Java BroadcastReceiver onReceive函数中的调用类函数
Java BroadcastReceiver onReceive函数中的调用类函数,java,android,Java,Android,我有一个带有BroadcastReceiver的服务如何从BroadcastReceiver的onReceive函数调用服务类中的函数?如果我不能,我能做什么?下面是一些代码: public class MyService extends Service { private BroadcastReceiver broadcastReceiver; @Override public IBinder onBind(Intent arg0) { return
我有一个带有
BroadcastReceiver
的服务如何从
BroadcastReceiver
的onReceive
函数调用服务类中的函数?如果我不能,我能做什么?
下面是一些代码:
public class MyService extends Service {
private BroadcastReceiver broadcastReceiver;
@Override
public IBinder onBind(Intent arg0) {
return null;
}
@Override
public void onCreate() {
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
... // How to call myFunction() here?
}
};
... // intentFilter, registerReceiver, etc...
}
private void myFunction() {
... // do something
}
}
你可以这样称呼它:
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
myFunction();
}
};
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
MyService.this.myFunction();
}
};
或者,如果myFunction
与BroadcastReceiver
方法具有相同的名称,则可以像下面这样显式调用外部类方法:
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
myFunction();
}
};
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
MyService.this.myFunction();
}
};
你可以这样称呼它:
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
myFunction();
}
};
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
MyService.this.myFunction();
}
};
或者,如果myFunction
与BroadcastReceiver
方法具有相同的名称,则可以像下面这样显式调用外部类方法:
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
myFunction();
}
};
broadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
MyService.this.myFunction();
}
};
我写错了函数名,所以IDE没有找到函数,我认为他们的函数很特别。谢谢,我写错了函数名,所以IDE没有找到这个函数,我认为他们的函数很特别。非常感谢。