Warning: file_get_contents(/data/phpspider/zhask/data//catemap/9/java/340.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Java 如何将json响应转换为数组?_Java_Json_Api_Rest - Fatal编程技术网

Java 如何将json响应转换为数组?

Java 如何将json响应转换为数组?,java,json,api,rest,Java,Json,Api,Rest,我希望json响应中的值被列出,而不是显示为逗号分隔的单行响应。下面是我的代码部分: URL url = new URL(urlStr); HttpURLConnection con = (HttpURLConnection) url.openConnection(); con.setRequestMethod("POST"); con.setRequestProperty("Content-Type", "application/json"); con.setDoOutput(true);

我希望json响应中的值被列出,而不是显示为逗号分隔的单行响应。下面是我的代码部分:

URL url = new URL(urlStr);
HttpURLConnection con = (HttpURLConnection) url.openConnection();

con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "application/json");
con.setDoOutput(true);
OutputStream os = con.getOutputStream();
os.write(DaoIntegration.getCustomSearchBody().getBytes());
os.flush();
os.close();
if (con.getResponseCode() != 200) {
    throw new RuntimeException("Failed : HTTP error code : " +
        con.getResponseCode());
} else {
    content = (InputStream) con.getInputStream();
    result = org.apache.commons.io.IOUtils.toString(content, "UTF-8");
    jsonObject = new JSONObject(result);

    String MemberResponse = jsonObject.get("MemberResponse").toString();
    String[] members = MemberResponse.split(",");
    System.out.println("MemberResponse: " + members);
}
我现在得到的是以下格式:

MemberResponse:{“AnniversaryDate”:null,“EmirateResidence”:null,“ReferralCode”:“ERXEN0B1NJ”,“Email”:abc@gmail.com,“TotalPointsSlapsed”:“0”}

我希望格式如下图所示:


你能试试这个并美化你的json和打印吗?请确保添加必要的jackson.core作为依赖项

ObjectMapper mapper = new ObjectMapper().writerWithDefaultPrettyPrinter().writeValueAsString(jsonObject);

可以使用对象映射器将jsonobject转换为hashmap。然后从hashmap转换为所需的任何形式。