如何阅读&;在java中从bufferedreader运行多个变量?
以前,我在两个不同的类中有这两个变量(a),(total),但我无法获得该类的属性 所以 我试图将这两个代码放在一个类中 但这两个变量都不起作用如何阅读&;在java中从bufferedreader运行多个变量?,java,arrays,string,bufferedreader,Java,Arrays,String,Bufferedreader,以前,我在两个不同的类中有这两个变量(a),(total),但我无法获得该类的属性 所以 我试图将这两个代码放在一个类中 但这两个变量都不起作用 System.out.println(“(“+file1.getName()+”)-“+”总字数=“+a+”统计的总重复字数:“%+Total”) 两人都没有工作: 目前为止,我的示例输出: (Blog 39.txt)-统计的重复单词总数:4,单词总数:0 都不是 (Blog 39.txt)-统计的重复单词总数:0,单词总数:82 我需要的输出是: (
System.out.println(“(“+file1.getName()+”)-“+”总字数=“+a+”统计的总重复字数:“%+Total”)代码>
两人都没有工作:
目前为止,我的示例输出:
(Blog 39.txt)-统计的重复单词总数:4,单词总数:0
都不是
(Blog 39.txt)-统计的重复单词总数:0,单词总数:82
我需要的输出是:
(Blog 39.txt)-统计的重复单词总数:4个,单词总数:82个
当我运行时,如果我更改代码(变量)顺序,“a”或“total”都不起作用(反之亦然)
有人告诉我如何获得变量输出吗??
:)
我是java的初学者
下面是我的代码
package ramki;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
import org.apache.commons.io.FileUtils;
import org.apache.commons.io.IOUtils;
public class newrepeatedcount {
public static void main(String[] args) {
FilenameFilter filter = new FilenameFilter() {
public boolean accept(File dir, String name) {
return name.endsWith(".txt");
}
};
File folder = new File("E:\\testfolder\\");
File[] listOfFiles = folder.listFiles(filter);
for (int i = 0; i < listOfFiles.length; i++) {
File file1 = listOfFiles[i];
BufferedReader ins = null;
try {
ins = new BufferedReader(
new InputStreamReader(new FileInputStream(file1)));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String line = "", str = "";
String st = null;
try {
st = IOUtils.toString(ins);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// split text to array of words
String[] words = st.split("\\s");
// frequency array
int[] fr = new int[words.length];
// init frequency array
for (int i1 = 0; i1 < fr.length; i1++)
fr[i1] = -1;
// count words frequency
for (int i1 = 0; i1 < words.length; i1++) {
for (int j = 0; j < words.length; j++) {
if (words[i1].equals(words[j])) {
fr[i1]++;
}
}
}
// clean duplicates
for (int i1 = 0; i1 < words.length; i1++) {
for (int j = 0; j < words.length; j++) {
if (words[i1].equals(words[j])) {
if (i1 != j)
words[i1] = "";
}
}
}
int a = 0;
try {
while ((line = ins.readLine()) != null) {
str += line + " ";
}
} catch (IOException e) {
e.printStackTrace();
}
StringTokenizer st1 = new StringTokenizer(str);
while (st1.hasMoreTokens()) {
String s = st1.nextToken();
a++;
}
int total = 0;
for (int i1 = 0; i1 < words.length; i1++) {
if (words[i1] != "") {
// System.out.println(words[i1]+"="+fr[i1]);
total += fr[i1];
}
}
System.out.println("( " + file1.getName() + " )-"
+ "Total repeated words counted:" + total + ","
+ "total no of words:" + a);
// System.out.println("total no of words:"+a);
}
}
}
package-ramki;
导入java.io.BufferedReader;
导入java.io.File;
导入java.io.FileInputStream;
导入java.io.FileNotFoundException;
导入java.io.FilenameFilter;
导入java.io.IOException;
导入java.io.InputStreamReader;
导入java.util.StringTokenizer;
导入org.apache.commons.io.FileUtils;
导入org.apache.commons.io.IOUtils;
公共类newrepeatedcount{
公共静态void main(字符串[]args){
FilenameFilter筛选器=新建FilenameFilter(){
公共布尔接受(文件目录,字符串名称){
返回名称.endsWith(“.txt”);
}
};
文件夹=新文件(“E:\\testfolder\\”;
File[]listOfFiles=folder.listFiles(过滤器);
for(int i=0;i
如果您将一个流读到底,您将无法再进一步读取。
由于您的代码在许多方面没有得到优化,我可以建议一种快速而肮脏的方法来让您的代码工作。在重新计算“a”的值之前,只需初始化分配给变量“ins”的BufferedReader
如果你把一个流读到它的末尾,你就不能再读下去了。
由于您的代码在许多方面没有得到优化,我可以建议一种快速而肮脏的方法来让您的代码工作。在重新计算“a”的值之前,只需初始化分配给变量“ins”的BufferedReader
每当您进行这样的数据处理时,Java8的流API可能是最佳选择
// get all the files under this folder
Files.walk(Paths.get("E:\\testfolder\\"))
// keep all the files ending in .txt
.filter(p -> p.toString().toLowerCase().endsWith(".txt"))
.forEach(p -> {
try {
// process all the lines of the file.
