Java 使用枚举将默认值设置为“不合格”
我有以下处理EligibilityType的代码:Java 使用枚举将默认值设置为“不合格”,java,enums,java-8,Java,Enums,Java 8,我有以下处理EligibilityType的代码: public enum EligibilityType { E (EligibilityTypeEnum.ELIGIBLE), I (EligibilityTypeEnum.INELIGIBLE); private final EligibilityTypeEnum eligibilityTypeEnum; private EligibilityType(EligibilityTypeEnum eligib
public enum EligibilityType {
E (EligibilityTypeEnum.ELIGIBLE),
I (EligibilityTypeEnum.INELIGIBLE);
private final EligibilityTypeEnum eligibilityTypeEnum;
private EligibilityType(EligibilityTypeEnum eligibilityTypeEnum) {
this.eligibilityTypeEnum = eligibilityTypeEnum;
}
public EligibilityTypeEnum toEligibilityTypeEnum() {
return eligibilityTypeEnum;
}
}
我了解到,所有不属于“E”值的内容都应该设置为EligibilityTypeEnum.Inqualify
我这样称呼它:
...
List<Workout> workouts = workoutResults.getWorkout();
for(int i = 0; i< workouts.size(); ++i) {
...
stin.getWorkouts().get(i).setEligibilityType(EligibilityType.valueOf(workouts.get(i).getRecommendation()).toEligibilityTypeEnum());
...
}
。。。
列出训练=workoutResults.getWorkout();
对于(int i=0;i
现在,如果workouts.get(i).getRecommension()
返回“C”,代码就会爆炸
除了“尝试捕获”之外,有没有其他方法可以实现这一点
有没有办法在enum中设置默认值?您可以在
EligibilityType
中拥有一个包含所有可能值的映射
public static final Map<String, EligibilityType> ALL_MAP = Arrays.stream(values())
.collect(Collectors.toMap(Enum::toString, Function.identity()));
EligibilityType.ALL_MAP.getOrDefault(someString, EligibilityType.DEFAULT)