Java 如何从FileItem获取完整路径

如何从FileItem获取完整路径并放入FileInputStream，似乎我只能获取名称。下面是我的代码，我试图上传文件和自动压缩到服务器。多谢各位

DiskFileItemFactory fup = new DiskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(fup);

List items = upload.parseRequest(req);
Iterator iter = items.iterator();

while (iter.hasNext()) {
                FileItem item = (FileItem) iter.next();                             
                if (!item.isFormField()) {

                File f = new File(Properties.get("dir") + File.separator + "test.zip");
                ZipOutputStream out = new ZipOutputStream(new FileOutputStream(f));
                ZipEntry e = new ZipEntry(flNm);
                out.putNextEntry(e);
                FileInputStream in = new FileInputStream((File) item);

                byte[] buffer = new byte[1024];
                int len;
                while ((len = in.read(buffer)) > 0) {
                    out.write(buffer, 0, len);
                }
                in.close();
                out.closeEntry();

                out.close();
                }
}

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您正在读取一个

文件

对象，该对象引用新创建的tempfile，该tempfile为空。并将其写入文件。你确定这就是你想做的吗？

嗨，对不起，我的错。我想问一下如何在java中将FileItem放入FileInputStream？我得到了我的代码“FileItem=（FileItem）iter.next（）；”并希望将该项放入FileInputStream in=newfileinputstream（）；