式化或合并两个直方图?,java,format,Java,Format,我有一个代码,可以打印出一些骰子的滚动直方图。我的问题是,我想在第二个柱状图旁边打印第一个柱状图,目前我的输出是这样的,但我想把星星放在滚动次数的右侧,如:2:3次///3:1次/等等 public static void main(String[] args) { // TODO code application logic here System.out.print("Please enter how many times to roll the dice:

我有一个代码,可以打印出一些骰子的滚动直方图。我的问题是,我想在第二个柱状图旁边打印第一个柱状图,目前我的输出是这样的,但我想把星星放在滚动次数的右侧,如:2:3次///3:1次/等等

        public static void main(String[] args) {
    // TODO code application logic here
    System.out.print("Please enter how many times to roll the dice: ");
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int [] rolls = new int[n];


    Random r1 = new Random();
    Random r2 = new Random();

    int dice1;
    int dice2;
    int [] t = new int [13];


    for (int roll=0; roll < rolls.length; roll++)
    {
         dice1 = r1.nextInt(6)+1;
         dice2 = r2.nextInt(6)+1;

         System.out.println(roll + " : I rolled a " + dice1 + " and a " + dice2);

         int sum;
         sum = dice1 + dice2;

         if (sum == 2)
             t[0]++;
         if (sum == 3)
             t[1]++;
         if (sum == 4)
             t[2]++;
         if (sum == 5)
             t[3]++;
         if (sum == 6)
             t[4]++;
         if (sum == 7)
             t[5]++;
         if (sum == 8)
             t[6]++;
         if (sum == 9)
             t[7]++;
         if (sum == 10)
             t[8]++;
         if (sum == 11)
             t[9]++;
         if (sum == 12)
             t[10]++;

    }   

System.out.println("Histogram of rolls:" ); 
    String star ="*";
    int [] h= {t[0], t[1],t[2], t[3],t[4], t[5], t[6], t[7],t[8], t[9],t[10]};
     for (int i=0; i <h.length; i++)
             {
        for(int j = 0; j < h[i]; j++) 
           System.out.print( star);
        System.out.println();
    }



    System.out.println("Histogram of rolls:" );

    System.out.println( "2 : " + t[0] + " times");
    System.out.println("3 : " + t[1] + " times");
    System.out.println("4 : " + t[2] + " times");
    System.out.println("5 : " + t[3] + " times");
    System.out.println("6 : " + t[4] + " times");
    System.out.println("7 : " + t[5] + " times");
    System.out.println("8 : " + t[6] + " times");
    System.out.println("9 : " + t[7] + " times");
    System.out.println("10 : " + t[8] + " times");
    System.out.println("11 : " + t[9] + " times");
    System.out.println("12 : " + t[10] + " times");

}
publicstaticvoidmain(字符串[]args){
//此处的TODO代码应用程序逻辑
System.out.print(“请输入掷骰子的次数:”);
扫描仪sc=新的扫描仪(System.in);
int n=sc.nextInt();
int[]滚动=新的int[n];
Random r1=新的Random();
随机r2=新随机();
int-1;
int-2;
int[]t=新的int[13];
对于(int roll=0;roll对于(int i=0;i将代码的最后一部分更改为:

    ...
    System.out.println("Histogram of rolls:" ); 
    String star ="*";

    // No point in using "int [] h"

    for (int i=0; i < t.length; i++) {

        // Placing the logic for printing the text inside the loop
        // is how you use arrays
        System.out.print( (i+2) + " : " + t[0] + " times");
        for(int j = 0; j < t[i]; j++) {
           System.out.print(star);
        }
        System.out.println();
    }
}
可简化为:

    t[sum-2]++;
建议:

1) 您根本不需要数组h[]

2) 您需要在同一个循环中同时打印直方图的每一行(“***”)和“直方图卷数”的每一行

3) 我将创建一个变量,“
String asterisks=“*************”;
并使用子字符串打印正确数量的星号。()副本,而不是“for(…)”循环

附言:

subString()是我在您的

    t[sum-2]++;