Java 从字节缓冲区生成xml消息
我有一个传递字节数组的函数。这些字节可以包含xml消息的一部分、一个整体或一个整体和一部分。我已经成功地使用状态机尝试解析消息,直到今天,我们才意识到,如果第二个源向我们发送数据,我可以获取消息的前半部分,并在第二个源的另一条消息开始之后立即获取。我希望能够通过丢弃不正常的消息来纠正这一点。我不认为我应该把它保存起来,直到完成为止 这是我的状态机:Java 从字节缓冲区生成xml消息,java,xml,state-machine,Java,Xml,State Machine,我有一个传递字节数组的函数。这些字节可以包含xml消息的一部分、一个整体或一个整体和一部分。我已经成功地使用状态机尝试解析消息,直到今天,我们才意识到,如果第二个源向我们发送数据,我可以获取消息的前半部分,并在第二个源的另一条消息开始之后立即获取。我希望能够通过丢弃不正常的消息来纠正这一点。我不认为我应该把它保存起来,直到完成为止 这是我的状态机: for (int i = 0; i < bytes.length; i++) { byte data = bytes[
for (int i = 0; i < bytes.length; i++)
{
byte data = bytes[i];
//based on the read state, perform an action. This is attempting to
//determine if we are reading the beginning of a message, or the end of the message.
if (bufferIndex == BmsConstants.MAX_DRAWING_LENGTH)
{
resetState();
}
switch (readState)
{
case SYNC:
//we've read: <
if (data == '<')
{
readState = DrawingDeviceParserState.START_LT;
buff[bufferIndex++] = (char) data;
} else
{
resetState();
}
break;
case START_LT:
//we've read: <?
if (data == '?')
{
readState = DrawingDeviceParserState.START_QM;
buff[bufferIndex++] = (char) data;
} else
{
resetState();
}
break;
case START_QM:
//we've read: <?x
if (data == 'x')
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
} else
{
resetState();
}
break;
case START_X:
//we've read: <, now just read until we get to the </event>
if (data == '<')
{
readState = DrawingDeviceParserState.END_LT;
buff[bufferIndex++] = (char) data;
}
else
{
buff[bufferIndex++] = (char) data;
}
break;
case END_LT:
//we've read: </
if (data == '/')
{
readState = DrawingDeviceParserState.END_SLASH;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_SLASH:
//we've read: </e
if (data == 'e')
{
readState = DrawingDeviceParserState.END_E;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_E:
//we've read: </ev
if (data == 'v')
{
readState = DrawingDeviceParserState.END_V;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_V:
//we've read: </eve
if (data == 'e')
{
readState = DrawingDeviceParserState.END_E1;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_E1:
//we've read: </even
if (data == 'n')
{
readState = DrawingDeviceParserState.END_N;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_N:
//we've read: </event
if (data == 't')
{
readState = DrawingDeviceParserState.END_T;
buff[bufferIndex++] = (char) data;
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
case END_T:
//we've read: </event>
//End of the message, now we can parse it.
if (data == '>')
{
//readState = DrawingDeviceParserState.END_GT;
buff[bufferIndex++] = (char) data;
parseXml(new String(buff, 0, bufferIndex));
resetState();
}
else
{
readState = DrawingDeviceParserState.START_X;
buff[bufferIndex++] = (char) data;
}
break;
}
}
for(int i=0;i 如果(data=='不确定具体问题是什么。我对我的问题进行了澄清。我认为您正在处理一种非常特定的xml格式?您似乎假设xml采用单字节编码。我不知道您希望如何处理任意混乱的消息?在我看来,您的问题是在您开始解析之前。我可以避免d进入断开消息的状态(如果可能的话)。这并不是因为它太具体,只是我不知道消息中有什么。我知道它是xml,但我不知道它是一条完整的消息还是多条消息,等等。这就是为什么我使用状态机来确保我得到了适当的标记。我不觉得这是最好的方法,这就是为什么我要发布这个问题的原因。