JavaFXActionEvent矩形

简言之：

我正在用AI和GUI创建一个纸牌游戏。用户的手显示在游戏界面上，我还没有完成界面，但我打算在屏幕上的矩形中添加一张牌面图像。我没有使用5种几乎相同的方法，而是找到了一篇类似的帖子，我正在尝试实现相同的想法。然而，我遇到了意想不到的事情。以下是我的控制器类中的相关代码：

/** This is where the players hand will be displayed. */
@FXML
private Rectangle card1, card2, card3, card4, card5;

public void playThisCard(final ActionEvent event) {
    if (event.getSource() == card1) {
        System.out.println("played card 1");
    } else if (event.getSource() == card2) {
        System.out.println("played card 2");
    } else if (event.getSource() == card3) {
        System.out.println("played card 3");
    } else if (event.getSource() == card4) {
        System.out.println("played card 4");
    } else if (event.getSource() == card5) {
        System.out.println("played card 5");
    } else {
        System.out.println("no card played");
    }
}

UI是在Scene Builder中构建的，因此在矩形上有FXML标记，控制器被正确绑定，并且我成功地获得了其他方法来执行用户对控件的输入

Exception in thread "JavaFX Application Thread" java.lang.IllegalArgumentException: argument type mismatch
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at sun.reflect.misc.Trampoline.invoke(MethodUtil.java:71)
at sun.reflect.GeneratedMethodAccessor1.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:497)
at sun.reflect.misc.MethodUtil.invoke(MethodUtil.java:275)
at javafx.fxml.FXMLLoader$MethodHandler.invoke(FXMLLoader.java:1769)
at javafx.fxml.FXMLLoader$ControllerMethodEventHandler.handle(FXMLLoader.java:1657)
at com.sun.javafx.event.CompositeEventHandler.dispatchBubblingEvent(CompositeEventHandler.java:86)
at com.sun.javafx.event.EventHandlerManager.dispatchBubblingEvent(EventHandlerManager.java:238)
at com.sun.javafx.event.EventHandlerManager.dispatchBubblingEvent(EventHandlerManager.java:191)
at com.sun.javafx.event.CompositeEventDispatcher.dispatchBubblingEvent(CompositeEventDispatcher.java:59)
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:58)
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114)
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:56)
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114)
at com.sun.javafx.event.BasicEventDispatcher.dispatchEvent(BasicEventDispatcher.java:56)
at com.sun.javafx.event.EventDispatchChainImpl.dispatchEvent(EventDispatchChainImpl.java:114)
at com.sun.javafx.event.EventUtil.fireEventImpl(EventUtil.java:74)
at com.sun.javafx.event.EventUtil.fireEvent(EventUtil.java:54)
at javafx.event.Event.fireEvent(Event.java:198)
at javafx.scene.Scene$ClickGenerator.postProcess(Scene.java:3470)
at javafx.scene.Scene$ClickGenerator.access$8100(Scene.java:3398)
at javafx.scene.Scene$MouseHandler.process(Scene.java:3766)
at javafx.scene.Scene$MouseHandler.access$1500(Scene.java:3485)
at javafx.scene.Scene.impl_processMouseEvent(Scene.java:1762)
at javafx.scene.Scene$ScenePeerListener.mouseEvent(Scene.java:2494)
at com.sun.javafx.tk.quantum.GlassViewEventHandler$MouseEventNotification.run(GlassViewEventHandler.java:352)
at com.sun.javafx.tk.quantum.GlassViewEventHandler$MouseEventNotification.run(GlassViewEventHandler.java:275)
at java.security.AccessController.doPrivileged(Native Method)
at com.sun.javafx.tk.quantum.GlassViewEventHandler.lambda$handleMouseEvent$355(GlassViewEventHandler.java:388)
at com.sun.javafx.tk.quantum.QuantumToolkit.runWithoutRenderLock(QuantumToolkit.java:389)
at com.sun.javafx.tk.quantum.GlassViewEventHandler.handleMouseEvent(GlassViewEventHandler.java:387)
at com.sun.glass.ui.View.handleMouseEvent(View.java:555)
at com.sun.glass.ui.View.notifyMouse(View.java:937)

---

如果要在

矩形

上处理鼠标单击，可以使用

所以我猜在您的FXML文件中有如下内容：

onMouseClicked="#playThisCard"

但是，如果您查看上述财产的签名：

public final ObjectProperty<EventHandler<? super MouseEvent>> onMouseClickedProperty

---

是处理鼠标单击事件的正确签名。

Ahh好的，这很有意义。第一次使用JavaFX和Scene Builder，在UI中的其余按钮上使用onAction=“”，但在SB中没有显示为可用选项。使用onMouseRelease=

public void playThisCard(final MouseEvent event)