Java JAX-RS的注释继承不起作用

rest-server.xml：

<jaxrs:server id="baseApi" address="http://localhost:8080/myfashions/catalog">
    <jaxrs:serviceBeans>
        <bean class="com.myfashions.api.service.rest.implementation.CatalogServiceImpl"/>
    </jaxrs:serviceBeans>
    <jaxrs:providers>
        <ref bean="customRequestHandler"/>
        <ref bean="customResponseHandler"/>
        <ref bean="restExceptionMapper"/>
        <bean class="org.codehaus.jackson.jaxrs.JacksonJaxbJsonProvider"/>
    </jaxrs:providers>
</jaxrs:server>

类别：

@Service
@Path("/myfashions/catalog")
public class CatalogServiceImpl implements CatalogService {
    @Override
    public SelectCategoryBeanList getMyfashionCategories() {
        ...
        ...
    }
}

---

当我打电话给

http://localhost:8080/myfashions/catalog/categories

，我没有找到与请求路径匹配的根资源。已找到路径

/myfashions/catalog/categories

，相对路径：

/categories

异常。有人能帮我吗。

地址的结构如下：

http(s)://<host>:<port>/<webapp>/<servlet URL-pattern>/<jaxrs:server address>/<resources>

您需要：

webapp name = myApp
servlet url-pattern = /rest/*
jaxrs:server address = myfashions
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

webapp name = myfashions
servlet url-pattern = /*
jaxrs:server address = ""
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

通常，只有在版本控制时，或者出于任何原因需要多个rest服务器时，我才在jaxrs:server元素上设置地址。大多数情况下，我将地址设置为“”

编辑：或者，如果需要：

http://localhost:8080/myfashions/catalog/categories

您需要：

webapp name = myApp
servlet url-pattern = /rest/*
jaxrs:server address = myfashions
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

webapp name = myfashions
servlet url-pattern = /*
jaxrs:server address = ""
@Path on the class = /catalog
@Path on the interface (on the method) = /categories

---

我不确定是否允许您完全省略

@products

注释。它是可继承的。我已编辑我的问题。你能告诉我哪里错了吗？你能回答这个问题吗？我遇到了同样的问题。您是否尝试过将类级别的

@Path

从

CatalogServiceImpl

移动到

CatalogService

？另外，在cxf页面上找到了对此的解释：