Map<String, Long> wordCount = Files.lines(p)
// break the lines into words
.flatMap(l -> Stream.of(l.split("\\s")))
// collect the words and count them
.collect(Collectors.groupingBy(w -> w, Collectors.counting()));
// find how many values are more than 1
long wordDuplicates = wordCount.values().stream().filter(l -> l > 1).count();
// get the sum of all the values.
long totalWords = wordCount.values().stream().mapToLong(l -> l).sum();
System.out.println(p + " has " + wordDuplicates + " duplicates and " + totalWords + " words");
// catch the IOException at the end because you can't do anything more with the file if this happens.
} catch (IOException e) {
e.printStackTrace();
}
});
//获取此文件夹下的所有文件
Files.walk(path.get(“E:\\testfolder\\”)
//保留所有以.txt结尾的文件
.filter(p->p.toString().toLowerCase().endsWith(“.txt”))
.forEach(p->{
试一试{
//处理文件的所有行。
Map wordCount=Files.lines(p)
//把台词分成几行
.flatMap(l->Stream.of(l.split(\\s)))
//收集单词并数一数
.collect(Collectors.groupingBy(w->w,Collectors.counting());
//查找有多少个值大于1
long-wordDuplicates=wordCount.values().stream().filter(l->l>1.count();
//获取所有值的总和。
long totalWords=wordCount.values().stream().mapToLong(l->l.sum();
System.out.println(p+“有”+字副本+“副本”和“+字总数+”字);
//
// get all the files under this folder
Files.walk(Paths.get("E:\\testfolder\\"))
// keep all the files ending in .txt
.filter(p -> p.toString().toLowerCase().endsWith(".txt"))
.forEach(p -> {
try {
// process all the lines of the file.
Map<String, Long> wordCount = Files.lines(p)
// break the lines into words
.flatMap(l -> Stream.of(l.split("\\s")))
// collect the words and count them
.collect(Collectors.groupingBy(w -> w, Collectors.counting()));
// find how many values are more than 1
long wordDuplicates = wordCount.values().stream().filter(l -> l > 1).count();
// get the sum of all the values.
long totalWords = wordCount.values().stream().mapToLong(l -> l).sum();
System.out.println(p + " has " + wordDuplicates + " duplicates and " + totalWords + " words");
// catch the IOException at the end because you can't do anything more with the file if this happens.
} catch (IOException e) {
e.printStackTrace();
}
});
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
import java.util.HashMap;
import java.util.Map;
public class NewRepeatedCount {
public static void main(String... arg0)
{
BufferedReader br = null;
Map<String, Integer> counterMap = new HashMap<String, Integer>();
try {
String sCurrentLine;
br = new BufferedReader(new FileReader("C:\\testing.txt"));
while ((sCurrentLine = br.readLine()) != null) {
String[] words = sCurrentLine.split("\\s");
for(String word : words)
{
int count = 1;
if(counterMap.get(word) != null)
{
count = counterMap.get(word);
count++;
counterMap.put(word, count);
}else{
counterMap.put(word, count);
}
}
}
System.out.println(counterMap.entrySet());
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
if (br != null)br.close();
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
}