Java中的UDP聊天

我正在尝试使用UDP创建一个客户端和服务器聊天程序。我遵循了一个使用TCP制作类似程序的教程，然后尝试将我的知识转换为使用UDP以类似的方式制作一个程序

我已经完成了一个客户端和服务器端，两者都没有显示错误，将运行，但一旦运行，将不会向另一方发送消息或接收消息。。。有人能帮我看看我做错了什么吗

用于发送消息的服务器端：

try{
        //creates the packet to be sent
        byte[] buf = new byte[256];
        String msgout = serverText.getText().trim();
        buf = msgout.getBytes();

        //uses the socet.receive method to get the packet to retrieve information to send
        DatagramPacket packet = new DatagramPacket(buf, buf.length);
        ss.receive(packet);
        InetAddress address = packet.getAddress();
        int port = packet.getPort();

        //uses packet information to create and send packet
        DatagramPacket packetSend = new DatagramPacket(buf, buf.length, address, port);
        ss.send(packetSend);

        //Displays the message in the chat area and clears the text area
        serverArea.setText(serverArea.getText().trim()+"\n Server: "+msgout);
        serverText.setText("");

    }catch (Exception e){

    }

然后是设置插座和接收/打印的主屏幕：

String msgin = "";
    try{

        ss = new DatagramSocket(1420); // Sets socket at 1420
        byte[] buf = new byte[256];
        DatagramPacket packet = new DatagramPacket(buf, buf.length);
        ss.receive(packet); //Receives the packet from the socket


        //Converts the byte array into a string
        String clientMsg = new String(packet.getData(), 0, packet.getLength());

        while(!msgin.equals("exit")){
            //Displays the message
            msgin = clientMsg;
            serverArea.setText(serverArea.getText().trim()+"\n Client: "+msgin); //displays client message

        }

    }catch(Exception e){

    }

这是客户端代码，我将其发送和接收区域合并为一个块：

try{
        //Creates the message out using the known socket that the Server creates and the known local address
        String msgout = clientText.getText().trim();
        sendBuf = msgout.getBytes();
        InetAddress address = InetAddress.getLocalHost();
        DatagramPacket sp = new DatagramPacket(sendBuf, sendBuf.length, address, 1420);
        s.send(sp);

        //Displays the text and clears the text field
        clientchat.setText(clientchat.getText().trim()+"\n Server: "+msgout);
        clientText.setText("");


    }catch (Exception e){

    }
String msgin = "";

    try{
        //Creates a socket
        DatagramSocket s = new DatagramSocket();

        //Receives the message from the server
        byte[] buf = new byte[256];
        DatagramPacket rp = new DatagramPacket(buf, buf.length);
        s.receive(rp);

        //Converts byte array to message
        String clientMsg = new String(rp.getData(), 0, rp.getLength());

        while(!msgin.equals("exit")){
            //Displays the message
            msgin = clientMsg;
            clientchat.setText(clientchat.getText().trim()+"\n Server: "+msgin); //displays client message

        }


    }catch (Exception e){

    }

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任何帮助和提示都将不胜感激

如果没有发生任何事情，并且您无法发送/接收消息，则可能会生成异常

然而，由于您有一个try-catch块，它捕获所有异常，然后什么也不做，所以您将不知道抛出了什么异常，如果抛出了任何异常的话

与其简单地忽略异常，您至少应该打印它们的原因

在catch语句中，添加以下内容，您将能够更轻松地进行调试

e.printStackTrace();

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如果您有空的catch块，当然不会看到错误。不幸的是，这对我的程序没有任何作用，它仍然没有任何作用。我想我只能放弃它，试着从新开始。