向Android Studio（Java）中的API发送请求时出现问题

我在连接到API时遇到问题。我的请求似乎还可以，但我的身份验证似乎不正确。有人能帮我吗

url和API Put请求是正确的，我使用mozilla HTTP请求程序对其进行了测试。但我没有成功。我得到HTTP 403作为响应代码，所以我认为我的身份验证有问题

        public String doWork(String pMail, String pPassword, String pNickname) {
    String output = "";
    try {


            //authentification header?
            Authenticator.setDefault(new Authenticator() {
                @Override
                protected PasswordAuthentication getPasswordAuthentication() {
                    return new PasswordAuthentication(
                            "admin@domain.com", "password".toCharArray());
                }
            });

            //Test: These parameters need to be sent from the GUI
            pMail = "name@domain.com";
            pPassword = "Testpassword";
            pNickname = "Testuser";

            String password = "password";
            String username = "admin@domain.com";
            //new try for authentification
            String authstring = username + ":" + password;

            byte[] authEncBytes = Base64.encode(authstring.getBytes(), 0);

            URL url = new URL("https://domain/API");

            //create https connection
            HttpsURLConnection httpsCon = null;
            httpsCon = (HttpsURLConnection) url.openConnection();
            httpsCon.setRequestProperty("Authorization", "Basic " + authEncBytes);
            httpsCon.setRequestMethod("PUT");
            httpsCon.setRequestProperty("Content-Type", "application/json");
            httpsCon.setRequestProperty("Accept-Language", "de");

            OutputStreamWriter out = new OutputStreamWriter(
                    httpsCon.getOutputStream());

            out.write("/Users/" + pMail + "/" + pPassword + "/" + pNickname);
            out.close();

            httpsCon.getInputStream();

        } catch (Exception e) {
            output = e.toString();
        System.out.println(output);

        }
    return output;
    }

我对Android Studio和必要的java编程非常陌生。所以，如果有人能给我一个提示，那就太好了：-）

这是我的代码（它已经在一个异步任务中，我没有得到NetworkInMainThreadException）

我还得到“方法不支持请求体：PUT”，但我认为这是因为身份验证

        public String doWork(String pMail, String pPassword, String pNickname) {
    String output = "";
    try {


            //authentification header?
            Authenticator.setDefault(new Authenticator() {
                @Override
                protected PasswordAuthentication getPasswordAuthentication() {
                    return new PasswordAuthentication(
                            "admin@domain.com", "password".toCharArray());
                }
            });

            //Test: These parameters need to be sent from the GUI
            pMail = "name@domain.com";
            pPassword = "Testpassword";
            pNickname = "Testuser";

            String password = "password";
            String username = "admin@domain.com";
            //new try for authentification
            String authstring = username + ":" + password;

            byte[] authEncBytes = Base64.encode(authstring.getBytes(), 0);

            URL url = new URL("https://domain/API");

            //create https connection
            HttpsURLConnection httpsCon = null;
            httpsCon = (HttpsURLConnection) url.openConnection();
            httpsCon.setRequestProperty("Authorization", "Basic " + authEncBytes);
            httpsCon.setRequestMethod("PUT");
            httpsCon.setRequestProperty("Content-Type", "application/json");
            httpsCon.setRequestProperty("Accept-Language", "de");

            OutputStreamWriter out = new OutputStreamWriter(
                    httpsCon.getOutputStream());

            out.write("/Users/" + pMail + "/" + pPassword + "/" + pNickname);
            out.close();

            httpsCon.getInputStream();

        } catch (Exception e) {
            output = e.toString();
        System.out.println(output);

        }
    return output;
    }

---

我也有类似的问题。这段代码对我有用。这是AsyncTask类中的doInBackground方法

protected String doInBackground(Void... urls) {

    try {



        URL url = new URL ("https://url.com/systems.json");

        String userPassword = "blah" + ":" + "blah";

        byte[] encodingBytes = Base64.encodeBase64(userPassword.getBytes());
        String encoding = new String(encodingBytes);
        HttpURLConnection connection = (HttpURLConnection) url.openConnection();
        connection.setRequestProperty("Authorization", "Basic " + encoding); //basic http authetication
        connection.connect();

        BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream()));
        StringBuilder stringBuilder = new StringBuilder();
        String line;

        while ((line = in.readLine()) != null) {
            stringBuilder.append(line).append("\n");
        }
        in.close();
        return stringBuilder.toString();
    }
    catch (Exception e) {
        e.printStackTrace();
        return null;
    }
}

在onPostExecute中，im将字符串作为参数，这是这段代码获得的提要。希望这有帮助

---

编辑：实际上，您的问题似乎是试图在UI线程中运行doWork方法。将代码从doWork方法移动到AsyncTask doInBackground方法，将不再引发异常。

顺便说一句，使用一些库来执行API请求，而不是自己编写。我使用改型，但可能还有其他一些好的库。

谢谢，我用截击来完成我的任务，现在我的Put、Post和Delete工作。我只剩下一个问题：如何将输出作为JSon对象

我的第一个想法是将此方法从void更改为任何数据类型（如String、Map或其他任何类型），并在末尾添加“return”。 我的第二个想法是直接在方法中处理JSon

谁能给我一个提示吗

public void getUserGroups（字符串pUserID） { 字符串getCommand=“”； getCommand=API_URL+“组/组/”+pUserID

    StringRequest stringRequest = new StringRequest(Request.Method.GET, getCommand, new Response.Listener<String>()
    {

        @Override
        public void onResponse(String response) {
            // Do i get my output here? ################################
            // #########################################################

            //here we have to check the response code
            if(response.equalsIgnoreCase(""))
            {
                //success
            }
            else
            {
                //error-code
            }
        }
    },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    //You can handle error here if you want
                }
            }){
        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String,String> headers = new HashMap<>();

            String credentials = KEY_EMAIL + ":" + KEY_PASSWORD;
            String encodedCredentials = Base64.encodeToString(credentials.getBytes(), Base64.NO_WRAP);
            headers.put("Authorization", "Basic " + encodedCredentials);
            //returning parameter
            return headers;
        }
    };


    //Adding the string request to the queue
    RequestQueue requestQueue = Volley.newRequestQueue(this);
    requestQueue.add(stringRequest);
}

StringRequest-StringRequest=new-StringRequest（Request.Method.GET，getCommand，new-Response.Listener（））
{
@凌驾
公共void onResponse（字符串响应）{
//我在这里得到我的输出吗################################
// #########################################################
//这里我们必须检查响应代码
if（response.equalsIgnoreCase（“”）
{
//成功
}
其他的
{
//错误代码
}
}
},
新的Response.ErrorListener（）{
@凌驾
公共无效onErrorResponse（截击错误）{
//如果需要，可以在此处处理错误
}
}){
@凌驾
公共映射getHeaders（）引发AuthFailureError{
Map headers=newhashmap（）；
字符串凭据=密钥\电子邮件+“：”+密钥\密码；
字符串encodedCredentials=Base64.encodeToString（credentials.getBytes（），Base64.NO_WRAP）；
标题。put（“授权”、“基本”+encodedCredentials）；
//返回参数
返回标题；
}
};
//将字符串请求添加到队列
RequestQueue RequestQueue=Volley.newRequestQueue（this）；
添加（stringRequest）；
}